[ad_1] The problem is here: double calcTipsPerHour = resultTotalHours / totalTips; This is currently doing 2 / 10 = 0.2. You want to do the reciprocal: double calcTipsPerHour = totalTips / resultTotalHours; This should also fix your waiter’s pay 0 [ad_2] solved my math is broken on TextView
[ad_1] You are doing quite a lot that is not necessary. I reduced the code and added some comments. In short: Use the position to find which data should be fetched (it could also be a prefetched list which would reduce the fetch from database to 1 query) You should use the ViewHolder pattern to … Read more
[ad_1] Try this function:- //1 minute = 60 seconds //1 hour = 60 x 60 = 3600 //1 day = 3600 x 24 = 86400 public void printDifference(Date startDate, Date endDate){ //milliseconds long different = endDate.getTime() – startDate.getTime(); System.out.println(“startDate : ” + startDate); System.out.println(“endDate : “+ endDate); System.out.println(“different : ” + different); long secondsInMilli = … Read more
[ad_1] Your implementation of Clip class is wrong. It should be something like this: public class Clip { private String title; private String author; public Clip(String title, String author) { this.title = title; this.author = author; } public String getTitle() { return title; } public void setTitle(String title) { this.title = title; } public String … Read more
[ad_1] The regular expression [abc]? matches zero or one character that can be either a, b, or c. Thus it does not match abc. Positive matches would be the empty string, a, b, or c. On the other hand [abc]+ matches one or more characters that can be either a, b, or c. Therefore, it … Read more
[ad_1] The problem is actually like counting in base sizeof(set) on length k (assuming the set has 10 items maximum). For instance, with a set of { 0, 1, 2 } on length 2, you count from 00 to 22, base 3. To solve the “one digit change only” constraint, instead of counting increasingly, do … Read more
[ad_1] First convert your Date in to specific Date format using SimpleDateFormat Use SimpleDateFormat simpleDateFormat = new SimpleDateFormat(“EEEE”); to get Day name in week WHERE EEEE -> Day name in week SAMPLE CODE SimpleDateFormat inFormat = new SimpleDateFormat(“dd-MM-yyyy”); try { Date myDate = inFormat.parse(date+”-“+month+”-“+year); SimpleDateFormat simpleDateFormat = new SimpleDateFormat(“EEEE”); String dayName=simpleDateFormat.format(myDate); } catch (ParseException e) … Read more
[ad_1] Your code is a beginning, but doesn’t fill all values. You should nest your for-loops, and only fill the left part. The right entry can then be mirrored from the left entry. Try this: public static void main(String[] args) { int[][] table = new int[5][8]; for (int row = 0; row < 5; row++) … Read more
[ad_1] Declaration: void printNames(Iterable<Teacher> teachers) { for (Teacher teacher : teachers) { System.out.printf(“%s “, teacher.getName()); } } Usage: switch (selection) { case 1: printNames(teachers); break; [ad_2] solved Creating a method in Java
[ad_1] Amit i’ve seen your other question, what matters is always only reachability, it doesn’t matter how you use student, it will always be reachable until the class that contains it is reachable. Update, regarding the question you added: I mean which case (CASE-1/CASE-2) is more GC efficient in terms of Time? Neither because you … Read more
[ad_1] you can do it like this EditText input = (EditText) findViewById(R.id.ip); Button button = (Button) findViewById(R.id.calcbutton); TextView textView = findViewById(R.id.tv15); button.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { int num = Integer.parseInt(input.getText().toString()); // for 0.15% float fifteen_percent = (float) ((num * 0.15) + num); textView.setText(String.valueOf(fifteen_percent)); } }); You can do the same for … Read more
[ad_1] For this you don’t even need regex. Just split the String and call the right indices: String latLongString = “Tracking info Latitude: 3.9574667 Longitude: 7.44882167″; //yours obviously won’t be hardcoded String[] split = latLongString.split(” “); String lat = split[3]; String lon = split[5]; [ad_2] solved Extracting two numbers from a string using java
[ad_1] “(\-)(.*)” is the pattern, which will give you 2 matches if the string contains them. [ad_2] solved Regular Expression to match first character and after a character [closed]
[ad_1] In your for loop, the variable result Is created outside of the for loops scope. Essentially, you are just changing the result variable that has already been created. If you attempted to create a new variable within the for loop such as “newResult = base * result”, it would fail if you attempted to … Read more
[ad_1] Either room is null, or room.getTile(x, y) returns null. You haven’t pasted the relevant bits of those, making it impossible to give more information. [ad_2] solved Unknown NullPointerException 10 ignore> [duplicate]