When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed] solved When I include brackets in a nested for loop, it doesn’t function correctly but when I take them out it does; why is this? [closed]
You can do it using syntax like the following: for (String s: cdSporNavn){ if(s.indexOf(“java”) != -1){ System.out.println(s); } } See Using Enhanced For-Loops with Your Classes for further information and examples. 0 solved enhanced for loop (java) [duplicate]
I think you need empty list so you can append the numbers to that i.e FirstNumbers = [1, 2, 3] SecondNumbers = [4, 5, 6] ThirdNumbers = [7, 8, 9] NestedNumbers = [FirstNumbers, SecondNumbers, ThirdNumbers] m = [] for i in range(0, 3): k = [] for each_number in NestedNumbers: k.append(each_number[i]) m.append(k) Output m : … Read more
You might want to use use zip functionality to print pairs of values. list1 = [“1”, “2”] list2 = [“3”, “4”] for pair in zip(list1, list2): print i This will print: (‘1’, ‘3’) (‘2’, ‘4’) Please notice that the lists should be at the same size. 2 solved Print a single string from and an … Read more
The for loop actually does loop, it just does do anything unless the answer is correct. you want: while enter!=”off”: if enter == “1”: prefer= input(“enter your preference”) if prefer ==”sports”: print(“Hardcore Sports Podcast”) enter = input(‘Enter 1 – recommendation, 2 – draw, off – exit’) else: print(“Kanye West’s new album”) enter = input(‘Enter 1 … Read more
The inner loop will perform all of its iterations for each iteration of the outer loop. This is a case where you can test the behaviour yourself fairly easily, and generally it is faster to try these kinds of things out than to ask the question on here and wait for an answer. For example, … Read more
No need to use variables $a and $b. Simply do this: for ($i = 1; $i <3 ; $i++){ $c = $i.$i; echo $c; } Update(1): Based on your edited question, the solution would be like this: for ($i = 2; $i < 6 ; $i++){ $j = (int)($i/2); $c = $j.$j; echo $c . … Read more
function myFunction() { var sum = 0; // should be initialized to 0 not “” for (var i = 0; i < 5; i++) { var mark = prompt(“Enter your mark: “); sum += Number(mark); // sum the marks (convert mark to number because prompt return a string) } var avg = sum / 5; … Read more
The first one. The reason is that it will loop when i is 1,2 and 3 and will stop when i is 4 as i<4 becomes false thus looping 3 times. The second one is not right as it will loop 4 times,namely when i is 0,1,2,3 and will stop when i is 4 as … Read more
This is an excellent interview question because any answer you give is likely to be wrong and more importantly be something you never previously thought seriously about. The whole point is to throw you off your game. They want to see how you react when you’re pushed into an area that you feel like you … Read more
Do you want something like this? const biscuitsPerCat = (cats, biscuits) => { const share = Math.floor(biscuits / cats.length) const cutoff = biscuits – cats.length * share return cats.reduce((res, cat, idx) => ({…res, [cat]: idx < cutoff ? share + 1 : share}), {}) } console.log(biscuitsPerCat([“Andy”, “Bandy”, “Candy”, “Dandy”], 14)) … which you could then … Read more
Ok JB Nizet gave me the answer, thank you a lot, it’s above my level, but it is working, so nice !. If u’re curious about my labo, it’s here : http://nicolash.org/football/#/liste have a nice day Solved the inverse problem with this : Is it possible to filter angular.js by containment in another array? And … Read more
Using for + range In python you can get a range by invoking range(begin, end) — where begin denotes the start of the range, and end is the upper limit (not included in the resulting range). Mathematically speaking the result will be the set of numbers in the range [begin, end). In order to port … Read more
A simple Array.prototype.reduce with Object.assign will do // objectMap reusable utility function objectMap(f,a) { return Object.keys(a).reduce(function(b,k) { return Object.assign(b, { [k]: f(a[k]) }) }, {}) } var arr = { “a”: “Some strings of text”, “b”: “to be encoded”, “c”: “& converted back to a json file”, “d”: “once they’re encoded” } var encodedValues = … Read more
As the error says, you have int max declared twice. You need to change the second one to a variable assignment, not declaration: int max = i; for(int j = i+1; j < 1; j++) { if (wholeNumber[j] > wholeNumber[max]) { max = j; // NOT: int max = j; } } 0 solved Java: … Read more