[Solved] list finding with 2 list
var inx = aaa.IndexOf(“2”); if (inx >= 0) { var result = bbb[inx]; } solved list finding with 2 list
var inx = aaa.IndexOf(“2”); if (inx >= 0) { var result = bbb[inx]; } solved list finding with 2 list
Your English segments are located in the first column. All you need to do is English = [sent.split(‘\t’)[0] for sent in data_examples] 0 solved Extracting all text before first tab from a list of strings
I think to be able to call the list.Add you have to call it from a function or a void (static void main() for example) 1 solved List c# The name “list.add” does not exist in this context
One way to do this without itertools is to use Python’s sum function to concatenate lists. >>> L = [ [1], [2], [3], [4], [5], [6], [7] ] >>> L_extend = [ sum(L[0:i+1], []) for i in range(len(L)) ] 2 solved Append cumulative list of lists python
If you can get it to print out one row of random numbers, you are almost there. The piece that you are missing is this: as you are running the loop that prints out the numbers, keep track of a counter (starting from 1). After each time a number is printed, check counter % 6. … Read more
d = [{‘A’: [3, 45, 34, 4, 2, 5, 94, 2139, 230345, 283047, 230847]}, {‘B’: [92374, 324, 345, 345, 45879, 34857987, 3457938457]}, {‘C’: [23874923874987, 2347]}] [{x.keys()[0]:sum(x.values()[0])} for x in d] solved I have a very big list of dictionaries and I want to sum the insides
nested[1] and nested[2] have no effect whatsoever on the time taken to perform operations on nested[0]. An object has no knowledge of what containers it might be referenced in or what other objects might be in the container with it. List operations take the same amount of time regardless of what objects are being added, … Read more
My guess is you’re trying to set the Classproperty of all the students in the list at once. You can do this with the ForEachextension method (include using System.Linq): class Student { public int Id { get; set; } public string Name { get; set; } public int? Class { get; set; } } public … Read more
Please look at the formatting tips, it will help you display your code as you wish. that said, I think this is what you want. The following code will iterate through each character in your list string. If it finds a match, it will print success list = “9876554321” for char in list: if char … Read more
Create a class that contains both items, and then sort that list: class Item { public int Id {get;set} public string Text {get;set;} } var unsorted = new List<Item> { new Item{Id = 3, Text = “eg3”}, new Item{Id = 1, Text = “eg1”}, new Item{Id = 2, Text = “eg2”}, } var sorted = … Read more
You can use the sorted function with the key parameter to look at the 2nd item, and reverse set to True to sort in descending order. >>> sorted(data_list, key = lambda i : i[1], reverse = True) [[‘Jimmy’, [8]], [‘Reece’, [8]], [‘Zerg’, [5]], [‘Bob’, [4]]] 2 solved How to sort this list by the highest … Read more
Im new to coding and was trying to loop through a list and kept coming up with the error code list index out of range. Why does this not work? solved Im new to coding and was trying to loop through a list and kept coming up with the error code list index out of … Read more
If I understand right you just want to determine which list has to be filled up depending on the datetable result set. So, when calling the function why don’t add (help)-parameter which determines where it was called from and depending on this variable the function will know what list to use. solved List to List
Lists don’t take name-value pairs. You probably want dictionaries here instead: definitions = { ‘title_label’: { ‘text’: (236, 218, 51), ‘background’: (125, 142, 246) }, ‘start_button’: { ‘text’: (32, 40, 145), ‘background’: (236, 235, 136), ‘pressed’: (44, 51, 112) }, ‘quit_button’: { ‘text’: (166, 21, 13), ‘background’: (48, 61, 188), ‘pressed’: (31, 40, 129) } … Read more
Simplest solution if all arrays have same length: string rowFormat = “{0,15}|{1,3} {2,3}”; Console.WriteLine(rowFormat, “History”, “B”, “W”); Console.WriteLine(new String(‘=’, 25)); for(int i = 0; i < array1.Length; i++) Console.WriteLine(rowFormat, array1[i], array2[i], array3[i]); But I would suggest to use custom type for your data instead of keeping data in three arrays. E.g. (names according to your … Read more