Assuming you want a list of dicts as the output of the json with each dict be the form in your question: The following one liner will put it into the data structure your looking for with each tuple generating it’s own complete structure: [{‘name’:i[0], ‘children’: [{‘name’: i[1], ‘value’: i[2]}]} for i in tuples] But … Read more
The pivot_table function in pandas should do what you want. For instance: import pandas as pd frame = pd.read_csv(‘myfile.csv’, header=None) frame.columns = [‘user_id’, ‘date’, ‘event_type’] frame_pivoted = frame.pivot_table( index=’user_id’, columns=”event_type”, aggfunc=”count” ) In general, using vectorized Pandas functions is much faster than for loops, although I haven’t compared the performance in your specific case. 0 … Read more
Firstly, you have to understand Machine Learning as a field, and have some understanding of its sub fields. If you don’t intuitively understand your tools, you won’t be able to identify when to use them. The idea you’re talking about is called exploratory data analysis, and it can be very approachable if you think about … Read more
You can then apply a transformation to the result. df[‘mean’] = df[‘mean’].apply(lambda x: round(x)) or, if you want to truncate: df[‘mean’] = df[‘mean’].apply(lambda x: int(x)) 0 solved Can I change the dtype of mean function in Pandas? I want to change it to int type [closed]
# Using standard scikit-learn label encoder. from sklearn.preprocessing import LabelEncoder le = LabelEncoder() # Encode all string columns. Assuming all categoricals are of type str. for c in df.select_dtypes([‘object’]): print “Encoding column ” + c df[c] = le.fit_transform(df[c]) 3 solved how to encode only categorical data in a dataframe
Use this pattern instead (it looks for single digits): import re print(re.search(r’\b\d\b’, “I’m 30 years old.”)) Output: None This also works for Unicode characters in Python 3. To also account for punctuation, you can use \b\d(\b|\.|\?|\!) 3 solved regular expression to search only one-digit number
Python understands 1.2e34, as a float, but you can cast it to an int. int(1.2e34). If you want to loop between 1 and n inclusive, you would normally use range(1, n+1). Thus, in Python 3: for i in range(1, int(1.2e34)+1): print(i) # or do whatever you want — As FHTMitchell pointed out, in Python 2, … Read more
You need to iterate on the list and retrieve the good properties on each. values = [[Decoded(data=b’AZ:HP7CXNGSUFEPZCO4GS5RQPY6XY’, rect=Rect(left=37, top=152, width=94, height=97))], [Decoded(data=b’AZ:9475EFWZCNARPEJEZEMXDFHIBI’, rect=Rect(left=32, top=191, width=90, height=88))], [Decoded(data=b’AZ:6ECWZUQGEJCR5EZXDH9URCN53M’, rect=Rect(left=48, top=183, width=88, height=89))], [Decoded(data=b’AZ:XZ9P6KTDGREM5KIXUO9IHCTKAQ’, rect=Rect(left=73, top=121, width=91, height=94))]] datas = [value[0].data for value in values] # list of encoded string (b”) datas = [value[0].data.decode() for value in … Read more
You can use a string comprehension: numbers = [float(p.replace(‘€’,”).replace(‘M’,”)) for p in a] which gives: [110.5, 210.5, 310.5] solved Can i include multiple statements when creating a one-line for loop?