with open(‘path/to/input’) as infile: for line in infile: if line.startswith(“@”): line = line.strip() print(line) print(line.rsplit(“#”, 1)[1]) elif any(line.startswith(e) for e in “#+”): print(line.strip()) solved split a line and print in second line [closed]
Is this what you mean? print(len([x for x in train[‘Survived’] if x == 1])) For more info, check out list comprehension 1 solved python how to create a new array, list or even a new column with objects from an array, list or column with a set criteria
I’ll leave finding out how to generate a magic square as an exercise. If you’re still having trouble with it, you can find other questions on StackOverflow about how to generate a magic square of a given size in Python. Once you have your 3×3 magic square magic(3) (as a numpy ndarray), you can obtain … Read more
Introduction A magic square is a square grid of numbers where the sum of each row, column, and diagonal is the same. In this tutorial, we will be discussing how to find all possible 3×3 magic squares using Python. We will be using a combination of loops and if-else statements to generate all possible magic … Read more
Like matszwecja said your input is a string and not callable. Also you are trying to execute a string with class.name in your class a which is not possible. If you really want to use classes it would look like this. class a: def name(self): print(“option a”) class b: def name(self): print(“option a”) class c: … Read more
As stated in the comments, nodeList is not actually a list, but a dict_keys object. Before trying to index it, you may simply convert it to a list: nodeList = list(nodeList) node = nodeList[0] 2 solved Trying to exctract a char from a list [closed]
In this simple case, you can create a dictionary with the keys being the roles themselves: > roles = {d[‘role’]:d for d in dic} > roles[‘NOC’][’email’] Note that you are still looping through all dictionary items to create the new one. 0 solved Python dictionary printing specific value [closed]
A += 1 means A = A + 1. So A += A = a would be A = A + A = a (which obviously doesnt work). The error you seem to experience is not caused by this operator. Perhaps you mixed spaces with tabs, or you simply did not indent a certain line … Read more
67% = 67/100 = 0.67 So new_price = old_price * Discount_in_percent/100 solved How Can I calculate value by percentage in python? [closed]
You never update the value of GuessedNumber inside the loop. Therefore, if the code enters the loop, it will never leave it because RandomNumber != GuessedNumber will always be true. You need to do something like this: import random RandomNumber=(random.randint(0,100)) GuessedNumber=int(input(“Guess any whole number between 0 and 100! “)) while RandomNumber != GuessedNumber: print(“Unlucky guess … Read more
The solution (in collaboration with OP) is: import PIL from binascii import unhexlify import zlib from cStringIO import StringIO sdata = “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” fh = StringIO(zlib.decompress(unhexlify(sdata))) image = PIL.Image.open(fh) PIL is the Python Imaging Library, and using StringIO, I pretend to have a file-like object. 1 solved get image from hexa string
t = list(t) list(t) returns a new list while keeping t as a tuple. Think about a case you want to have both tuple and list. t2 = list(t) t is still a tuple while t2 is now a list. solved Permanently converting tuples to lists in Python [closed]
Here’s one of many ways to get it: >>> x = r”'”self.unsupported_cmds = [r’\s*clns\s+routing’,””’ >>> print x “self.unsupported_cmds = [r’\s*clns\s+routing’,” >>> import re >>> pattern = re.escape(x) >>> re.match(pattern, x) <_sre.SRE_Match object at 0x7ffca3f66098> >>> print pattern \”self\.unsupported\_cmds\ \=\ \[r\’\\s\*clns\\s\+routing\’\,\” solved Regular expression to match the string [closed]
This is very crude and it is unclear what you want: s1 = “t his will fail” s2 = “t h i s s e p a d” def is_spaced(s): prev = s[0] result = “is spaced” for c in s[1:]: if not c.isspace() and not prev.isspace(): result = “not spaced” break prev = c … Read more
I’ll keep it very simple, because this is very basic stuff. i = 10 Variable i is initialised as 10. while i > 0: print i*’*’ + 2*(10-i)*’ ‘ + i*’*’ i -= 1 While variable i is bigger than 0, it prints the string * i times, an empty space 2 * (10 – … Read more