You can create a method getObjByKey to find in the provided arr array the object that contains key property and use Destructuring assignment the get the value Code: const getObjByKey = (key, arr) => arr.find((obj) => Object.entries(obj).find(([k, v]) => key === k)); Then you can do: const { data2 } = getObjByKey(‘data2’, date1); const { … Read more
Your function is declared to return char and you are returning an array of char. But even if you fix the return value which should be char * it’s still wrong because you should not return a local variable, instead pass the array as an argument to the function like this void n_zeroes(int n, char … Read more
To get the sum of the elements as your question states, you can use streams. int sum = history.stream() .filter(his->his.getRes().equals(“Vundet”)) .mapToInt(his->his.getWins()) // assuming this getter exists. .sum(); 2 solved Get the sum of elements of an ArrayList
here you go: public static void main(String… args) { String[] verifiedNames = { “barry”, “matty”, “olly”, “joey” }; System.out.println(“choose an option”); System.out.println(“Uselift(1)”); System.out.println(“see audit report(2)”); System.out.println(“Exit Lift(3)”); Scanner scanner = new Scanner(System.in); int choice = scanner.nextInt(); switch (choice) { case 1: scanner.nextLine(); // get ‘\n’ symbol from previous input int nameAttemptsLeft = 3; while (nameAttemptsLeft– … Read more
There are multiple things. One is that some of your code is unnecessary. public Dice(int dice1 /*, int a, int b, int c, int d, int e, int f*/ ){ this.dice1 = dice1; //this.a = a; //this.b = b; //this.c = c; //this.d = d; //this.e = e; //this.f = f; } You don’t need … Read more
<?php for ($i=5; $i < 1005; $i+=5) { ?> <option value = “<?php echo $i; ?>”><?php echo $i; ?></option> <?php } ?> $i+=5 <– This is the only change. How about this? 0 solved increament by 5 for loop in php
condition should be incrementing by 10: for (int x = 10; x <= 20; x=x+10) solved Unexpected behavior of a switch statement in a for loop [closed]
You can use System.out.printf: Let’s consider String str = “012345678901234567890123456789012345678”; add spaces before the string: System.out.printf(“%56s”, str); Output: ############################################################ # # # 012345678901234567890123456789012345678 # # # ############################################################ add spaces after the string: System.out.printf(“%-56s”, str); Output: ############################################################ # # # 012345678901234567890123456789012345678 # # # ############################################################ To be sure that the string is not too long, you … Read more
Here’s the answer, you should prompt for input, then check the input using a while loop instead of IF-ELSE to make sure the user provided the answer you desired. This is actually a simple logic question tho. You may explore do-while loop too. #include <iostream> using namespace std; int main() { string item; float price; … Read more
Here you are: #include <stdio.h> #include <string.h> int main( void ) { const char *s = “ABCDEFGHIJKLMNOPQRSTUVWXYZ”; const size_t N = strlen(s); while (1) { printf(“Enter a non-negative number (0 – exit): “); size_t n; if (scanf(“%zu”, &n) != 1 || n == 0) break; size_t k = 0; for (size_t i = 0; i … Read more
To start, we’ve seen no numbers, and the code assumest the biggest is 0 or larger: var biggest = 0; We’ll look at each number in the list: for(i=0; i < num.length; i++ ) { Is the current number bigger than the biggest we’ve seen? if( num[i] > biggest ) { If so, it’s the … Read more
Here’s a solution without loops. # some artificial data set.seed(1) daf <- data.frame(species = factor(paste0(“species”, c(rep(1:3, 10)))), year = rep(2000:2009, 3), x = sample(1:100, 30)) library(dplyr) library(broom) lm_fit <- daf %>% group_by(species) %>% do(fit = lm(x ~ year, .)) tidy(lm_fit, fit) # or as.data.frame(tidy(lm_fit, fit)) to get a data.frame # # A tibble: 6 x … Read more
Solution is simple: i = 0 total = 0 while i < len(my_list): total += my_list[i] average = total / len(my_list) i += 1 solved Using a while loop instead of a for loop in Python [closed]
If you set j = i then the minimum distance would be zero since you’d be computing the distance between a point with itself! If you set j = 0 the above would still apply, albeit with unnecessary duplicated comprisons, since you’d be including j == i. solved what happens when we change the value … Read more
By char *stdnames[100]; you got an array of (pointers to char). The NEXT BIG QUESTION is Who will allocate memory for each of these pointers? A small answer would be – You have to do it yourself like below : stdnames[count]=malloc(100*sizeof(char)); // You may replace 100 with desired size or stdnames[count]=malloc(100); // sizeof(char) is almost … Read more