You can use a for loop with integer variables, floating-point variables, even no variables at all. int i; for(i = 0; i < 10; i++) continue; float f; for(f = 0.0; f < 5; f += 0.5) continue; for(;;) break; But see What Every Computer Scientist Should Know About Float-Point Arithmetic for why you should … Read more
Your $digit variable is the maximum, use it that way. Change your for loop in this for ($x= 1; $x <= $digit; $x++) { echo ‘Hello ‘ . $x. ‘<br />’; } Then you will get what you want. solved Input numeric text for # loops [closed]
Your for loop is shorthand for the following code: int i = start; if (i <= end) { /* loop body */ i += step; } To answer your question, it will run ceiling((end – start + 1) / step) times. Walk through the logic on paper to see if you come to the same … Read more
The problem is in the condition if((i + j) > ((n / 2) + 1)) It should be if(j >= n – i – 1) // or if(i + j >= n – 1) To make this easier, I would create a helper function. Also, there’s no need for the VLA a[n][n] that you don’t … Read more
The values of your variables throughout the loops are like follows: x y result ———- 0 0 1 0 1 2 0 2 3 1 0 4 1 1 5 1 2 6 2 0 7 2 1 8 2 2 9 3 0 10 3 1 11 3 2 12 So that’s why result … Read more
This would be the equivalent in python. In range(0, height, cellSize), 0 and height are the bounds of the range, and cellSize is how many out counter increments. for y in range(0, height, cellSize): for x in range(0, width, cellSize): rect(x, 0, cellSize, cellSize) 5 solved Python single line for loops [duplicate]
You can create a separate method: for task in self.tasks: task = randomTask() … def randomTask(): while True: num1 = random.randint(0, 10) num2 = random.randint(0, 10) if num1 + num2 <= 10: break return “{} + {} =”.format(num1, num2) solved I can’t make this in to a for loop
Change: for (int i = 0; i > cars.Count; i++) To: for (int i = 0; i < cars.Count; i++) solved Searching for a String in a text file
yes, your for loops ARE being skipped, since the second part of the for statement is not the break condition but the condition that has to be fullfilled for the loop to run. So it is NOT for(a = 0; a == 15; a += 3) but for(a = 0; a <= 15; a += … Read more
Well the loop seems to be this one (at the end of the code): for i,j in itertools.combinations([a,b,c],2): all_diffs=alldiffs(i,j) total=count_total(i,j) zero=count_zero(all_diffs) total=np.array(total) union=map(sub,total,zero) zero=np.array(zero).tolist() union=np.array(union).tolist() union=[list(x) for x in union] sim=[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \ for (aa, bb) in itertools.izip(zero, union)] sim_comb=sum(sim,[]) sum_of_sim=sum(sim_comb) number_sum=len(sim_comb) ave=sum_of_sim/number_sum one_ave=1-ave print one_ave One possible … Read more
x and y are single floats, not arrays as indicated by the output of your print statement. plt.plot() tries to draw lines between points, but since there is only one point, there can be no line. I would assume you want to somehow make x and y into arrays of values perhaps something like this… … Read more
I’ve rewritten this so it is easier to understand, splitting out complicated code, and removing unused lines: def record_disp(info): #define a function that takes the input data, info a=[list(x) for x in info] #turn the input list into a list of lists lens=[] # make an empty list to store max lengths #loop with x … Read more
For a oneliner, you could use map from Array.prototype: secondArray = secondArray.map((element, index) => firstArray.includes(index) ? “blank” : element ) Please note the map function returns a new array, instead of modifying the original one. Edit: removed redundant return and curly-braces around the arrow function body 1 solved how to search for the value with … Read more
Instead of reading val1 and val2 directly from stdin, read a line of text. If the line does not start with |, extract the numbers from the line using sscanf or istringstream. If the line starts with |, break out of the while loop. #include <stdio.h> #include <iostream> using namespace std; const int LINE_SIZE = … Read more
Dont know what you mean there. But here is what I understand from your question <?php for ($i=0; $i< count($contentdinamit[“chart”][“songs”][“song”]); $i++ ) { if(($i+1)<=10){//limit your item by 10 echo'<li class=”up”><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”><strong>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“song_name”].'</strong></a><br /><a href=”‘ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'”>’ .$contentdinamit[“chart”][“songs”][“song”][“$i”][“artist_name”].'</a></li>’; } } ?> 6 solved How to limit items from for loop?