[ad_1] You can just run your python apps on a Raspberry Pi. There are many tutorials on the web. Video: https://www.youtube.com/watch?v=VFs1dhJPYa4 Tutorials: https://makezine.com/projects/program-raspberry-pi-with-python/ http://www.makeuseof.com/tag/10-raspberry-pi-projects-beginners/ http://www.techradar.com/news/software/learn-to-program-your-raspberry-pi-1148194/2 2 [ad_2] solved Can a python file run on a Raspberry Pi? [closed]
[ad_1] your_data # this is your data final_data = {} for line in yourdata: uid = line[“userId”] pids = line[“PageId”] if uid not in final_data : final_data[uid] = {} for pid in pids : pid = int(pid) if pid not in final_data[uid]: final_data[uid][pid]=0 final_data[uid][pid] += 1 res = [{“userId”:uid,”PageIDCount”:pids} for uid,pids in final_data.items()] I suppose … Read more
[ad_1] You cannot stop each draw statement unless you provide a checker in between each line drawn. The below code is just a rough mock up of how you could make something to check for a tracking variable used to tell it to no longer draw new lines. The closest thing you can do to … Read more
[ad_1] This is a simple way, but I get 4: >>> sum(a in b for a in ListA for b in ListB) 4 Unless you want to be case-insensitive >>> sum(a.lower() in b.lower() for a in ListA for b in ListB) 5 As stated, though, your question is ambiguous: this method counts how many matches … Read more
[ad_1] I would reccomend using with (docs) whenever you do file I/O in python. Also, iterate over each line instead of using inFile.read(). If you have a large file, your machines memory will thank you. def stats(inF): num_lines = 0 num_words = 0 num_chars = 0 with open(inF, ‘r’) as input_file: for line in input_file: … Read more
[ad_1] You generate the CC number once and display it multiple times. Instead, put the CC generator in the loop. from random import choices from string import digits for _ in range(5): cc_digits = choices(digits, k=16) cc_number = “”.join(cc_digits) space = ” “.join(cc_number[i:i+4] for i in range(0, len(cc_number), 4)) print(space) 1 [ad_2] solved How do … Read more
[ad_1] Assuming that you want to name your keys as key1, key2.. and so on when a key is not found: l = [[‘a’,1], [‘b’,2], [3], [‘d’,4]] d = {} i = 1 for x in l: try: d[x[0]] = x[1] except IndexError: d[‘key’+str(i)] = x[0] i += 1 print(d) Output: {‘a’: 1, ‘b’: 2, … Read more
[ad_1] t=”POST / HTTP/1.0\r\nAuthentication: Bot {token}\r\nHost: discord.com/api/guilds/{702627382091186318}/channels\r\n\r\n” This is not a valid HTTP request. You essentially send (line breaks added for clarity): POST / HTTP/1.0\r\n Authentication: Bot {token}\r\n Host: discord.com/api/guilds/{702627382091186318}/channels\r\n \r\n But a correct POST request would look like this instead: POST /api/guilds/{702627382091186318}/channels HTTP/1.0\r\n Authentication: Bot {token}\r\n Host: discord.com\r\n Content-length: … \r\n <body, where size … Read more
[ad_1] I would suggest using a Dictionary for this task: d = {} for x in range(1,10): d[“slider{0}”.format(x)]= models.IntegerField(widget=widgets.Slider, default=50, label=””) 2 [ad_2] solved How to declare multiple similar variables in python? [duplicate]
[ad_1] I believe it should just be a couple of small typos. First, your second line looks like it should be indented, and where you have links[“property”], it looks like you would want link[“property”]. for link in links: payload[f’Links[{link[“property”]}][url]’] = link[‘url’] The reason it is giving you that error is that you are trying to … Read more
[ad_1] You can find white dot by numpy.where. You can try this way: import numpy as np import cv2 img = cv2.imread(‘XXWck.png’) x, y, z = np.where(img==(255,255,255)) points = zip(x,y) print(points) 1 [ad_2] solved Get X and Y coordinates of white dot in a black screen python [closed]
[ad_1] Keeping it simple, you could do something like this: reading = 0 notReading = 0 for book in bookLogger: if book[‘Process’] == ‘Reading’: reading += 1 elif book[‘Process’] == ‘Not Reading’: notReading += 1 print(f’Reading: {reading}’) print(f’Not Reading: {notReading}’) Alternatively, you could also use python’s list comprehension: reading = sum(1 for book in bookLogger … Read more
[ad_1] contacts = [{“name”:”John”,”age”:30},{“name”:”Peter”,”age”:20},{“name”:”Sarah”,”age”:33}] for i in range(len(contacts)): print(contacts[i][“name”]) for person in contacts: print(person[“name”]) The second way would be considered more “Pythonic”. EDIT – added to answer question in comment To access only the last record in the list, use a negative offset. print(contacts[-1][“name”]) 1 [ad_2] solved Looping through array of objects in Python coming … Read more
[ad_1] Before you can use a module, you need to import it. Add import functools at the top of your script. 0 [ad_2] solved I have a problem with the functools.reduce() built-in function [closed]
[ad_1] Define r outside the Checkdiv function and in the function use r variable as a global variable with global keyword; global r and then r=int(n % d). so that other code blocks will be able to see the r variable too. r = 0 def Checkdiv(n, d): global r r = int(n % d) … Read more