It is really simple: yourMap.mapValues(_.toMap) scala> :paste // Entering paste mode (ctrl-D to finish) Map( 0 -> Array((1,1), (2,1)), 1 -> Array((2,1), (3,1), (0,1)), 2 -> Array((4,1), (0,1), (1,1)), 3 -> Array((1,1)), 4 -> Array((5,1), (2,1)), 5 -> Array((4,1)) ) // Exiting paste mode, now interpreting. res0: scala.collection.immutable.Map[Int,Array[(Int, Int)]] = Map(0 -> Array((1,1), (2,1)), 5 … Read more
First, do you know about the csv module? If not, read the introduction and examples to the point where you know how to get an iterable of rows. Print each one out, and they’ll look something like this: [‘AVNIVGYSNAQGVDY’, ‘123431’, ‘27.0’, ‘Tetramer’] Or, if you use a DictReader: {‘Epitope’: ‘AVNIVGYSNAQGVDY’, ‘ID’: ‘123431’, ‘Frequency’: ‘27.0’, ‘Assay’: … Read more
import csv one_year_reserved = { ‘australia-central’: 0.0097, ‘usgov-virginia’: 0.00879, ‘us-south-central’: 0.00731, ‘france-south’: 0.01119, ‘us-west’: 0.00719, ‘europe-north’: 0.00822, ‘asia-pacific-east’: 0.0097, ‘japan-east’: 0.00799, ‘west-india’: 0.00833, ‘united-kingdom-west’: 0.00685, ‘usgov-arizona’: 0.00879, ‘brazil-south’: 0.00982, ‘australia-east’: 0.00776, ‘us-west-2’: 0.00605, ‘asia-pacific-southeast’: 0.00776, ‘south-india’: 0.01005, ‘us-central’: 0.00731, ‘us-east-2’: 0.00605, ‘south-africa-west’: 0.01016, ‘canada-central’: 0.00674, ‘south-africa-north’: 0.00811, ‘canada-east’: 0.00685, ‘us-east’: 0.00605, ‘korea-south’: 0.00639, ‘united-kingdom-south’: 0.00685, … Read more
This is the whole point of defaultdict: you construct one with a callable (in this case, int), and when a key is accessed that doesn’t exist, it will call it (producing 0), and insert it into the dictionary. It auto-creates keys as you access them. solved Python adding elements to dict and to defaultdict [closed]
You can flatten the internal dict and update it back to the original dict. Eg., product = d.pop(“product”)[0] flattened = {f”product.{key}”: value for key, value in product.items()} d.update(flattened) This should do the trick. 1 solved Flat a list of containing only one dict
What you are trying to do is impossible to do in any predictable way using regular dictionaries. As @PadraicCunningham and others have already pointed out in the comments, the order of dictionaries is arbitrary. If you still want to get your result, you must use ordered dictionaries from the start. >>> from collections import OrderedDict … Read more
You could use a comprehension(But you need to convert those numbers to string), Try code below: converted = {‘w’: 4, ‘a’: 3, ‘d’: 1, ‘e’: 1, ‘x’: 6} print(“”.join([str(char) for k, v in converted.items() for char in (k, v)])) solved Join Operation for Dictionary in Python [closed]
package main import “fmt” func main() { //create a map m := map[int64]int64{512: 8, 513: 9, 234: 9, 392: 0} //create a slice to hold required values s := make([][]int64, 0) //range over map `m` to append to slice `s` for k, v := range m { // append each element, with a new slice … Read more
I would do it like this: >>> fst = {‘A’: 5, ‘B’: 6, ‘C’: 8} >>> snd = {‘A’: 4, ‘B’: 9, ‘E’: 2} >>> out = {k: fst[k] + snd[k] for k in fst.keys() & snd.keys()} >>> out.update({k: fst[k] if k in fst else snd[k] for k in fst.keys() ^ snd.keys()}) >>> out {‘A’: … Read more
Assuming the keys (here, prompt) of both dictionaries are the same, or at least for every key in the answers dictionary, there is a matching response prompt, then you can count them like so count = 0 for prompt, response in responses.items(): if response == answers.get(prompt, None): count += 1 return count 1 solved Compare … Read more
Since the map key type is an array, the assignment: for k,_ := range ans { will rewrite k for every iteration. This will rewrite the contents of the array k. The slice k[:] points to k as the underlying array, so all the slices with k as their underlying array will be overwritten as … Read more
To give some example of what we mean, I think this is kind of alright import random import pickle class BaseCharacter: def __init__(self): self.gold = random.randint(25, 215) * 2.5 self.currentHealth = 100 self.maxHealth = 100 self.stamina = 10 self.resil = 2 self.armor = 20 self.strength = 15 self.agility = 10 self.criticalChance = 25 self.spellPower = … Read more
Actually the 1 is the error. The value 1 cannot serve as the valueMapper, whose type should be Function<? super T, ? extends U>. In your example the value mapper should be a function that accepts an element of your Stream (a String) and returns an Integer. The lambda expression s -> 1 will do. … Read more
Using LINQ is the best option here. If you want access your class in regular loop, it will be like this: foreach (KeyValuePair<string, MYCLASS> entry in MyDic) { // Value is in: entry.Value and key in: entry.Key foreach(string language in ((MYCLASS)entry.Value).Language) { //Do sth with next language… } } 1 solved How to get specific … Read more
You are looking for nested dictionaries. Implement the perl’s autovivification feature in Python (the detailed description is given here). Here is a MWE. #!/usr/bin/env python # -*- coding: utf-8 -*- import csv class AutoVivification(dict): “””Implementation of perl’s autovivification feature.””” def __getitem__(self, item): try: return dict.__getitem__(self, item) except KeyError: value = self[item] = type(self)() return value … Read more