javascript

[Solved] Getting the words between a pattern in a String in Javascript

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Here is a better way to do it: let text = `Some text here hello FirstComponent hello-end a bit more text here hello SecondComponent hello-end a bit more text there hello ThirdComponent hello-end some text there` function extractContent(input, startTag, endTag) { const re = new RegExp(“(“+ startTag + “)(.|\n)+?(” + endTag + “)”, ‘g’); const … Read more

[Solved] different CSS style class on page load for mobile and desktop [duplicate]

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Someone has posted something similar earlier, but removed the answer, after a little bit of tinkering I got this to work. By default the sidebar doesn’t have ‘active’ class set. Also by default it is hidden for mobile, but displayed for desktop. ‘active’ class gives the ability to display the sidebar on mobile. /* small … Read more

[Solved] Load javascript after 2 clicks on website

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$(function(){ var count = 1 $(document).click(function(){ if(count<=2){ count+=1; } else{ alert(“already clicked two times”); } }); }) this will start showing the alert after the 2nd click. You can write the code to load the javascript instead of this alert. 4 solved Load javascript after 2 clicks on website

[Solved] how to join rows in table [closed]

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Try the following: It will search for duplicated words in the first td in each tr. If match then it will move the content to the first tr and then remove the duplicated tr var arr = []; $(“table tbody tr”).each(function() { arr.push($(this).find(“td:first”).text()) }) var sorted_arr = arr.slice().sort(); var results = []; for (var i … Read more

[Solved] JavaScript arrays: how do I compact excess length?

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Since nothing in JavaScript specification says length must be exactly one higher than the last index, your demand is not reasonable. In common use, dense arrays overwhelmingly outnumber sparse ones. Since JavaScript does not keep indices in an ordered structure, finding out which index is the last every time array contents change would incur a … Read more

[Solved] Convert string to date format using javascript

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A little workaround could be the following, but if you have to manipulate dates a lot, I strongly recommend you to use the Moment.js library: https://momentjs.com/ var strDate = “2016-11-20”; var utcDate = new Date(strDate).toUTCString(); var convertedDate= utcDate.substring(utcDate.lastIndexOf(“, “) + 1, utcDate.lastIndexOf(” 00:”)); console.log(convertedDate.trim().replace(/\s/g, ‘-‘)); Pay attention that the implementation of this method may change … Read more

[Solved] How to filter a dropdown list based on a already pre selected list

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jQuery Get the selected country and then find the <option> using attribute-equals-selector and hide the siblings $(function () { var country = $(‘.selected’).data(‘country’); $(‘#CountryCode’).find(‘[value=”‘ + country + ‘”]’).siblings().hide(); $(‘#CountryCode’).val(country); }); HTML Add data-* attribute to the html elements <ul> <li data-country=”ARG”>Argentina</li> <li data-country=”USA” class=”selected”>United States</li> <li data-country=”AUS”>Australia</li> </ul> DEMO 1 solved How to filter a … Read more

[Solved] How to make an html element appear and disappear again and again with Js?

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you can do this using setInterval method:- var interval=500,i=0; setInterval(function(){ i++; if (i % 2 !== 0) { document.getElementById(‘square1’).style.visibility = ‘visible’; document.getElementById(‘square2’).style.visibility = ‘hidden’; } else { document.getElementById(‘square1’).style.visibility = ‘hidden’; document.getElementById(‘square2’).style.visibility = ‘visible’; } },interval); if you want it to go active after it reached a point on the page use an if construct to … Read more