[ad_1] You can try turning resultList into a function: import scalikejdbc.SQL def resultList(sqlQuery: String): List[List[String]] = SQL(sqlQuery) .map( rs => List( rs.string(“transaction_id”) ) ) .list() .apply() 16 [ad_2] solved How can i execute the sql query with parameter?
[ad_1] Have call the method query $sql = $conn->query(“SELECT * FROM `whatevers` LIMIT 0, 30 “); 1 [ad_2] solved Call to fetch_assoc() on a non-object failing? [closed]
[ad_1] I made something based on your request. the content written inside the box was written inside a ‘p’ tag(paragraph). just so that you can have an idea. but you can delete that paragraph and what ever type of content you want. here is the html and CSS code. <!DOCTYPE html> <html lang=”en”> <head> <link … Read more
[ad_1] This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row. SELECT ID, MAX(alphabet) AS preference … Read more
[ad_1] I think your problem may be $(‘#id’).val() There is no element with the id=’id’ 1 [ad_2] solved Is the following code valid? [closed]
[ad_1] This is what are you looking for SELECT `t1`.* FROM `messages` `t1` INNER JOIN ( SELECT MAX(`id`) as `latest`, `user_id` FROM `messages` GROUP BY `user_id`) `t2` ON `t1`.`user_id` = `t2`.`user_id` AND `t1`.`id` = `t2`.`latest` [ad_2] solved this is sql table tbl_message distinct records by user_id but last id display mins DESC record form id … Read more
[ad_1] I have made an example how it could look with PDO (as i see you are just starting and i suggest to learn PDO as its not that hard) This way you also are safe from SQL injections. $host=”127.0.0.1″; $db = ‘test’; $user=”root”; $pass=””; $charset=”utf8mb4″; $usid = 0; $docname=””; $dsn = “mysql:host=$host;dbname=$db;charset=$charset”; $options = … Read more
[ad_1] This is not the answer, but the start point for you. Here is sqlfiddle: http://sqlfiddle.com/#!9/197dd9/1 You should add more data into that fiddle. After that use my query to see some results and play with that query until you get to the closest result of what you expect to get. And once you get … Read more
[ad_1] That Answer Already Given Many Times Please refer Following Links. Access denied for user ‘root@localhost’ (using password:NO) ‘Access denied for user ‘root’@’localhost’ (using password: NO)’ https://superuser.com/questions/603026/mysql-how-to-fix-access-denied-for-user-rootlocalhost Php/Mysql login authentication And If Can’t Resolve the Issue then Go On This Link. https://stackoverflow.com/help/duplicates https://stackoverflow.com/help/how-to-ask [ad_2] solved Access denied for user ‘root’@’localhost’ (using password: NO)?Unable to authenticate … Read more
[ad_1] You should not use whitespaces in your column names. change public static String COLUMN_PRODUS = “Nume Produse”; into public static String COLUMN_PRODUS = “NumeProduse”; [ad_2] solved SQLiteLog: (1) near “Produse”: syntax error
[ad_1] Ok, so here what i did to fixed my problem: PHP ….//Some query from mysql table $posts = array(); //Added foreach($data as $row) { $posts[] = array(‘post’=>$row); //New }echo json_encode(array(‘posts’=>$posts)); //then print here ANDROID JAVA JSONObject json = new JSONObject(response); JSONArray jArray = json.getJSONArray(“posts”); for (int i = 0; i < jArray.length(); i++) { … Read more
[ad_1] Try to avoid posting same question in other ways, edit the same question. You asked the same question in MYSQL OR not working Hope this will really help you:- try { $keyword = trim($_GET[“keyword”]); if ($keyword <> “” ) { $sql = “SELECT * FROM tbl_contacts WHERE 1 AND ” . ” (first_name LIKE … Read more
[ad_1] You’re performing a (potentially slow) network operation on the main thread. If your target SDK is 11 (Honeycomb) or higher this will throw a NetworkOnMainThreadException on Honeycomb or above, because this behaviour can block the UI and lead to an unresponsive app. You could use an AsyncTask to get around this, loading the data … Read more
[ad_1] Warning: mysqli_stmt::bind_param(): Number of variables doesn’t match number of parameters in prepared statement [duplicate] [ad_2] solved Warning: mysqli_stmt::bind_param(): Number of variables doesn’t match number of parameters in prepared statement [duplicate]
[ad_1] CREATE DATABASE IF NOT EXISTS database_name will execute the CREATE DATABASE database_name only if the database_name does not already exist. If the database_name does not exit, both queries will do the same job, that is they create the database_name. If the database_name exits, CREATE DATABASE database_name will return an error similar to “the database … Read more