Assuming your data object is a simple dict or list,all you need to do is: with open(output_path, ‘w’) as f: json.dump(data, f, sort_keys=True, indent=4) This will correctly dump to the output file. 3 solved How to fix ‘\n’ from json?
You shouldn’t try to manipulate them as strings – this will be fragile and very specific to the strings. Instead, parse the strings into dictionaries, do whatever manipulations you want, and then dump them back to JSON strings: import json s1 = ‘{“step”:”example step”, “data”:”example data”, “result”:”example result”}’ s2 = ‘{“attachments”:[ { “data”:”gsddfgdsfg…(base64) “, “filename”:”example1.txt”, … Read more
The output that you seem to want can be obtained with : [{“projectname” : key} for key in list1] 1 solved convert the python list to the dictionary with the same key but with different values
Use the json package and load the json. Assuming it is a string in memory (as opposed to a .json file): jsonstring = “”” [ { “issuer_ca_id”: 16418, “issuer_name”: “C=US, O=Let’s Encrypt, CN=Let’s Encrypt Authority X3”, “name_value”: “sub.test.com”, “min_cert_id”: 325717795, “min_entry_timestamp”: “2018-02-08T16:47:39.089”, “not_before”: “2018-02-08T15:47:39” }, { “issuer_ca_id”:9324, “issuer_name”:”C=US, O=Amazon, OU=Server CA 1B, CN=Amazon”, “name_value”:”marketplace.test.com”, “min_cert_id”:921763659, … Read more
+= Symbol is used for the appending text . ADD – AND assignment operator, It adds right operand to the left operand and assign the result to left operand 5 solved didn’t know symbol “+=” in android [closed]
JSONObject jObject = new JSONObject(response); JSONSONArray p = jObject.getJSONArray(“SizeOptions”); for(int i=0;i<p.length();i++) { JSONObject jObjectValue=p.getJSONObject(i); String name = jObjectValue.getString(“Name”); } 2 solved Parsing Json from server
You need to use JSON.parse(); it transforms your string into an array. var jsonStr=”[{“y”: 0.0, “x”: 0.0}, {“y”: 5.0, “x”: 5.0}]”; var array=JSON.parse(jsonStr); console.log(array[0].x,array[1].x); array contains everything you need. array[0] is the first set of values. array[0].x is the first x value. DEMO http://jsfiddle.net/uXr5g/1/ 1 solved I was wondering if a JavaScript programmer could help … Read more
First of all, I need to change your code to this to even get the result you’re talking about: $arr = array(‘id’ => $_POST[‘id’], ‘name’ => $_POST[‘name’], ‘model’ => $_POST[‘model’], ‘color’ => $_POST[‘color’]); $result = json_encode(array(‘success’ => 1, ‘message’ => “Updated Successfully”, $arr)); echo $result; The problem you are facing with the key “0” is … Read more
Consider a simplified example where your line of code >>> response=conn.getresponse() has retrieved the response from the server and saved it as an HTTPResponse object, and when you .read() the response you see a JSON string like this >>> responseData = response.read().decode(‘utf-8’) >>> responseData ‘{“day”: “Thursday”, “id”: 3720348749}’ You can use Python’s built-in JSON decoder … Read more
It seems like you want to encode your PHP array to JSON. Use json_encode() for that. json_encode($array); Returns a string containing the JSON representation of value. solved How to change data php to javascript json [closed]
Help me , i want to only call the id and need all the data like firstname,lastname,age etc in consol.log not like console.log(users.[0]); . [duplicate] solved Help me , i want to only call the id and need all the data like firstname,lastname,age etc in consol.log not like console.log(users.[0]); . [duplicate]
Try this: $(document).ready(function (){ $.getJSON(‘myurl.com/myFile.json’,function(result){ alert(result); }); }); It should be $(document).ready not $(document).read Remove the extra a after the alert. Remove the extra bracket after the url ‘myurl.com/myFile.json’) <– This one Please have a look at the jQuery API before starting something new. 2 solved Cannot access json with getJson function
try this $curl = curl_init(); curl_setopt($curl, CURLOPT_URL, ‘http://havanzee.tk/api/quote.json’); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HEADER, false); $strc = json_decode(curl_exec($curl),true); curl_close($curl); $i = rand(0,count($strc[‘danh-ngon’])-1); echo $strc[‘danh-ngon’][$i][‘content’]; 4 solved Random value json in php [duplicate]
You are trying to decode an array, either specify the specific item within the array, or make it a string. For instance: $unBillableArr=”{“id”:”123″, “to”:”+923412268656″, “MsgReceivedFrom”:”03349433314″, “message”:”Qwertyy”, “recdate”:”2017-11-20 19:01:49″}”; $json = json_decode($unBillableArr, true); // Or $unBillableArr = [‘{“id”:”123″, “to”:”+923412268656″, “MsgReceivedFrom”:”03349433314″, “message”:”Qwertyy”, “recdate”:”2017-11-20 19:01:49″}’]; $json = json_decode($unBillableArr[0], true); However, given the string you are receiving does not … Read more
Why don’t you read the documentation where it clearly states: json_t *json_loads(const char *input, size_t flags, json_error_t *error) Return value: New reference. Decodes the JSON string input and returns the array or object it contains, or NULL on error, in which case error is filled with information about the error. flags is described above. Also … Read more