[ad_1] You just have to many brackets ((df[‘Location’].str.contains(‘- Display’) & df[‘Lancaster’] == ” & df[‘Dakota’] == ‘D’ & df[‘Spitfire’] == ‘SS’ & df[‘Hurricane’] == ”)) You needed to remove a ‘)’ after each (‘- Display’) it looks like you will still have some problems with sorting through your data. But this should get you past … Read more
[ad_1] Try this code: a = input(“enter first number\n”) b= input(“enter second number\n”) limit=[] limit.append(a) limit.append(b) natNo=range(1,1000) xyz = [] for i in limit: xyz +=filter(lambda x: x == i or x % i==0, natNo) set = {} map(set.__setitem__, xyz, []) nums=set.keys() print “the multiples of the given numbers are: “+str(nums) c=reduce(lambda x, y:x+y, nums) … Read more
[ad_1] I finally found a solution, I hope someone helps from urllib.request import urlopen from bs4 import BeautifulSoup from io import BytesIO from zipfile import ZipFile file = urlopen(url).read() file = BytesIO(file) document = ZipFile(file) content = document.read(‘word/document.xml’) word_obj = BeautifulSoup(content.decode(‘utf-8’)) text_document = word_obj.findAll(‘w:t’) for t in text_document: print(t.text) [ad_2] solved Python: Extract text from … Read more
[ad_1] Can be extracted with a simple regular expression, as long as the text file is in the same format as the Python log output you posted (Returns all of them): import re file=””.join([i for i in open(“yourfileinthesamefolder.txt”)]) serials=re.findall(“u’serial_number’: u'(.+)'”,file) print(serials) I suggest reading up on how to use regular expressions in Python: Regular Expression … Read more
[ad_1] There is a function called list to do this directly.This can convert any string into list of characters. list(‘01101’) will return [‘0’, ‘1’, ‘1’, ‘0’, ‘1’] One more way is a=”01101″ a_list=[] for item in a: a_list.append(item) print(a_list) 5 [ad_2] solved a=’01101′ this has to be converted to [‘0′,’1′,’1′,’0′,’1’] ?? IN PYTHON [duplicate]
[ad_1] As far as I know, there are actually a few options: An external .txt file The module Pickle A database The module Pickle – simple example of how to pickle work import pickle element= [“Summer”,”Sun”] element.append(“Ice”) pickling_on = open(“Element.pickle”,”wb”) pickle.dump(element, pickling_on) pickling_on.close() So, now that the data has been pickled pickle_off = open(“Element.pickle”,”rb”) element … Read more
[ad_1] You can use this code: import re domain = “collabedge-123.dc-01.com” # preg_match(“/^(collabedge-|cb|ss)([0-9]+).dc-([0-9]+).com$/”, $domain, $matches); regex = r”^(collabedge-|cb|ss)([0-9]+).dc-([0-9]+).com$” res = re.match(regex,domain) print(res.group(0)) print(res.group(1)) print(res.group(2)) print(res.group(3)) Output: collabedge-123.dc-01.com collabedge- 123 01 1 [ad_2] solved How to split multiple string formats using regex and assigning its different groups to variable [closed]
[ad_1] Session timeout is set on server side – unless you actually try to time it by incrementing inactivity time and see when it times you out, there is no way for you to determine what the timeout period is. Any HTTP request (that should include page refresh) would most likely cause you to remain … Read more
[ad_1] The following should solve your problem. Note that if the names are not exactly the same they will be counted as different names. In your original post, the second item has the name ‘William’ whilst the first has the name ‘William ‘ which has a space after the m!!! data = [{‘desig’: ”, ‘name’: … Read more
[ad_1] Your Python code outputs: a=1&b=2&aaa=bbb In Ruby we might do this as: require ‘cgi’ parameters = {a: 1, b: 2} encoded = parameters.merge(Hash[*[‘aaa’, ‘bbb’]]) .map { |key, value| “#{CGI.escape key.to_s}=#{CGI.escape value.to_s}” } .join(‘&’) p encoded Which outputs the same: a=1&b=2&aaa=bbb It’s longer than the Python code, but IMHO also slightly more readable … You … Read more
[ad_1] My aim is to develop an auctioning system and I want to be able to choose the auction strategy – English, Dutch, Silent, etc – at run time. You could just use strategy pattern (also known as the policy pattern) to accomplish exactly this. You could also use mixins to provide the strategy instead … Read more
[ad_1] As an answer to: Is there a builtin I could use to input the position and return the item in the list? You just need to access the list with it’s index as: >>> my_list = [1,2,4,8,16] >>> my_list[4] 16 # returns element at 4th index And, this property is independent of language. All … Read more
[ad_1] Your code, as posted, works: File exists /usr/bin/python2.7 /home/surest/github/tests/test.py Enter the directory to the ISO file (or just drag the file here): /home/surest/Desktop/duties.odt /home/surest/Desktop/duties.odt <type ‘str’> True Process finished with exit code 0 Typo in filename/path /usr/bin/python2.7 /home/surest/github/tests/test.py Enter the directory to the ISO file (or just drag the file here): /home/surest/Desktop/meesa-typoed.odt /home/surest/Desktop/meesa-typoed.odt <type … Read more
[ad_1] input = “””3 5 2 1 3 4 2 3 4 2 2 1 3 2 1 8 7″”” f = [int(i) for i in input.split()] A = tuple(f) The value of A is now: (3, 5, 2, 1, 3, 4, 2, 3, 4, 2, 2, 1, 3, 2, 1, 8, 7) Important note: … Read more
[ad_1] One approach def filterList(numList, threshold): return list(filter(lambda x: x < threshold, numList)) Another approach: filteredList = [x for x in numList if x < threshold] 0 [ad_2] solved How do I return a list of numbers below a certain threshold without using complex list functions? [closed]