You’ve used the same name, list, for both a built-in type and a local variable. Don’t re-use the built-in names. Quoting PEP-8: If a function argument’s name clashes with a reserved keyword, it is generally better to append a single trailing underscore rather than use an abbreviation or spelling corruption. Thus class_ is better than … Read more
The reason you have the error is because the lists made by glob and os.listdir are not the same, either different files (glob is only getting jpg files and listdir gets everything) or different order, or both. You can change the filenames in a list, orig_files, to make a corresponding list of new filenames, new_files. … Read more
You can use the indices method of the slice to generate a tuple that can be passed to range. You need to know the length of your instance though. For example: >>> sl = slice(2) # or wherever you get that from >>> length = 100 >>> list(range(*sl.indices(length))) [0, 1] 5 solved How to transform … Read more
Here’s a straightforward solution with a simple loop: dict_x = {} for value in list_x: if isinstance(value, str): dict_x[value] = current_list = [] else: current_list.append(value) Basically, if the value is a string then a new empty list is added to the dict, and if it’s a list, it’s appended to the previous list. solved Convert … Read more
You need to specify the newline character when you open the file. On Windows, the default ends up adding an extra ‘\r’. with open(‘quotes.csv’, ‘a’, newline=”\n”) as myFile: writer = csv.DictWriter(myFile, fieldnames=fieldnames) … 1 solved i don’t know why this code is writing empty rows on my csv file when using a PC but not … Read more
This is one of the easiest problem ever. This is my solution (since you tagged your post for Python 3): name = input(‘Enter your name: ‘) print(“Welcome”, name) For Python 2, just change input to raw_input, and remove the parenthesis of the print function. 1 solved Ask the user for its name using raw_input [closed]
If your second dataframe in your upper screenshot is called df, this should do: df.set_index(‘Name’).stack().reset_index(level=0) 2 solved Panda Data Manipulation
I suspect what you are talking about is a quine. a Simple quine in python would be s = r”print ‘s = r\”{0}\”‘.format(s), ‘\n’, s” print ‘s = r\”{0}\”‘.format(s), ‘\n’, s solved Source Code is the output in Python [closed]
To just add a count you could keep a set of itertools.count objects in a defaultdict: from itertools import count from collections import defaultdict counters = defaultdict(lambda: count(1)) result = [(n, next(counters[n])) for n in inputlist] but this would add counts to all elements in your list: >>> from itertools import count >>> from collections … Read more
If what you want is to split the string at the first space, then you can use the string.split(s, maxsplit=n) where s is the string to split by and maxsplit=n is the number of splits to stop at. If you do not give any value for s that is only call the function as string.split(maxsplit=n) … Read more
For anyone curious, I quickly wrote a function for it. First off, the complete matching is written as a 2D list. The following function is needed before writing the main one: def index_2d(myList, v): #Returns tuple containing the position of v in the 2D list for i, x in enumerate(myList): if v in x: return … Read more
Firstly, You should not write in range(0,5) if you want to iterate through n numbers. Secondly, You do not need to write another while function. You use for loop or while loop for this question. Change for i in range(0,5): while i < 5: print(i ** 2) i += 1 break to for i in … Read more
import sys reload(sys) sys.setdefaultencoding(‘utf8’) Its just a guess as there is no code but if your code used to work in python3 and not in Python2 then this was the only problem I could think of. Try this if it helps. Otherwise its very difficult to recognize the issue. NOTE: I may help you in … Read more
First, move the non-date columns in to the index, then use replace and reset_index: df = df.set_index(‘CashFlows’) df = df.rename(columns=lambda x: ‘year_’+str(x.year)) solved How to change column names from numbers to names [closed]
You need to append to code each time through the loop, not assign to it. You shouldn’t reinitialize it in the loop, and the return statement should be after the loop. And if you want a 2-dimensional list, you need to wrap the concatenations in another list. However, the loop can be replaced completely with … Read more