[Solved] Python3: Error with colon in if statement
You need to put one “)” the line before the if and also the last “else” is missing a “:” solved Python3: Error with colon in if statement
You need to put one “)” the line before the if and also the last “else” is missing a “:” solved Python3: Error with colon in if statement
after applying the proposed corrections to the code, and applying the axiom: only one statement per line and (at most) one variable declaration per statement. the following proposed code performs the desired functionality results: cleanly compiles properly checks for and handles errors the call to printf() format string ends with ‘\n’ so the data is … Read more
In my opinion, you forget to press “Enter” after entering input. A scanner can read the input if only you press the “Enter” key. Your solution seems correct to me. I was able to properly run it on my PC. You can find a similar question here: How to use Scanner to accept only valid … Read more
You compare an Integer with a String. That obviously can not work. Convert either Guess into int or i into String. solved I am doing a coin toss game program. But i am having an error in this portion [ (if Guess==i) {. How do I solve this? [duplicate]
You’re missing crucial break statements in your switch, e.g. switch(rank) { case 14: { if(suite == ‘H’) printf(“Your card is the Ace of Hearts!”); else if(suite == ‘C’) printf(“Your card is the Ace of Clubs!”); else if(suite == ‘D’) printf(“Your card is the Ace of Diamonds!”); else printf(“Your card is the Ace of Spades!”); } … Read more
Yes, enclose them in curly braces: if ( loan < 1000 ) { f = (loan * 100 / 1000); System.out.println( “The loan amount is $” + loan ); System.out.println( “The finance charge is $” + f ); System.out.println( “The total cost is $” + (loan + f) ); } solved multiple executed statements in … Read more
there will be no $locked here.It should be only locked a var type varriable. Which should be like this before the ajax block: var locked = “<?php echo $locked ?>”; solved Ajax if not working. How to it work?
Its still not entirely clear what behavior you want, but it seems you don’t understand what else does. An else (or else if) statement will only execute if the if/else if statements above it do not. With your code, this means that you will only ever execute the “A” block or the “B” block, never … Read more
If statement should be in any function or method… You can not write if statement directly into your class…. Your if statement does not contain any body… So, take it into any function or method to solve syntex error. 2 solved If statement creates syntax errors – android
Edit: This only addresses the second portion of the question. To disable a control try setting enabled to false. btnCheckAnswer.Enabled = false; 3 solved c# If else if statement event triggers before else if does
Consider the following Linked List: HEAD —> [“value2” | -]–> [“value3” | -]–> [“last_value” | null] Assuming current points to “value3”: HEAD —> [“value2” | -]–> [“value3” | -]–> [“last_value” | null] ↑ then current.next != null is true, since current.next is actually the “next” node. Now let’s assume current moved to “last_value”, now we’ll … Read more
I totally agree with the other answers and comments, but for convenience here is the code public class Program { public static void Main() { Console.WriteLine(“Who is the best?”); var answer = Console.ReadLine(); if (answer.Equals(“tim”)){ Console.WriteLine(“You’re right!”) } else { Console.WriteLine(“Wrong!”) } } } 1 solved C# How to have it read words and output … Read more
PHP’s round simply returns the rounded value, so you need to assign the number to itself: <?php $NumberToCheck = round($NumberToCheck, 0, PHP_ROUND_HALF_UP); ?> Manual: http://php.net/manual/en/function.round.php solved PHP if statement after a condition not working
Some pseudocode : Set salesA, salesB, salesC = 0 While choice != ‘Z’ Begin Initials = InputString Number = InputNumber If string[0] == ‘A’ Then salesA += Number Else If string[0] == ‘B’ Then salesB += Number Else If string[0] == ‘C’ Then salesC += Number End Print salesA, salesB and salesC 1 solved Setting … Read more
charAt is zero based. You should use ab.charAt(0) if you use only a single char. Another good advice is to start method names with a lower case and use the camelCase format. 3 solved if char equals a letter then execute a code