If you want to create an instance, you can just do this c=Chemise() Then call whatever method you want c.Affiche_info() What you’re currently doing is creating another class that inherits from the first solved Object-Oriented Programming / python3 Classes
You are increasing your total line count incrementally with each processed line. Read in the full file into a list, then process the list. While processing the list, increase a counter thats “the current lines nr” and pass it to the output function as well. The len() of your list is the total line count … Read more
Try with this: \d+\s*((?:Apple|Banana|Orange|Pineapple)s?\b[\s\S]*?)(?=$|\d+\s*(?:Apple|Banana|Orange|Pineapple)s?\b) See: Regex demo The code: import re regex = r”\d+\s*((?:Apple|Banana|Orange|Pineapple)s?\b[\s\S]*?)(?=$|\d+\s*(?:Apple|Banana|Orange|Pineapple)s?\b)” test_str = “I have 2 apples in my bag and apples are great food toeat. you shud eat apples daily. it is very good for health. 3 bananas are also good. it reduces fat.” matches = re.findall(regex, test_str, re.MULTILINE | re.IGNORECASE) … Read more
So from the sound of your question you are attempting to get a binary search working for your example. First, it is useful to know that a binary search only works reliably on sorted data. This is quite different than a standard linear search that will always find the value, regardless of order. As you … Read more
From the question, it seems that you want to compute \sum_{i=1}^{n} 1/i If the input is 0, then returns 0. Remember that in a recursive function, you need to define a base case and an inductive clause. In your question, the inductive clause is: 1.0 / i + sum_of_reciprocals(i-1) while the base case can be … Read more
A correct version of you code – the problem was that you were having a bytes object instead of the str you probably expected. I added a .decode(‘utf-8’) to the content read from the website, and now the html is an str object. You recieved the error because you were working on a bytes object … Read more
Use the collections module to use the Counter function. Such as: import collections def carCompt(*args): return collections.Counter(“”.join(map(str.upper, args))) This will return {‘A’:5, ‘D’:1, ‘E’:3, ‘H’:2, ‘L’:1, ‘N’:1, ‘O’:1, ‘P’:2, ‘R’:2, ‘S’:1, ‘X’:1} If you want it to be case sensitive then leave it like: import collections def carCompt(*args): return collections.Counter(“”.join(args)) which will return {‘a’: 4, … Read more
You should edit your question so that it becomes clear to everyone, e.g. what format you used, what you have tried to get that output and so on. Actually, it’s an interesting problem. I assume you have above data in pandas’ dataframe format. It’s also important to add more tags related to your question. Anyway, … Read more
from itertools import chain l = [[‘password’, ‘_rev’, ‘_id’, ‘username’], [‘password’, ‘_rev’, ‘_id’, ‘username’, ‘name’], [‘password’, ‘_rev’, ‘_id’, ‘username’],[‘password’, ‘_rev’, ‘_id’, ‘username’,’country’]] list(set(chain(*l))) Output – [‘username’, ‘_rev’, ‘_id’, ‘name’, ‘password’, ‘country’] solved merge list of nested list to a single list which has lakhs of data python [duplicate]
I hope this helps! num = 7 while(True): if(num >= 1 and num <= 5): #If num is between 1 and 5 inclusive… #Do something. else: print(“Input out of bounds! “) num = int(input(“Please enter a new number: “)) 1 solved need assistance with while true look at body for more info [closed]
I would do if any((i != 0 and i != 1) for i in state): raise ValueError(“Error: A state is not specified or invalid entry”) This is short and concise. It can be even changed to valid = set((0, 1)) if any(i not in valid for i in state): raise ValueError(“Error: A state is not … Read more
You get NoSuchElementException, the driver can’t find your element. Change your xpath to this driver.find_element_by_xpath(“//*[@id=’pnnext’]/span[2]”).click() Without 3 quotation marks. 5 solved Selenium NoSuchElementException with driver.find_element_by_xpath
You can store the generate x and y in a list. This way you can check if x and y already exist, and if they don’t, add new ones. l = [] n = 1 while len(l) < 101: if not l: x = random.randint(0,n-1) y = random.randint(0,n-1) l.append((x, y)) else: x = random.randint(0,n-1) y … Read more
import random lst = [‘a’,’b’,’c’] print(random.choice(lst)) (Use the random module to get random values instead of going through the long process of creating a randomizer) solved How to chose a random word from a list with a condition in python [closed]
When you initialize your variables playerX and playerY you don’t specify they are global, so the function is trying to set the value of a local variable that does not exist. To fix this at the beginning of your update_coords function add global playerX, playerY This tells the computer that playerX and playerY are the … Read more