date

[Solved] Days remaining before birthday in php [duplicate]

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Duplicate Date Difference in php on days? EDITED: $diff=$date-time();//time returns current time in seconds $days=floor($diff/(60*60*24));//seconds/minute*minutes/hour*hours/day) $hours=round(($diff-$days*60*60*24)/(60*60)); Is this how you wanted? $birthday = “1977-9-10″; $cur_day = date(‘Y-m-d’); $cur_time_arr = explode(‘-‘,$cur_day); $birthday_arr = explode(‘-‘,$birthday); $cur_year_b_day = $cur_time_arr[0].”-“.$birthday_arr[1].”-“.$birthday_arr[2]; if(strtotime($cur_year_b_day) < time()) { echo “Birthday already passed this year”; } else { $diff=strtotime($cur_year_b_day)-time();//time returns current time in seconds … Read more

[Solved] How to add date to MySQL table name? [closed]

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1st create archive database (vervanger_archive) . 2nd at original base if you dont have set DATE_ADD (adding timestamp for each row). 3rd SET 1 cron task once upon a day to move OLD rows from Original table to the archive table. Creating tables with timestamp names is bad choice.. 1 solved How to add date … Read more

[Solved] show remaining minutes instead of hours

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Barebones solution: long remainingMillis = countdownEnds.getTime() – System.currentTimeMillis(); long remainingMinutes = TimeUnit.MILLISECONDS.toMinutes(remainingMillis); String countdownEndsString = String.format(“%d minutes”, remainingMinutes); For a nicer solution use java.time, the modern Java date and time API, for the calculation of the minutes: long remainingMinutes = ChronoUnit.MINUTES.between( Instant.now(), DateTimeUtils.toInstant(countdownEnds)); In this case also see if you can get rid of the … Read more

[Solved] PHP regular expression matching date [duplicate]

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<?php $date=”2009/10/22″; if ( preg_match(‘/^(?:(19[0-9]{2}|20[0-9]{2}))\/(0[1-9]|1[012])\/(0[1-9]|[12][0-9]|3[01])$/’, $date ) ) { echo $date , ‘ is a valid date format.’; } else { echo $date , ‘ is not a valid date format!’; } ?> Also please make sure you use checkdate() function in addition to this. 1 solved PHP regular expression matching date [duplicate]

[Solved] android: how to display the month and years in words from the Calender Date in android? [closed]

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you can format it easily using java.text.SimpleDateFormat SimpleDateFormat sString s= “2013-1-18”; SimpleDateFormat sdf = new SimpleDateFormat(“EEEE,MMMM, dd “); System.out.println(sdf.format(new SimpleDateFormat(“yyyy-M-dd”).parse(s)));df Output: Friday,January, 18 solved android: how to display the month and years in words from the Calender Date in android? [closed]

[Solved] Giving wrong day of week in PHP

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You need to use date format “Y-m-d” to get the result you want. $date=”2017/06/07″ means June 07, 2017. If you want to get the day of July 06, 2017 then change $date=”2017/06/07″; To $date=”2017/07/06″; 0 solved Giving wrong day of week in PHP

[Solved] convert string time to date type in java

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With java.sql.Time you retrieve the right value from your time field in mysql. import java.io.IOException; import java.sql.Time; import java.text.ParseException; import java.text.SimpleDateFormat; import java.util.Date; public class teste { /** * @param args * @throws IOException */ public static void main(final String[] args) throws IOException { SimpleDateFormat sdf = new SimpleDateFormat(“HH:mm:ss”); try { Date data = sdf.parse(“21:00:00”); … Read more

[Solved] Show Date as dddd Mmmm d, yyyy SQL

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Use the following with DateName and convert functions : select DateName( month , q.dt )+’ ‘+convert(char,day(q.dt))+’, ‘+convert(char,year(q.dt)) from ( select convert(date,’20180802′) as dt ) q; SQL Fiddle Demo With respect to your last comment make your query as : select DateName( weekday , q.dt )+’ ‘+ DateName( month , q.dt )+’ ‘+ convert(char,day(q.dt))+’, ‘+convert(char,year(q.dt)) as … Read more

[Solved] php not converting dates

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This is because date_format accepts an object and not a string. You should use the function date and pass to it’s second argument a timestamp. solved php not converting dates

[Solved] new Date(2015,2,30) and new Date(‘2015-2-30’)

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The output will be console.log(new Date(2015,2,30)); // here 2 represents the march, ,month starts from 0 where 0 represents first month console.log(new Date(‘2015-3-30’)); Mon Mar 30 2015 00:00:00 GMT+0530 (India Standard Time) Mon Mar 30 2015 00:00:00 GMT+0530 (India Standard Time) new Date(‘2015-2-30’) // it means 30th day in February; which will convert it to … Read more