This is the way break works. If you want to iterate over the whole list, simply remove the break (or if you want to do something with the value, use pass as a placeholder). values = [1, 2, 3, 4, 5] for value in values: if value == 3: pass print(value) Output: 1 2 3 … Read more
System.out.print(Arrays.deepToString());//neither of them seems to be working System.out.print([0].Stringform()); This is dead code. It does nothing. In the first line you are asking the class Arrays to do something?? I’m not sure what you want to do there. Also change the name of the Number() function it might have conflicts with Java. Also brackets and semicolons … Read more
it’s ok now for (int i = 4; i > 0; i–) { for (int j = 1; j <= i; j++) Console.Write(“*”); Console.WriteLine(); } solved How to reverse for loop in c# for string type ? i need to remove one character each iteration
PHP Simple HTML DOM Parser would be a great place to start and the also read up on Cronjobs But show us what you got so far, so we can help you, we are not going to write the code for you. Edit: the problem is with this line: $html = file_get_contents($url); where is the … Read more
I wonder what can I do to increase the speed of the code. Can I get rid of some loops etc? The time complexity of each test case will be O(n) regardless of what you do, since you have to read all the numbers before you know when you stop printing zeros. Now, as for … Read more
Use squaring = element * element against squaring = list[element] * list[element] because for the first element, for example, you’re consulting list[-9] and that index is out. 0 solved Given a sorted list of integers, square the elements and give the output in sorted order
You have write a for loop from testAgainst and testAgainst.length === 4 that’s why it loops 4 times on toTest You algorithm is good. I don’t see any other possibilities, maybe by using regexp but it depends what you want to do solved Why is this for loop looping through the array 4 times?
I would suggest using a Dictionary for this task: d = {} for x in range(1,10): d[“slider{0}”.format(x)]= models.IntegerField(widget=widgets.Slider, default=50, label=””) 2 solved How to declare multiple similar variables in python? [duplicate]
I believe it should just be a couple of small typos. First, your second line looks like it should be indented, and where you have links[“property”], it looks like you would want link[“property”]. for link in links: payload[f’Links[{link[“property”]}][url]’] = link[‘url’] The reason it is giving you that error is that you are trying to get … Read more
Just add one line of code after the cout statement as follow: if (mode == TOPIG) { cout << “TOPIG MODE” << endl; while (cin.good()){ getline(cin, lines); while (!looking) { spot = lines.find(” “); if (spot == -1){ looking = true; spot = lines.length( ); } line = lines.substr(0, spot); TP1stLetter(line); if (!looking) lines = … Read more
It will decrement the value by 1 for each iteration This value is called as step which tells the for loop to how to get the next value for the iteration. It can be both negative and positive, but not zero. the positive step means it will increase the iteration value from the first argument … Read more
public static void loopingIssue(Integer totalItems, Integer range) { IntStream.range(0, totalItems).filter(i -> i % range == 0) .mapToObj(e -> mapToGroup(e, totalItems, range)) .forEach(System.out::print); } public static String mapToGroup(Integer e, Integer totalItems, Integer maxRange) { if (e + maxRange >= totalItems) { return e + “-” + (totalItems – 1); } else { return e + “-” … Read more
Here’s one way you can do this with a loop: Sub x() Dim i As Long For i = 1 To 5 Cells(6 – i, i).Value = “x” Next i End Sub 0 solved How to create a excel VBA loop to print text(“x”) in cell A5,B4,C3,D2,E1
Introduction This tutorial will provide a step-by-step guide on how to create a loop in Excel VBA to print the text “x” in cells A5, B4, C3, D2, and E1. This loop will be created using the For Next loop, which is a type of loop that allows you to repeat a set of instructions … Read more
Problem Your first version has a synchronisation bug, which manifests itself as a data race: $ go run -race main.go 0 (PrintAddr): 0xc0000b4018 0 (PrintAddr): 0xc0000c2120 ================== WARNING: DATA RACE Write at 0x00c0000b4018 by main goroutine: main.main() redacted/main.go:29 +0x1e5 Previous read at 0x00c0000b4018 by goroutine 7: main.(*User).PrintAddr() redacted/main.go:19 +0x44 Goroutine 7 (finished) created at: main.main() … Read more