you can use basic for loop and if statement to check values: List_1 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, 5), 5, 6, 7)] List_2 = [((1.1, 2, 3), (1.1, 2, 3, 4), (3, 4.4, 5), 5, 6, 7)] List_1 = list(List_1[0]) # [(1.1, 2, 3), (1.1, 2, 3, 4), (3, 4, … Read more
The output that you seem to want can be obtained with : [{“projectname” : key} for key in list1] 1 solved convert the python list to the dictionary with the same key but with different values
If you want to cycle the list elements, you can use itertools.cycle. We can call next twice on each iteration to get two numbers at a time from the iterator. from itertools import cycle a = cycle([0,1,2,3,4,5,6]) for _ in range(10): print(f”{next(a)} – {next(a)}”) Output: 0 – 1 2 – 3 4 – 5 6 … Read more
you should import your Module or external library first. and random module dose not have random.str() function! Try This : import random a = [‘blue’, ‘red’, ‘green’, ‘yellow’, ‘brown’, ‘black’] print(random.choice(a)) Good Luck. 1 solved How to generate a random word
<html> <body> <script> Array.prototype.randomElement = function () { return this[Math.floor(Math.random() * this.length)] } var list1 = [ “1”, “2”, “3”, “4”, “5”, “6”, “7”, “8”, “9”]; var list2 = [ “a”, “b”, “c”, “d”, “e”, “f”, “g”, “h”, “i”]; var list3 = [ “car”, “horse”, “gym”, “fair”, “boat”]; function myFunction() { document.getElementById(“demo”).innerHTML = list1.randomElement() + … Read more
var summary = FullList .GroupBy(p => p.product_id) .Select(g => new { product_id = g.product_id, product_name = g.First().product_name, quantity = g.Sum(p => p.quantity) }) .ToList(); As an exercise think about Concat for getting all the depot names. 2 solved C# + get list from list [closed]
The code loops through word with a step size of 3 and groups every 3 consecutive words. Let’s say word = [1, 2, 3, 4, 5, 6, 7, 8, 9] Over the course of the loop, i will be = 0, 3, 6 To grid, you append word[0:3],word[3:6],word[6:9] So grid will have in it [[1,2,3],[4,5,6],[7,8,9]] … Read more
Since your question does not clearly state that: This anwer assumes that the entries in all list should be sorted afterwards and that each number is unique within each sublist. You can reach this as follows: numbers = [[50, 100],[100, 130],[20, 50, 100, 130]] unique = sorted({n for l in numbers for n in l}) … Read more
The condition is tested before each iteration of the loop, not after every statement inside the loop body. So even though queue.pop(0) empties the list, you still execute the next statement and print the message. Then it goes back to the beginning and tests queue again. This time the condition fails and the loop terminates. … Read more
your first question: [i for i in range(n) for j in range(5)] your second question: [j for i in range(k) for j in range(1,6)] where k is the number of repeats 5 solved How to create the following lists with list comprehensions? [closed]
Using a list comprehension: A = [x for x in A if x not in B] 3 solved How to remove a list of elements from a list?
The syntax for the append method is as follow: list.append(obj) So you should replace students.append() by: students.append(tmp) Moreover, your print_info and input_info methods are not displaying the properties of a given student, but the properties of the class Student itself (which are always the same for every instance of the class). You should fix that. 3 solved Create … Read more
Is this what you are looking for? b = [[j for i in a for j in i]] 1 solved Lists in Python – Each array in different row [duplicate]
You should init hours_result outside of the outer for loop, here it’s set to [] for each med. 0 solved Creating multidimensional list of medicine dosage times [closed]
Given a non-empty list of strings of the same length, how do I create a list of lists of the letters at each position in the string without using zip? [closed] solved Given a non-empty list of strings of the same length, how do I create a list of lists of the letters at each … Read more