[ad_1] a and b are the solutions of: X^2 – nX + x = 0 d = n*n – 4*x a = (- b – d**0.5)/2 b = (- b + d**0.5)/2 1 [ad_2] solved Solve a simultaneous equation with product of the 2 variables in Python?
[ad_1] There’s nothing wrong with having a while loop inside a for loop. To demonstrate: i = 0 kebab = [“chicken”,”garlic”,”cheese”,”tomato”,”lettuce”,”chilli”] print “Kebabs are so good, this is what mine has:” excitement_over_kebab = 1 for ingredients in kebab: while excitement_over_kebab == 1: print kebab[i] i+=1 if i == 6: print “Enough talk, my lunch break … Read more
[ad_1] Short explanation (and no other letter) 0 is less than or equal to 0 so A will be printed. Longer explanation (in case the short one was unclear to you) There are three conditions being checked: A. num <= 0 B. num >= 10 C. num % 2 == 0 (i.e. num is an … Read more
[ad_1] Im new to coding and was trying to loop through a list and kept coming up with the error code list index out of range. Why does this not work? [ad_2] solved Im new to coding and was trying to loop through a list and kept coming up with the error code list index … Read more
[ad_1] A simple way to do this is to use a dictionary. Something like this: list1 = [[‘John’,2],[‘Smith’,5],[‘Kapil’,3]] list2 = [[‘Smith’,2],[‘John’,2],[‘Stephen’,3]] dict = {} for item in list1: try: dict[item[0]] += item[1] except: dict[item[0]] = item[1] for item in list2: try: dict[item[0]] += item[1] except: dict[item[0]] = item[1] print dict This gives the output: {‘John’: … Read more
[ad_1] import re from datetime import datetime, timedelta dateString = “hello hello 2017-08-13, 2017-09-22” dates = re.findall(‘(\d+[-/]\d+[-/]\d+)’, dateString) for d in dates: originalDate = d newDate = datetime.strptime(d, “%Y-%m-%d”) newDate = newDate + timeDelta(days=5) newDate = datetime.strftime(newDate, “%Y-%m-%d”) dateString = dateString.replace(originalDate, newDate) Input: hello hello 2017-08-13, 2017-09-22 Output: hello hello 2017-08-18, 2017-09-27 6 [ad_2] solved … Read more
[ad_1] A recursive function that creates a new nested dictionary, replacing a key value with a different value def replace_key(elem, old_key, new_key): if isinstance(elem, dict): # nested dictionary new_dic = {} for k, v in elem.items(): if isinstance(v,dict) or isinstance(v, list): new_dic[replace_key(k, old_key, new_key)] = replace_key(v, old_key, new_key) else: new_dic[replace_key(k, old_key, new_key)] = v return … Read more
[ad_1] just with minor adjustments eg. class names and attributes etc. You need to be super careful with naming. Python doesn’t know what your variables mean or how to infer one name from the other. It may be obvious to you that Attack has the same meaning as DAP – but that’s just obvious to … Read more
[ad_1] It doesn’t ‘mean’ anything, not to Python; it is just another character in a string literal: “Enter the value for the co-efficient of x^2. ” You could have written something else: “Enter the value for the co-efficient of x to the power 2. ” and nothing but the output shown when asking for input() … Read more
[ad_1] The following code should provide a framework on which to build and extend the program in your question. Most of the code should be fine as it currently written, but you can expand its functionality if needed. To continue building on what questions can be asked and what answers are given, consider adding more … Read more
[ad_1] You want echo -e … so that echo understands that \n is an escape sequence for newline 0 [ad_2] solved ‘\n’ is treated as ‘\’ and ‘n’ [duplicate]
[ad_1] the issue is that the bar_label is a new feature and available in matplotlib version 3.4 or later – ref this link. Check the version of matplotlib using import matplotlib print(‘matplotlib: {}’.format(matplotlib.__version__)) Upgrade to v3.4 or latest version using pip install matplotlib –upgrade. You will need to include the code in the link you … Read more
[ad_1] the default behaviour of split() is to split by whitespace. You code would not throw errors if the input only contained numbers and whitespaces, e.g. 156 178 165 171 187. If you want a different split seperator, e.g. the comma ,, you could use split(“,”) instead. Valid input would be e.g. 156,178,165,171,187. Note that … Read more
[ad_1] You can use next with a generator comprehension. res = next(i[‘name’] for i in json_dict[‘ancestors’] if i[‘subcategory’][0][‘key’] == ‘province’) # ‘Lam Dong Province’ To construct the condition i[‘subcategory’][0][‘key’], you need only note: Lists are denoted by [] and the only element of a list may be retrieved via [0]. Dictionaries are denoted by {} … Read more
[ad_1] While you can achieve this with a bash script, probably the easier way is to use the xargs utility. xargs -L 1 ./myscript.py <inputfile The bash way would be: while read line do ./myscript $line done <inputfile [ad_2] solved text file each line to command in bash [closed]