Because you are not initializing any thing in your constructor so it takes default value for all variable in you class. So you can change your constructor like : private String author; private String title; private int quantity; private double costPerBook; private String orderDate; private double weight; private char type; //R,O,F,U,N public BookOrder(String author, String … Read more
Introduction This article will discuss the issue of the BookOrder class not rendering results in Test. The BookOrder class is a class that is used to store and manage book orders. It is used to store information about the books that have been ordered, such as the title, author, and price. The class also has … Read more
You have to change the get_name() to return a non-const reference, like string& get_name(); to get it working/compile. But will look strange. What you can do instead is pass the member name directly iss >> employee.name; that’s what friends do. And don’t forget to return the stream is. 1 solved Operator Overloading Error: no match … Read more
Introduction Operator overloading is a powerful feature of C++ that allows you to redefine the behavior of operators for user-defined types. However, when using operator overloading, you may encounter errors such as “no match for ‘operator>>’”. This error occurs when the compiler cannot find a suitable definition for the overloaded operator. In this article, we … Read more
Would overriding func1 work? class Class(file1.Class2): def func1(self): print “Class3.func1” c = Class3() c.func2() Since func2 is not defined in Class3, Class2.func2 is called. However, in the body of that function, self is still an instance of Class3, so self.func1() calls Class3.func1, not Class1.func1. That is different from d = Class2() d.func2() where self in … Read more
It’s public: and not Public:. Because dd is part of A, you need an instance of A to access dd. 1 solved c++ access stuff out side the class [closed]
The compiler will translate a call to a member function into a call to a static function, with an implied this parameter pointing to the object. That means the contents of the object, valid or invalid, are not relevant to the whether the call is made. This changes if the method is virtual, since the … Read more
Your code already shows you making a new A() and a new B(). There is no AB(). By the nature of inheritance, a B is already an A; every B is also an A – just a more specific sub-type. A B = new AB(); says “declare B to be a new variable of type … Read more
From what little information you’ve given, I’d say you’re executing it the wrong way. Make sure you run the following two commands: javac HelloPrinter.java java HelloPrinter The first command compiles your source code into a .class file. The second command executes that class file. 2 solved Finding Main Class in “Hello World” program in Java … Read more
The first you have correctly identified is caused by access to a private member. The fix? A public member function which returns the menu: string getMenu(); The second is an invalid attempt to treat ‘mimmos’ as an array when infact it is a single instance. Since the comment above it indicates it is an attempt … Read more
This line of code isn’t closed: $this->query(“INSERT INTO testing_Rand (number1, // etc and you are missing a ; after this line: $newRand.=implode(‘,’, $varNum) If I get it, you meant to write this instead: public function insert_SQL($varNum ) { $this->query(“INSERT INTO testing_Rand (number1, number2, number3, number4, number5, number6, number7, number8, number9, number10) VALUES (“.implode(‘,’, $varNum).”)”); } … Read more
The code you are writing in the Offnen.cs file isn’t doing anything with the file because the variable “mp” is local to the object o (Offnen). Perhaps something like this is what you are looking for: MainWindow.xaml.cs #region Öffnen der Datei private void menuOffnen_Click(object sender, RoutedEventArgs e) { mp.Pause(); Offnen o = new Offnen(); o.OffnenDerDatei(mp); … Read more
Is there any way to compile this code such as inheritance, overload…? No. Not as you are trying to at least. mylist *y = new mylist(); //….how? isn’t valid since you have to provide a template parameter for mylist like mylist<MyType>. You’re probably looking for template specializations. 6 solved c++ use template class [closed]
To overload, you specify a method of the same type and name but with different parameters. for example: public int Foo(int bar) { return bar*2 } public int Foo(string bar) { return bar.Length*2; } Then when you reference the Foo method, you get 1 overload, the string parameter one. HOWEVER, The age part of your … Read more
We don’t have the full details on your string class, so this is hard to reproduce. However, when you call sensors[0] = sensor1; you are copying your Sensor, but haven’t defined an assignment operator (or copy constructor for that matter). You also do this in the Car constructor with (*(m_sensors + i)) = Sensor(*(sensors + … Read more