On your class DVDPlayer you chose to say that a regular DVDPlayer cannot record. So you set it to false. If you want it to record you either change the variable directly, like you did on the class DVDPlayerTestDrive. The boolean canRecord = false is only meant to show you that it is possible to … Read more
Here’s a simple solution to convert unix time to localDate and then you’re free to format it as you please: long time = 1491231860; final LocalDate localDate = LocalDate.fromMillisSinceEpoch(unixSeconds); 1 solved unix YYYYMMDDHHMMSS.miliseconds format to java date [closed]
Your ENUM values on the map seem like another map. Therefore I put it like this Map<Enum, Map<String, Object>> However, question is not clear! Here is one possible solution. import java.util.*; public class Main { public static void main(String[] args) { Map<Enum, Map<String, Object>> map = new HashMap<>(); Map<String, Object> value = new HashMap<>(); value.put(“String1”, … Read more
if you don’t want to/can’t use libraries c==’ ‘||c==’\t’||c==’\n’||c==’\r’ note that \r is a carriage return it’s part of the windows \r\n combination (and used commonly in network protocols) solved Character Comparison [closed]
You don’t show much effort to let us help you solving this. But since I’m learning bash scripting, I took your question as practicing. So… here is a bash script to rename duplicated files. /!\ The renamed files will be in the folder of first argument. So, in your case, you’ll have to launch it … Read more
To give you an example of a better code: int number1 = scanner.nextInt(); int number2 = 0; while (true) { number2 = scanner.nextInt(); if (number1 == number2){ System.out.println(“Woo!”); break; } number1 = number2; } Explanation: This code will always compare the two last entered numbers. (e.g. 1,2,2 will print Woo!). For better legibility I changed … Read more
You can always try to do it like this; var imgUrl = “http://sits/productimages/00670535922278.png?sw=350&sh=350;”; var splitterArray = [‘.jpeg’, ‘.png’, ‘.jpg’, ‘.gif’]; for (var i = 0; i < splitterArray.length; i++) { var imgUrlArray = imgUrl.split(splitterArray[i]); if (imgUrlArray.length > 1) { //Do your thing here } } You use a array of your extensions that will be … Read more
There is no way to set the initial index of an array: it still has a 1st (index 0) element, it just happens to be null in your case. You can always start iterating from whatever index you want, but you’ll be wasting space. You could always make your own class… class WeirdIndexArray<T> { private … Read more
1. Install Java. Don’t have Java installed? Search for and install OpenJDK Java 7 or 8 via Software Center. Or install oracle java by following this post. 2. Download Eclipse from its website. Check out your OS Type, 32-bit or 64-bit, by going to ** System Settings -> Details -> Overview,** then select download Linux … Read more
Well, there are quite a number of syntax errors: public class Node <T> implements NodeActionInterface { // <T> data; T data; // ^ T is the data type… Node<T> leftTree; Node<T> rightTree; // ^ not really an errror, but you should use the generic here //public <T> Node(<T> data) public Node(T data) // ^ declared … Read more
You can search on a listview and you can use OnItemClickListener From search view new SearchView.OnQueryTextListener() { @Override public boolean onQueryTextChange(String newText) { if (TextUtils.isEmpty(newText)) { mListView.clearTextFilter(); } else { mListView.setFilterText(newText.toString()); //you can use this to filter items } return true; } @Override public boolean onQueryTextSubmit(String query) { return true; } } And in Listview … Read more
The short answer: #a.+#((([A-Za-z]{3,9}:(?:\/\/)?)(?:[\-;:&=\+\$,\w]+@)?[A-Za-z0-9\.\-]+|(?:www\.|[\-;:&=\+\$,\w]+@)[A-Za-z0-9\.\-]+)((?:\/[\+~%\/\.\w\-_]*)?\??(?:[\-\+=&;%@\.\w_]*)#?(?:[\.\!\/\\\w]*))?) This will match any character except line breaks in the content section, and should match any url. NOTE: You will have to escape all backslashes in the given regex to represent it as a java String literal. Sources for the url regex: What is the best regular expression to check if … Read more
func is always calling itself. There is no stopping condition. Each call creates a new stack frame, until the call stack is full and StackOverflowError is thrown. Recursive methods should always have a stopping condition. For example – n < 0 : public static int func(int n){ int result; if (n >= 0) result = … Read more
You created a new empty list and iterated by its elements (there are none). If this method must calculate what you want, use this: public static double q1(ArrayList<String> input1){ double sum1 = 0; for (String s1: input1){ sum1 += s1.length(); //Line 6 } return Math.pow(sum1, 3); } solved Why won’t my method store the length … Read more
You are comparing all the characters of the String against all the characters of the same String, so of course you find a match and return “yes”. You only need a single loop. All you need is : e = 0; for ( int i = 0 ; i <t ; i++) { f = … Read more