A.) vs. B.) B will always copy the first value before checking if the result is 0. A will do the test first, and if the result is 0, it will stop before ever copying the first value. C.) vs. B.) Similar to A, C does the test first, and will never copy a value … Read more
To return a value from a loop, use break value: def my_def(port) @hsh.each do |k, v| break k if v == port end end In general, @Stefan’s comment solves this particular problem better: def my_def port @hsh.key port end solved return value from loop
I would suggest neither, rather I would suggest this List<int> data = Enumerable.Range(0, 10000000).ToList(); int j = -1; // Method 1 while (++j < data.Count) { // do something } int j = 0; do { //anything } while (++j<data.count); pre-increment operation is faster than post, although a small performance advantage 3 solved Performance: While-loop
You can just use: Collections.reverse(viewList); As documented by Oracle here. solved How to rewrite ArrayList in opposite direction [duplicate]
Well the message is clear and it is easy to spot in your program: double gallons,miles; while (miles>=0||gallons>=0) { miles is declared in a function and so is an automatic variable. Automatic variables are not initialized (so they have garbage values). Now in the first executable statement you compare miles. But miles is still uninitialized. … Read more
It’s usually a good idea to explain what you understand, so we don’t have to treat you as though you know nothing. Important note: This code behaves erratically. I’ll discuss that later. The exclusive or operator (^) produces its result by applying the following pattern to the binary representation of the numbers in question: Where … Read more
main = do nStr <- getLine let n = read nStr print . take n $ map (^2) [1..] Stack overflow is inappropriate for questions that have not been well-researched. Hit LYAH, RWH, the Haskell wikibook, or a combination of the two before you post here. solved How can I calculate a power of 1..n … Read more
Do something like for(int i=0; i< GroupOfPeople.Count; i++) { GroupOfPeople nm = (GroupOfPeople) nm.GroupOfPeople[i]; if(i < GroupOfPeople.Count – 1) names += nm.FirstName + “, “; else names += ” and ” + nm.FirstName; } solved C# ASP.NET for loop issue [closed]
You must realize that 12 does not divide 52, and that there are not 4 weeks to every month. So to give an example that you can fine tune to get exactly what you want, I’ve defined a week to belong to the same month that its thursdays belong to. This dovetails nicely with the … Read more
The inner loop will perform all of its iterations for each iteration of the outer loop. This is a case where you can test the behaviour yourself fairly easily, and generally it is faster to try these kinds of things out than to ask the question on here and wait for an answer. For example, … Read more
Shift all the items from the midpoint to the right, and then add the midpoint. If i were you i’d iterate in reverse. for (int i = array.length – 1; i > midpoint; i–) { array[i] = array[i-1]; } array[midpoint] = somenumber solved Adding a number to midpoint af an array [closed]
you just need to think that first line should be filled with *. Second thing is first character of every line should be *. and last character should also be *. and in between you need to fill spaces. int main() { int n=6; for(int i=n-1;i>=0;i–) // using n-1, bcz loop is running upto 0 … Read more
If this is what you’re aiming for: List(List(r1), List(r2), List(r3 chain, r4), List(r5 chain, r6 chain, r7)) then here is a possibility: val rules = List(“r1”, “r2”, “r3 chain”, “r4”, “r5 chain”, “r6 chain”, “r7”) val (groups, last) = rules.foldLeft(List[List[String]](), List[String]()) { case ((groups, curGroup), rule) if rule.contains(“chain”) => (groups, rule :: curGroup) case ((groups, … Read more
Based on your comment A user can input multiple integers the amount is unknown. Ex: 3 4 5 1. There is a space inbetween them. All i want to do is read the integers and put it in a list while using two scanners. You are probably looking for: scanner which will read line from … Read more
No need to use variables $a and $b. Simply do this: for ($i = 1; $i <3 ; $i++){ $c = $i.$i; echo $c; } Update(1): Based on your edited question, the solution would be like this: for ($i = 2; $i < 6 ; $i++){ $j = (int)($i/2); $c = $j.$j; echo $c . … Read more