You can do it with min and zip quite easy: l1 = [1,2,3,4,5,6] l2 = [10,20,5,8,30,25] l3 = zip(l2,l1) print(min(l3)) Output: (5, 3) Comment As mention in the comment by @sshashank124 it is important that the first list is the list you want to find the minimum. In this case it would be l2 that … Read more
A simple way to do it is to iterate over the string, that will give you each letter separately: alphabet = “abcdefghijklmnopqrstuvwxyz” for letter in alphabet: print(“a” + letter) solved Adding first character of a string to each of the other characters [closed]
yes months = range(1, 13) if it’s python3 then: months = list(range(1,13)) solved Append a range of numbers in a List in Python, as 1 Line of Code
If all you want to do is return the index of b inside of a, if b is present, and so something else if it is not, try this : – a = [“one”, “two”, “three”, “four”] b = “three” try: print a.index(b) #if inside the function, use return except: #do something2 solved How to … Read more
#example of the list being used conundrum = [‘black pen’, ‘lift pen’, [‘go to’, -98, 132], [‘draw dot’, 10], ‘lift pen’, [‘go to’, -120, 137], [‘draw dot’, 10], ‘lift pen’, ‘thick lines’, [‘go to’, -55, 80], ‘lower pen’] #Import everything from the turtle library from turtle import * #Define the draw function def draw(test): home() … Read more
If i is the index you want to have, check the Count: if (i >= 0 && (list.Count – 1) >= i) { // okay, the item is there } If talking about nullable types, you could also check if the item on that index isn’t null: if (i >= 0 && (list.Count – 1) … Read more
You need to iterate on the list and retrieve the good properties on each. values = [[Decoded(data=b’AZ:HP7CXNGSUFEPZCO4GS5RQPY6XY’, rect=Rect(left=37, top=152, width=94, height=97))], [Decoded(data=b’AZ:9475EFWZCNARPEJEZEMXDFHIBI’, rect=Rect(left=32, top=191, width=90, height=88))], [Decoded(data=b’AZ:6ECWZUQGEJCR5EZXDH9URCN53M’, rect=Rect(left=48, top=183, width=88, height=89))], [Decoded(data=b’AZ:XZ9P6KTDGREM5KIXUO9IHCTKAQ’, rect=Rect(left=73, top=121, width=91, height=94))]] datas = [value[0].data for value in values] # list of encoded string (b”) datas = [value[0].data.decode() for value in … Read more
There is a function combinations in itertools and it can be used to generate combinations. import random import itertools # Generate a random list of 30 numbers mylist = random.sample(range(-50,50), 30) combins = itertools.combinations(mylist, 3) interested = list(filter(lambda combin: sum(combin) == 0, combins)) print(interested) Note that the results from filter() and itertools.combinations() are iterables and … Read more
I don’t know how you designed your models but you can follow this way: class Person { String name; Integer age; List<Address> addressList; // getter, setter, const… } class Address { // some fields… // getter, setter, const… } And then you can add your address to your person via add method: Person p = … Read more
list1 is a list that contains 1 element that is an numpy.array that contains multiple floats64. list2 is list that contains 1 element that is a list that contains multiple strings (that happen to look a lot like floats). You can convert them like so: import numpy as np # list of list of strings … Read more
A = [s for s in A if s.strip() != ”] or A = [s for s in A if len(s.strip()) > 0] 1 solved How to remove str. Of spaces from list [closed]
If you want to check if a string i contains string j, you can do it using i in j. Then comes the part how do you want the output actually. What my approach was to go through the list1 and for each of them go though the list2 and check if element of list2 … Read more
Here’s one utility function that worked for me: def printList(L): # print list of objects using string representation if (len(L) == 0): print “[]” return s = “[” for i in range (len(L)-1): s += str(L[i]) + “, ” s += str(L[i+1]) + “]” print s This works ok for list of any object, for … Read more
Use .FirstOrDefault() to get the first element matching your Where(), or null when none match: var oCustomer = oCust.Where(x => x.CountryCode == “US”).FirstOrDefault(); also discuss how to solve the above scenario using auto mapper with sample code. You’ve done this under various of your questions: “Here is my question, oh and please explain this related … Read more
If you already have a list of filenames use collections.Counter: from collections import Counter files = [“foo.txt”,”foo.txt”,”foobar.c”] c = Counter(files) print (c) Counter({‘foo.txt’: 2, ‘foobar.c’: 1}) The keys will be your files and the values will be how many times the file appears in your list: solved I have a list of file names and … Read more