Guessing that you want to split by the comma then this will make it String toSplit = “LXI H, 2000H, MOV M A”; // this is a regular expression, you should study regular expressions too String[] split = toSplit.replace(“,”, “”).split(” +”); for (String s : split) System.out.println(s); Read the String class in the java API … Read more
Move your displayer(); below: @Override public void onClick(View v) { so you get: @Override public void onClick(View v) { displayer(); //Call method “displayer” when user presses button TextView Tv = (TextView) findViewById(R.id.TV); TextView Tv2 = (TextView) findViewById(R.id.Tv2); String date = sdf.format(calendar.getTime()); Tv.setText(“The current time is ” + date); String str = date.charAt(0) + “” + … Read more
What you call capacity, is the size, or even better the length of the array, i.e. the amount of items that you can store in the array. The indexing always start from ZERO, therefore, as you can also easily figure out yourself, if you start from ZERO and you have an array of length N, … Read more
Java does not support union types; however, both of these types share the same base Object class, so you could assign either one of them to a variable defined like this Object something; something = “Hello World!”; something = new ArrayList(); // this is a collection. Odds are that you probably were thinking of a … Read more
The error messages are very descriptive. Check file MainActivity.java, line 65 and fix it. Similar for line 86. Anyway, these are the errors: Syntax error on token “)”, { expected MainActivity.java /CalculatorVamalV2/src/com/elitiv/calculatorvamalv2 line 65 Java Problem You missed a close brace } in the inner class definition: @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); … Read more
In your switch statement, replace every return; with break; which is the signal to break out of the switch, but the rest of the code will run. When you write return within a void method, when its reached it means you are breaking out of the method itself so no code past it will be … Read more
Rules for a.compareTo(b) returns negative value : a is before b returns 0 : a equal to b return positive value : a is after b Because the parameter are first, second and you compare like second.compareTo(first) you’ll get reverse order : (second+first) 344 first+ second 434 comparing : -1 >> 4 is before 34 … Read more
For Java 8 use a lambda expression and the Arrays sort function: Users[] someUsers = {user1, user2, user3}; Arrays.sort(someUsers, (a,b) -> a.firstName.compareTo(b.firstName)); For previous versions use a Collection Comparator: Users[] someUsers = {user1, user2, user3}; List<Users> userList = new ArrayList<Users>(Arrays.asList(someUsers)); Comparator<Users> comparator = new Comparator<Users>() { @Override public int compare(Users left, Users right) { return … Read more
That code runs just fine with the java command-line tool: java canine When you do java canine, you’ll telling the java tool to find and load the canine class and run its main method. If you were using java Animal, the issue is that Animal has no main. canine does. Clearly, class canine is -in … Read more
If all of your images are similarly sized, you are attempting to allocate ~2028601104 bytes = ~1981055KB = ~1934MB. You have 64MB or less on most Android devices that your app can use. The image that you failed on is 22050012 bytes in size, when decoded and perhaps scaled. That is equivalent to 2347 x … Read more
In i = i– – –i you have: i–, a post-decrement, which retrieves the current value of i (1) and then decrements i to 0 – –i, a pre-decrement, which decrements i again and retrieves the updated value, -1 So you end up with i = 1 – -1 which is 2. Needless to say, … Read more
d1 is not initialized in the else block and in only in the if or else if blocks, so if all the statements in if() and else if() blocks are false then the controller comes to the else block, where d1 is still not initialized. so when you try to access it inside system.out.println(), the … Read more
If any OS is multi-processor, then JVM uses all of them or one of them? On most modern hardware architectures, the JVM will make use of all CPUs/cores made available to it by the OS. And As processors ahve different memory context so their corresponding memory threads will also have different memory contexts, so they … Read more
Here it is Method body public void callDatabase(String date1, String date2){ PreparedStatement stmt=con.prepareStatement(“select absentdt, period from stu_attendancemaster where classid=70 AND absentdt BETWEEN ‘”+date1+”‘ AND ‘”+date2+”‘ “); ResultSet rs=stmt.executeQuery(); while(rs.next()) { //get data here } } Method call String d1,d2; //initialize callDatabase(d1,d2); 3 solved How to fetch database values between two dates [closed]
public class TranslateChar { /** @param args */ public static void main(final String[] args) { final Map<Character, Character> mapCharCod = new HashMap<>(36); final Map<Character, Character> mapCharDecod = new HashMap<>(36); mapCharCod.put(‘A’, ‘Z’); mapCharCod.put(‘B’, ‘X’); mapCharCod.put(‘C’, ‘Y’); mapCharDecod.put(‘Z’, ‘A’); mapCharDecod.put(‘X’, ‘B’); mapCharDecod.put(‘Y’, ‘C’); final String toCod = “CAB”; StringBuilder sb = new StringBuilder(“{“); for (final char c … Read more