Try this: (df.join(pd.DataFrame( df[‘number’] .map(lambda x: range(1,x+1)).tolist()) .rename(lambda x: ‘C{}’.format(x+1),axis=1))) Output: number C1 C2 C3 C4 C5 C6 0 1 1 NaN NaN NaN NaN NaN 1 2 1 2.0 NaN NaN NaN NaN 2 3 1 2.0 3.0 NaN NaN NaN 3 4 1 2.0 3.0 4.0 NaN NaN 4 6 1 2.0 3.0 … Read more
Try using “$ django-admin startproject myproject”, the myproject should be the folder that contains your project. If that doesn’t work try checking this website: https://www.tutorialspoint.com/django/django_creating_project.htm And follow the steps. 1 solved How to create django project [closed]
First, length is not defined anywhere, but you are trying to use it in the while condition. That would cause the error you are probably seeing. The length of your list can be obtained with len(list). Second, your while body isn’t actually using the list values: (list[counter] +total) isn’t doing anything, as it’s not assigned … Read more
You can use regular expressions from re module: import re s = “(‘-1259656819525938837′, 598679497)\t0.036787946” re.findall(r'[-+]?[0-9]*\.?[0-9]+’, s) % gives: [‘-1259656819525938837’, ‘598679497’, ‘0.036787946’] solved how to parse this string in Python? [duplicate]
You can use subprocess module. import subprocess subprocess.call([“tclsh”, “oommf.tcl”, “avf2odt”, “-average”, “space”, “-axis”, “z”, “-onefile”, “<filename>.txt”, “-headers”, “none”, “-ipat”, “*.omf”]) See https://docs.python.org/2/library/subprocess.html#subprocess.call 3 solved Use python to run a command line [duplicate]
you can try in this way a=input(‘input:’) while a.strip()!=”: b=a.split() ans=”” while len(b) >0 : word=b[0][::-1] ans+=word+” ” b.pop(0) print ans a=input(‘input:’) #output i ma hsejar !aloH 0 solved How can i use a while loop on this program?
After a couple of tryouts I just achieved to solve it: tuple_1 = (‘asdf@’, ‘asdf’) tuple_2 = () for elem in [item for item in tuple_1 if ‘@’ in item]: tuple_2 = tuple_2 + (elem,) print tuple_2 I hope this is what you need! I’m voting you up, since it was a little bit of … Read more
Python’s with statement comes handy here. And its good habit to use it when you’re working with files, as it takes care of tearing down the objects, and catching exceptions too. You can read about it in the documentation. And here is how you would use with in your program: from sys import argv from … Read more
use itertools.product to get the tuples (you will have to filter out the same number twice), then use set intersections of the digits to see if they have any digits in common. import itertools numbers = [12, 23, 26, 54] [t for t in itertools.product(numbers, numbers) if set(str(t[0])) & set(str(t[1])) and t[0] != t[1]] [(12, … Read more
If you get stuck here’s a solution import math baseInt = 2020 #This is the int you want to find within the other int randomInt = 1012020 #This is the int you’re going to count up to def checkBaseInt(baseInt, theIteratorInt): theNumString = str(theIteratorInt) #Converting to strings to find the substring baseIntString = str(baseInt) if(theNumString.find(baseIntString) == … Read more
Here is how you would do it in Python 2: n = int(raw_input(“Type n:”)) total = 0 for i in range(1,n+1): total += i**2 print total Here is how you would do it in Python 3: n = int(input(“Type n:”)) total = 0 for i in range(1,n+1): total += i**2 print(total) This takes the numbers … Read more
Simplest would be to have it backwards. Generate factorials until you find it or not. That way, you are sure always to compare integers: def is_factorial(n): i = f = 1 while f < n: i += 1 f *= i return f == n solved How to check if a given number is a … Read more
To match the symptoms reported I believe that your code is actually: import random name=input(“Welcome to this Arithmetic quiz,please enter your name:”) score = 0 for i in range(10): number1=random.randint(20,50) number2=random.randint(1,20) oper=random.choice(‘+-*’) correct_answer = eval(str(number1)+oper+str(number2)) answer = (int(input(‘What is:’+str(number1)+oper+str(number2)+’=’)) == correct_answer) if answer == correct_answer: print(‘Correct!’) score +=1 else: print(‘Incorrect!’) print(“You got”,score,”out of 10″) Note … Read more
There are a couple of issues with your code. Your while loop never executes because z is 1 and sk is 10, so they are not equal. sk % x. x is a range object, you don’t want to use the modulus on that. if x is x % 2 != 0 this bit is … Read more
We can just pick the coin which shop has the largest. So the key point is the order of pick. I think you can use dfs to search all pick orders, and find the best one: def pick_coins(demand, shops): # invalid input if sum(demand) > len(shops): return -1 res = 0 def dfs(demand, idx_remains, num): … Read more