[ad_1] I solved my question, is not simple question IF first added boolean equals in my class public boolean equals(Object o) { ItemAdubacao adubacao = (ItemAdubacao) o; if (this.getTanque_id() == adubacao.getTanque_id() && (this.getProduto().equals(adubacao.getProduto()))) { return true; } return false; } then I created an ArrayList to separate the duplicate objects and adding the sum of … Read more
[ad_1] You are dividing an int by int; the result is an integer. You must cast one of the int to the double data type to get the correct result. Sum = (double)n/d; [ad_2] solved [Java]- What is wrong with this code? [closed]
[ad_1] How about using something like this, boolean run = true; while(run) { //when the condition to terminate the program is met //set run to false run = false; } 1 [ad_2] solved I want my program to run again and again without getting stop
[ad_1] The x() statement is a method call with a parameter of y which returns a boolean for the evaluation. 10 [ad_2] solved What is the result type of x in if (x(y)) in Java?
[ad_1] If d is the instance variable then it would be visibile to every method that you defined above. [ad_2] solved If I change the value of a variable in one function, will the changed value be used in another in Java?
[ad_1] Yes you can. Unfortunately Java is not well suited for this task (for various reasons). I would suggest you buy an arduino set and learn what it can do regarding controlling devices and receiving input from sensors, so you know more about what is possible. 2 [ad_2] solved Java Programming real objects [closed]
[ad_1] String studId = “”; String firstName =””; String lastName =””; int number =0; int index = 0; StudentServiceImpl studServImpl = new StudentServiceImpl(); Scanner scan = new Scanner(System.in); do{ System.out.println(“1.Add Student:”); System.out.println(“2.Delete Student:”); System.out.println(“3.Display Students:”); System.out.println(“4.Exit”); System.out.println(); System.out.print(“Select number: “); System.out.println(); number=scan.nextInt(); if(number==1){ Student student = new Student(); System.out.println(“Enter Student No.”); studId = scan.next(); student.setStudId(studId); … Read more
[ad_1] Assuming you have one thread: use sleep(timeout) – it will always wait timeout seconds before continuing. Assuming you have two threads: Option 1: Thread1 simply should wait and has nothing to do with Thread2 – use sleep(timeout) – it will always wait timeout seconds before continuing. Option 2: Thread1 does have something to do … Read more
[ad_1] try this String []aaaa = “[1000000062,1000000095,1000000058,1000000400]”.replace(“[“, “”).replace(“]”, “”).split(“,”); int aa[] = new int[aaaa.length]; for(int i=0; i<aa.length; i++){ aa[i] = Integer.parseInt(aaaa[i]); } 1 [ad_2] solved Convert ArrayString to Array android [closed]
[ad_1] public static void main(String[] args) { int smallest = 0; int large = 0; int num; System.out.println(“enter the number”);//how many number you want to enter Scanner input = new Scanner(System.in); int n = input.nextInt(); num = input.nextInt(); smallest = num; //assume first entered number as small one // i starts from 2 because we … Read more
[ad_1] Probably there could be better solutions, but the following should work for you: public static void main(String[] args) { Integer[] a = new Integer[] { 1, 0, 0, 1, 0, 0 }; List<Integer> a1 = Arrays.asList(a); Integer[] b = new Integer[] { 0, 1, 1, 0, 0, 0 }; List<Integer> a2 = Arrays.asList(b); List<Integer> … Read more
[ad_1] Based on the JavaDoc – jEditorPane supports the bleeding edge HTML 3.2 and CSS1 so the short answer is, you really don’t want to try rendering modern web pages with it. However, you may be able to do this: import javax.swing.text.html.HTMLEditorKit; import javax.swing.text.html.StyleSheet; HTMLEditorKit kit = new HTMLEditorKit(); jEditorPane.setEditorKit(kit); URL url = new URL(location … Read more
[ad_1] Don’t use the getJsonObject() method to get the values inside the JSONObject, but use the corresponding getters for the types of the values. The key-value pairs themselves are no JSONObjects. JSONObject jsonObj = new JSONObject(response); String fromCurrency = jsonObj.getString(“from”); String toCurrency= jsonObj.getJSONObject(“to”); Double fromAmount = jsonObj.getDouble(“from_amount”); Double toAmount= jsonObj.getDouble(“to_amount”); [ad_2] solved How to read … Read more
[ad_1] Try this it worked to me : public class HelloWorld { private static int a = 1; private static int b = 1; public static void main(String[] args) { if (isCorrect(a, b)) { debug.setText(“YES!”); } if (!isCorrect(a, b)) { debug.setText(“NO!”); } } public static boolean isCorrect(int a, int b) { boolean ok = false; … Read more
[ad_1] And what is so mysterious about it? public static void main(String args[]) { Random ran = new Random(); //Generate a digit between 0-8 +1 int number = ran.nextInt(9) + 1; //Multiply with 10000 number *= 10000; //Add a number between 0-9999 number += ran.nextInt(10000); System.out.println(“Random no:” + number); } You should gain some fundamental … Read more