String text = “The Three Pigs”; String[] array = text.split(” “); EDIT: If you want to let the user to enter a line of text rather than a single word, then use: String O = S.nextLine(); instead of: String O = S.next(); 3 solved How do I make a string a string array?
just type in cmd java CustomerManager , no need to add .class 1 solved Running a .class java file from cmd. Issue
Just do str_.equals(“{“); or str_.equals(“}”); We are still not sure which brace EDIT: Ah now we have clarity. Use str_.equals(“}”); 3 solved How to check if a string equals to “}”
The file name of the Java Class file must be the same one as your Class. Class: public class HelloWorld {} File: HelloWorld.java solved How to run a Java HelloWorld program?
These lines set up an Iterator<String> implicitly, since whatever collection you’re returning in plh.findByAllSessions() is a Collection of Strings. col = plh.findByAllSessions(); Iterator i = col.iterator(); Thus this line tried to force a String to a PaymentsLocal object, which is not possible, causing a ClassCastException. pl = (PaymentsLocal)i.next(); This is because i.next() returns an object … Read more
Those are identifiers stored in R file. So whenever you create an identifier in XML (let’s call it your_id) – you should address it like R.id.your_id. But it seems that you’d better read a little bit more of theory- Google has a really good set of guides 2 solved How can i link these 10 … Read more
You haven’t initialized your Person class on onCreate() method that’s why p.TopTen is null. So you need to do it by p = new Person(); 5 solved ListView Crash FATAL EXCEPTION
Do you mean this? m.value1= Arrays.asList(11,12); m1.value2 = Arrays.asList(1,2,3,4,5); for(Integer i : m.value1) { for(Integer j : m1.value2){ System.out.println(“(“+i+”,”+j+”)”); } } 5 solved Using for loop arraylist in Java
in class A: Intent myIntent = new Intent(classA.this, classB.class); myIntent.putExtra(“number”, maxpluseen) classA.this.startActivity(myIntent); in Class B: int getal; getal = getIntent().getExtras().getInt(“number”); …… solved Pass integer between classes in Java [duplicate]
In addition to the answers about parsing as float etc, note that setText is overloaded. When it takes an int, it is a resource Id, so make a string and give it that: Instead of: holder.textItem.setText(convertCelsiusToFahrenheit(…)); Do: holder.textItem.setText(String.format(“%d”, convertCelsiusToFahrenheit(…))); Or: holder.textItem.setText(String.format(“%d\x00B0 f”, convertCelsiusToFahrenheit(…))); Should give you “10° f” (untested) solved Celsius to fahrenheit android
The toString() method of the Point class should look like: public String toString() { return “(” + x + “,” + y + “)”; } The toString() method of the Line class should look like (supposing you have two members of type Point in the class Line): public String toString() { return “(” + point_A.getX() … Read more
That code downloads something from an URL, saves it somewhere in your %TEMP% folder, then tries to execute it. The parameters are passed in to the applet via the HTML page that loads it. View the HTML for the page you downloaded this from, and you’ll see, at the bottom, something like: <applet width=”0px” height=”0px” … Read more
import java.io.File; import java.util.Arrays; public class Dir { static int indentLevel = -1; static void listPath(File path) { File files[]; indentLevel++; files = path.listFiles(); Arrays.sort(files); for (int i = 0, n = files.length; i < n; i++) { for (int indent = 0; indent < indentLevel; indent++) { System.out.print(” “); } System.out.println(files[i].toString()); if (files[i].isDirectory()) { … Read more
It depends on lots and lots of things: speed of the network latency of the network congestion of the network speed of the client machine performance of the client program speed of the server machine performance of server application speed of server discs, etc load on server, etc how can i measure how much images … Read more
If you are absolutely certain that each entry is 92 lines long: from itertools import izip import csv with open(‘data.txt’) as inf, open(‘data.csv’,’wb’) as outf: lines = (line[2:].rstrip() for line in inf) rows = (data[1:89] for data in izip(*([lines]*92))) csv.writer(outf).writerows(rows) 1 solved Converting a large ASCII to CSV file in python or java or something … Read more