[ad_1] I’ll keep it very simple, because this is very basic stuff. i = 10 Variable i is initialised as 10. while i > 0: print i*’*’ + 2*(10-i)*’ ‘ + i*’*’ i -= 1 While variable i is bigger than 0, it prints the string * i times, an empty space 2 * (10 … Read more
[ad_1] How about: foreach(array(458752, 131586, 65793) as $x) { $j = intval($x / 65536); $x = $x % 65536; $i = intval($x / 256); $k = $x % 256; echo “x=$x, i=$i, j=$j, k=$k\n”; } output: x=0, i=0, j=7, k=0 x=514, i=2, j=2, k=2 x=257, i=1, j=1, k=1 2 [ad_2] solved PHP value=arraykey + arraykey … Read more
[ad_1] Inside foreach you are updating $result and $row with new values, so the outer while will stop to loop. Rename those variables and it’ll work! [ad_2] solved while loop inside foreach loop inside while loop [closed]
[ad_1] If it helps you to understand, you can rewrite it from AND to OR: while (command != “quit” && command != “q”) { // do job } is equivalent to while (!(command === “quit” || command === “q”)) { // do job } https://en.wikipedia.org/wiki/De_Morgan%27s_laws 5 [ad_2] solved OR and AND operator confusion in Javascript … Read more
[ad_1] You’ve tagged this as c++ but it seems like you’re using entirely c.. So I’ll answer this as if it’s c. A segmentation fault occurs when you access memory that you don’t own. In this case you’re trying to print a character outside of the bounds of your string. (e.g. your string is len … Read more
[ad_1] string $val_for_Db = “”; for ($i=0;$i<$loop;$i++) { $val_for_Db = $val_for_Db.””.$value.”:”; } $val_for_Db = substr($val_for_Db ,-1); Now insert $val_for_Db to database. 2 [ad_2] solved PHP – duplicate value [closed]
[ad_1] The computer must repeat the question till it recieves a valid response. It (output) goes like this indefinitely. Reason : The problem is that you are receiving input only once in your code and then entering into loop to check for the age. since age value is not re-assigned after every iteration, if the … Read more
[ad_1] Your vector has zero length at start vector<int> binV; //zero length In this line of code for (int i = 0; i < binV.size(); i++){//some code} Will not run because binV is empty This expression is not correct if (input == 1 && input == 0) //not valid This && is logical and operator, … Read more
[ad_1] To get an array like this, simply use Array.from const additionPerLoop = 1000; const amount = 10000; const res = Array.from({length: Math.floor(amount / additionPerLoop) + 1}, (_, i) => i * additionPerLoop); console.log(res); 0 [ad_2] solved Optimizing a while loop in Javascript
[ad_1] When the scanf(“%i”, &choice); statement is executed, it puts the integer entered by the user, into the int variable choice. However, it also leaves the newline character in the input buffer causing the user input to get thrown off. When the scanf(“%c\n”, &guess); statement is executed, the next character entered is placed on the … Read more
[ad_1] what is wrong with this loop Initial value of b fails this check. 2*b+1 < 5 So neither loop body, nor the increment are ever executed. consider 2*b +1 as 2*c +1, i just ask, is this condition is a valid loop condition Yes, you can put any valid javascript expression there. As long … Read more
[ad_1] Okay. Thanks to @AshishJohn this question is now solvable. In the provided link you can see a define in the beginning which changes the syntax of for loops: #define for(i,a,b) for(i=a;i<b; i++) So for(j,0,np) will be converted by the preprocessor to: for (j=0; j<np; j++) which is a normal for loop. np is also … Read more
[ad_1] I’m guessing this is what you want to do, but since you haven’t told us your goals we can only guess public void DoWork() { for(int i=2; i < variable/ 2; i++) { if (variable% i == 0) { label4.Text =”yes not”; return; } } label4.Text = “yes”; } I don’t use C# but … Read more
[ad_1] Here is the code together with some comments. import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.ArrayList; import java.util.List; //import java.util.Scanner; public class Ingredients { public static void main(String [] args)throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); //or Scanner scan = new Scanner(System.in); int ingredientID=0; int sumOfIngredients=0; System.out.println(“Keep selecting the ingrients that you want … Read more
[ad_1] To work with elements in a cell array, use curly braces {} to retrieve the data stored at each cell index, as in the following loop: for i = 1:74 str = m{i}; % do something with string end 0 [ad_2] solved How to work with strings in a loop – MatLab [closed]