really just guessing here: <?php $i=23;//13,33,43,9999999993 if(substr($i,-1) == 3){ echo “there is 3”; } the code substr($i,-1) returns the last character of the string $i to cover 2 or 3 or 4 $i=24; if(in_array(substr($i,-1),array(2,3,4))){ echo “ends in 2 or 3 or 4”; } 0 solved How to choose range with php If condition [closed]
What you are missing is not checking the input value. First check the input value…: System.out.println(input); …and see if the value is ok. Then you can say if your “if-else” component is working or not. Also delete the gap @ input.equals (“Hola”). it must be input.equals(“Hola”) Addition: You cannot use == operator for Strings in … Read more
Use a branch-If-equal beq , something like this : beq $t0 $t1 if #here your else block j done if : #here your if block done: Here is a link to a MIPS instruction reference. solved C to MIPS How will i convert an if else statement [closed]
The expression (x[i] > y) is a boolean, which in this context is casted as an integer (0 or 1), but hardly ever reaches 3. So the branch will always be skipped. If your values x[i] and y are integers, just take the difference: if (x[i] – y == 3) {…} If those are floating … Read more
int input; while (true){ scanf(“%d”,&input); if (input>=1 && input<=10){ // process with your input then use break to end the while loop } else{ printf(“Wrong input! try Again.”); continue; } } 1 solved How to prompt the user to enter a integer within a certain amount of numbers
Here is a simplified version of what you have: action = “” if action == “stat”: # Not true, action == “” # stuff elif action == “list”: # Not true, action == “” # stuff elif action == “retr”: # Not true, action == “” # stuff else: # Looks like this is where … Read more
Come on… at least post some seemingly valid code… with an actual question. function changeImage(image) { var patharray = image.src.split(“https://stackoverflow.com/”); var name = patharray[patharray.length -1]; if (name == “FlyingHigh.png”) { … } } solved If any user with some free time can help me with my array loop [closed]
As the error says, you have int max declared twice. You need to change the second one to a variable assignment, not declaration: int max = i; for(int j = i+1; j < 1; j++) { if (wholeNumber[j] > wholeNumber[max]) { max = j; // NOT: int max = j; } } 0 solved Java: … Read more
As much as i understand it should be something like this System.out.println(“Write year between 1950-2050: “); int keyboard = input.nextInt(); int OL = (keyboard); int WC = (keyboard); int nothingspec = (keyboard); int instru = (keyboard); boolean blOL = false; boolean blWC = false; //this occurs whenever the number can be divided by 4 if(keyboard>=1950&&keyboard<=2050){ … Read more
In that case, I usually use any if not any((foo == ‘1’, bar == ‘2’, baz == ‘3’)): print ‘Invalid’ any returns True as soon as one of the conditions in the provided iterable is True. So it is like a list of or but is way easier to manage, especialy when you start having … Read more
Using your structure, we can do this: var links = new Array(); // Missing this part as code links[0] = new Array(); links[0][“linkName”] = “W3Schools”; links[0][“linkLogo”] = “http://www.w3schools.com/images/w3schools.png”; links[0][“linkURL”] = “http://www.w3schools.com/”; links[0][“linkDescription”] = “W3Schools is a web developer information website, with tutorials and references relating to web development topics such as HTML, CSS, JavaScript and … Read more
This should work for your purposes: name = input(“Please enter your name: “) name = name.lower() luckynumb = 0 firstnamenumb = 0 surnamenumb = 0 number = [1, 2, 3, 4, 5, 6, 7, 8, 9] row1 = [“a”, “b”, “c”, “d”, “e”, “f”, “g”, “h”, “i”] row2 = [“j”, “k”, “l”, “m”, “n”, “o”, … Read more
There is no performance difference since the generated code is exactly the same: $ echo “int main() { int number; if (number == 0) return -1; return 0; }” | g++ -x c++ -S – -o /dev/stdout | md5sum 9430c430d1f748cc920af36420d160ce – $ echo “int main() { int number; if (number == 0) return -1; else … Read more
try this: if (Catz.Checked) { // do whatever } If I understood you correctly and Catz is a CheckBox then the property you are looking for is probably Checked. This can be true or false In an if statement you can use the bool variable without a comparison operator like “==” to check for the … Read more
if (fileURL.pathExtension == “png”) { // image } else if (fileURL.pathExtension == “mp4”) { // video } 5 solved iOS Swift, how to do if statement for different file extension? [closed]