java

You need to isolate your variable. How about a reg-ex? return source.replaceAll(“(\\W)(” + var2Rename + “)(\\W)”, “$1” + newName + “$3”); Explanation. The \\W will check for non-letter characters, eg the boundary of a variable expression. We want a boundary on both sides of the variable, and then to replace we need to make sure … Read more

public static String checkUserInputSeriesName(Scanner sc, SeriesLibrary seriesLibrary){ boolean validInput = false; String seriesName = null; do{ validInput = false; seriesName=sc.nextLine(); for(int i = 0; i < seriesLibrary.getTvSeries().size(); i++){ if(seriesName.equals(seriesLibrary.getTvSeries().get(i))){ validInput = true; } } if(!validInput){ System.out.println(“That Series does not exist, please try again!”); sc.nextLine(); } }while(!validInput); return seriesName; } solved My validation method is not … Read more

First, pass Address class as parameter. void setAddress(Address s) Since Address in a static nested class, but you have declared Address as String in your Problem3_1 class file. So you will need to concat the values manually like void setAddress(Address s) { //address = s; address = s.number + ” , ” + s.street; } … Read more

Simply count the number of attempts and exit the loop once it reaches the threshold. Like that: int attemptsNum = 0; final int maxAttempts = 3; do { System.out.print(“Guess a number between 1 and 10: “); user = input.nextInt(); if (user > comp) System.out.println(“My number is less than ” + user + “.”); else if … Read more

When you know what String you are looking for, you can try the following. String s=”description: John Newman Logged on: 03.26.2018 9:26:29″; String log1 = null; if(s.toLowercase().contains(“logged on”)){ log1 = “Logged on”; // Your desired string }else if(s.toLowercase().contains(“logged off”)){ log1 = “Logged off”; // Your desired string } or Simply String log1 = (s.toLowercase().contains(“logged on”)) … Read more

Since you start with Java – on the first degrees on your learning curve you will eventually not need any private classes. They make sense for inner classes (a class within a class) when this inner class is not usable/useful outside the parent class. But for now: just keep in mind, that private is not … Read more

Assuming you have the corresponding getters and setters, you may try something like below: List<Person> unique = persons.stream() .collect(Collectors.groupingBy(Person::getCustomerNumber)) //returns a Map<String,List<Person>> with customerNumber as key .values() .stream() // stream and sort each list .map(e-> e.stream().sorted( Comparator.comparing(Person::getBirthday) .thenComparing(Person::getBirthTime)) .findFirst().get()) // map to first Person obj .collect(Collectors.toList()); unique.forEach(System.out::println); 1 solved Remove objects from list based on … Read more