First make from your string a list. list_name = string_name.split(‘ ‘) Then switch the keys and the values from your dict (if using python 3.x use iter instead of iteritems) my_dict = {y:x for x,y in my_dict.iteritems()} Then you can iter tro your code for numbers in list_name: print(my_dict[int(numbers)]) 6 solved Python – Swap a … Read more
I fond the answer. the path in os.listdir(“C:\ZZZ”) is relocated to main folder & got output. Thanks to everyone solved py file not executed when run through batch file
def conexclast(strlst): ”’ function to concatenate all elements (except the last element) of a given list into a string and return the string ”’ output = “” for elem in strlst: strng = str(elem) output = output+strng return ‘ ‘.join(strlst[0:-1]) print(“Enter data: “) strlst = raw_input().split() print(conexclast(strlst)) The main correction is splitting the user’s input … Read more
I would suggest a simplified “architecture”. Your functions to get the user and computer choices should return values that can be compared. import random CHOICES = (‘rock’, ‘paper’, ‘scissors’) def get_user_choice(): choice = input(‘Rock, paper, or scissors? ‘) choice = choice.lower().strip() if choice not in CHOICES: print(‘Please select one of rock, paper, or scissors’) choice … Read more
from functools import reduce import ast,sys input_int = int(sys.stdin.read()) num_list = [x for x in range(1, input_int+1)] print(reduce(lambda x, y : x + y ** 3, num_list) / reduce(lambda x, y : x + y ** ,num_list)) 1 solved Compute the ratio of the sum of cube of the first ‘n’ natural numbers to the … Read more
If you want to check whether the input is zero before doing anything else, do so. If you want to stop the loop in certain conditions, put the break inside a conditional. Note that count and total were unused. Also, format() with no formatting is redundant. def main(): while True: entry = int(input(‘Enter a number … Read more
You are missing a closing parenthesis: if imagesNamesList==[“None” for x in range(len(listOfImages))]: # here–^ However, you could write this code better (cleaner and more efficiently) like so: if imagesNamesList == [“None”]*len(listOfImages): Or, if your lists are huge, you can do as @mgilson noted: if all(x == “None” for x in imagesNamesList) and len(imagesNamesList) == len(listOfImages): … Read more
The first time a module is imported, an entry for it is made in sys.modules. sys.modules is a dict, mapping the module name to the module code. All subsequent imports of the same module find the module’s name in sys.modules, and simply retrieve the module’s code from the sys.modules dict. So the code in the … Read more
Print is a function in python 3 so change print buildConnectionString(myParams) To: print(buildConnectionString(myParams)) solved Syntax error on print-statement in Python 3 [duplicate]
If you want [{‘name’: ‘None’, ‘age’:20, ‘dead’:’NO’}] then try: data_dict = {‘name’: ‘None’, ‘age’:20, ‘dead’:’NO’} data_list =[data_dict] 7 solved How to insert a dictionary inside list [closed]
Here is an example of reading and writing a text file below. I believe that you are looking for the “open” method. with open(‘New_Sample.txt’, ‘w’) as f_object: f_object.write(‘Python sample!\n’) f_object.write(‘Another line!\n’) You simple open the file that you want and enter that file name as the first argument, and then you use ‘w’ as the … Read more
It appears to me that within your list comprehension you just have one minor issue! Instead of: item for item in textString within your list comprehension, I would suggest: item for item in listText as currently you are iterating through each char of the whole text, rather than each element in the list of the … Read more
Try this: import re lst = [‘a’, ‘4’, ‘add’, ‘e’, ‘a’, ‘c0a8d202’, ‘128’, ‘4’, ‘0’, ’32’] pattern = re.compile(r’c[0-9a-fA-F]?’) for i in lst: if re.search(pattern, i): print(lst.index(i)) Note: this is as per your desired output but i am agree with @Jean-François Fabre who said that what’s wrong with lst.index(‘c0a8d202’) ? what’s the point of regular … Read more
Use string formatting: In [48]: def solve(a,b): a,b=str(a),str(b) spaces=len(a.split())-1 return “{0} {1} {2}”.format(a,”.”*(68-len(a)-len(b)-spaces),b) ….: In [49]: print solve(a,b);print solve(p,q) Hello …………………………………………………. False Python rocks …………………………………………… True 5 solved Python text formatting
Please never use reserved words like list, type, id… as variables because masking built-in functions. If later in code use list e.g. list = data[‘FirstNames’].tolist() #another solution for converting to list list1 = list(data[‘SecondNames’]) get very weird errors and debug is very complicated. So need: L = data[‘FirstNames’].tolist() Or: L = list(data[‘FirstNames’]) Also can check … Read more