You have to escape the \ in Java, so replace all your \ with \ (mentioned by Hacketo) Regex is regex, they don’t get changed with respect to languages but yes, the way they are tested, changes..You just need to look into how to match a string with a regex in java. 3 solved Convert … Read more
I think you might be confused because it is showing scientific notation? ‘{}’.format() should help in that case. Xi = (70 + 1344736401384689745317259585614247891453883777111/315)% 115792089210356248762697446949407573529996955224135760342422259061068512044369 print(‘{0:f}’.format(Xi)) solved How to calculate this mathematical expression in python? [closed]
Yes, this works. For a list of all possible expressions see http://msdn.microsoft.com/en-us/library/system.data.datacolumn.expression.aspx Here also is a sample program demonstrating this works. using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Data; namespace ConsoleApplication2 { class Program { static void Main(string[] args) { DataTable table = new DataTable(); // Create the first column. DataColumn textColumn = … Read more
The language specification defines the syntax, and doesn’t care what you call the parts that make up the language. In abc->def, the first operand is abc, and -> is the operator and def is the second operand, but it is restricted to an identifier is the name of a member of the structure or union … Read more
As for me then this return 0*printf(“%d”,a[i]); just a bad programming style. At least it would be better to write instead return ( printf(“%d”,a[i]), 0 ); not saying about printf(“%d”,a[i]); return 0; Maybe this statement is found in a recursive function. As for your question Having trouble understanding output of line of code – then … Read more
482/10/5/2.0*2+14/5 48/5/2.0*2+14/5 9/2.0*2+14/5 4.5*2+14/5 9.0+14/5 9.0+2 11.0 Divisions go from left to right, addition comes last. An integer is only converted to double in an arithmetic operation with a double. That only happens three times: In step 3 (9/2.0), step 4 (4.5*2) and step 6 (9.0+2). All other operations are pure integer operations. 0 solved … Read more
It works like a foreach loop, so foreach (x in [1..3]) { foreach (y in [x .. x * 2]) { yield y; } } First x is 1, so y in [1 .. 2] Then x is 2, so y in [2 .. 4] Then x is 3, so y in [3 .. 6] … Read more
To begin with SDICA>31.04.2019END($> is not a valid date 🙂 April just has 30 days in a month. But to answer your question, you can use dateutil module, especially the parser.parse function for the problem at hand from dateutil import parser #Parse date from the string, fuzzy parameter can find hidden datetime string around a … Read more
A simple regex will do the job. preg_match(‘/\d{5}/’, $input) See also http://www.php.net/preg_match 2 solved check if 5 digit number is available in a string
All depend on the situation in hand. Both are valid but for multiple scenarios this one is quicker and much more efficient $a = $b == “” ? “default” : $b; solved Which is the most efficient way to work around the first one or the next one?
You could do a = !a && val1 if you dont mind switching between false and val1. This is based on the behaviour of && operator in javascript: if first operand is true && operator assigns the second operand, else it returns first operand. Please note: This does make your code more difficult to read. … Read more
You would need to use something like \d{5} which will match 5 digits. Depending on the language you are using you would then access whatever the group matched. For instance, in Java: String str =”AF1400006″; Pattern p = Pattern.compile(“\\d{5}”); Matcher m = p.matcher(str); if(m.find()) System.out.println(m.group()); Which yields the number you are after. An example of … Read more
I’m amazed this program works. There are sections of code that I don’t understand, for example: STARTB:for (i = 0; i < ns; i++) { if (numholder[i] == “(“) { temp_i = i; i2 = i; } if (numholder[i] == “)”) { temp_i = i – temp_i; } } The variables temp_i and i2 may … Read more
If you are talking about the “Execute SQL Task”, expressions are possible. Here what I usually do is to configure the type as “direct input” and then define the whole statement – including my parametrized values – as expression. If you rightclick the task, you can select properties and in the properties you open the … Read more
Assuming you’re trying to decrement…count by 1…you need one more minus sign, like this int i = 10; i–; to be a valid expression in C/C++. 1 solved Getting error in the c Program regarding expected ; before token [closed]