[Solved] php add counter with thousands separator [closed]

Preety straight forward answer for you… <?php $fp = fopen(“counters/counterlog.txt”, “r”); $count = fread($fp, 1024); fclose($fp); $count = $count + 1; echo “<p>Pageview: ” . number_format($count) . “</p>”; // <=== $fp = fopen(“counters/counterlog.txt”, “w”); fwrite($fp, $count); fclose($fp); ?> 1 solved php add counter with thousands separator [closed]

[Solved] find number of 1 and 0 combinations in two columns

Assuming you have a pandas dataframe, one option is to use pandas.crosstab to return another dataframe: import pandas as pd df = pd.read_csv(‘file.csv’) res = pd.crosstab(df[‘X’], df[‘Y’]) print(res) Y 0 1 X 0 3 7 1 1 3 A collections.Counter solution is also possible if a dictionary result is required: res = Counter(zip(df[‘X’].values, df[‘Y’].values)) 4 … Read more

[Solved] Countdown in days

Not a lot of code needed, just a small helper function to calculate days difference and then a replace content with whatever you want. Full sample: <html> <div id=”counter” /> <script type=”text/javascript”> function daysDifference($startDate, $endDate) { oneDay = 24*60*60*1000; return Math.ceil(($endDate.getTime() – $startDate.getTime()) / oneDay); } // 2015/01/01 $startDate = new Date(2015, 0, 1); // … Read more

[Solved] Perl set counter to match in loop

If you only want to increment unless some condition is met, you should mention that in your code. Using the postfix foo() unless condition(); syntax means the condition will only refer to the previous statement, not the entire scope ( which would arguably be insane to parse ). So print ‘…’ unless $foo is the … Read more

[Solved] Java cannot find symbol during compiling

This has to do with the scope of your variable: From Java Language Specification, Section 6.3: The scope of a declaration is the region of the program within which the entity declared by the declaration can be referred to using a simple name, provided it is visible. A declaration is said to be in scope … Read more

[Solved] Counting changes in an array

Below one is solution I believe. Sure there is more room to refactor it, you can start from here. a = [“red”, “orange”, “green”, “red”, “yellow”, “blue”, “green”] a.reject {|e| ![‘red’, ‘green’].include? e } .each_cons(2) .select{|e| e == [‘red’, ‘green’]} .size A more artistic version. def neither_red_nor_green e ![‘red’, ‘green’].include? e end def red_followed_by_green ary … Read more

[Solved] Python making a counter

I would suggest a simplified “architecture”. Your functions to get the user and computer choices should return values that can be compared. import random CHOICES = (‘rock’, ‘paper’, ‘scissors’) def get_user_choice(): choice = input(‘Rock, paper, or scissors? ‘) choice = choice.lower().strip() if choice not in CHOICES: print(‘Please select one of rock, paper, or scissors’) choice … Read more

[Solved] need this item in table and border like this form

this is the way to wrap your already exist php code in table, try it: $e = array(“item1”, “item2”, “item3”, “item4”, “item5”, “item6”, “item7”, “item8”, “item9”, “item10”, “item11”, “item12”); $i = 0; echo “<table border=1><tr>”; //tr to start the 1st row foreach ($e as $value) { $i++; if ($i % 3 != 1) echo “<td>&nbsp;</td>”; … Read more