[Solved] Python Logical Operators

The operator and returns the last element if no element is False (or an equivalent value, such as 0). For example, >>> 1 and 4 4 # Given that 4 is the last element >>> False and 4 False # Given that there is a False element >>> 1 and 2 and 3 3 # … Read more

[Solved] Python Object Comparisons

What Im not sure about is what methods I need to use to compare the vectors. I tried googling it but couldn’t find anything. Does python have some methods to override < > <= and so on? Yes, Python has magic methods which are exactly for this purpose. You’re already using magic methods, such as … Read more

[Solved] Function to switch between two frames in tkinter

You shouldn’t put any logic in a lambda. Just create a normal function that has any logic you want, and call it from the button. It’s really no more complicated that that. class SomePage(…): def __init__(…): … button1 = tk.Button(self, text=”Back to Home”, command=lambda: self.maybe_switch_page(StartPage)) … def maybe_switch_page(self, destination_page): if …: self.controller.show_frame(destination_page) else: … If … Read more

[Solved] List in list changes but var in list not? [duplicate]

The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability. In your case, you are binding the name user_data to a list object. In other words, user_data acts as a list-reference to the actual list object in memory. When you say user_list.append(user_data), all you’re doing is appending … Read more

[Solved] How to extract an alphanumeric string from a sentence if a starting point and end point is given [closed]

Using regex Code import re def extract(text): ”’ extract substring ”’ pattern = r’^G.*[794]’ # pattern ends in 7, 9, 4 # Find pattern in text m = re.match(pattern, text) # find pattern in string if m: # Found pattern substring # Remove space, \, (, – by replacing with empty string m = re.sub(r'[ … Read more

[Solved] Extract numbers, letters, or punctuation from left side of string column in Python

Use Series.str.extract with DataFrame.pop for extract column: pat = r'([\x00-\x7F]+)([\u4e00-\u9fff]+.*$)’ df[[‘office_name’,’company_info’]] = df.pop(‘company_info’).str.extract(pat) print (df) id office_name company_info 0 1 05B01 北京企商联登记注册代理事务所(通合伙) 1 2 Unit-D 608 华夏启商(北京企业管理有限公司) 2 3 1004-1005 北京中睿智诚商业管理有限公司 3 4 17/F(1706) 北京美泰德商务咨询有限公司 4 5 A2006~A2007 北京新曙光会计服务有限公司 5 6 2906-10 中国建筑与室内设计师网 11 solved Extract numbers, letters, or punctuation from left side of string … Read more

[Solved] python IndentationError: expected an indented block [closed]

You have no indentation in your Python code! def datasource(cluster,user,password,url,env,jdbc_driver,timeOut,maxConn,minConn,reapTime,unusdTimeout,agedTimeout): #Declare global variables global AdminConfig global AdminControl Fixing this, there will be others. The next one to fix is: if len(Serverid) == 0: print “Cluster doesnot exists ” else: print “Cluster exist:”+ cluster and so on. 1 solved python IndentationError: expected an indented block [closed]

[Solved] AttributeError: ‘NoneType’ object has no attribute ‘current’

At the moment you call: print self,self.parent.current the LoginScreen is not instantiated yet, so you are calling for and object that does not exist. The workaround is to delay the call by 1 frame, that can be done using Clock class: Clock.schedule_once(self._myprintfunction, 1/60) and latter in your code but in the same class: def _myprintfunction(self, … Read more