Why not do this: for(int i=0; i<selectedPlanet.size(); i++) { if(planet.isChecked()) { selectedPlanets.add(planet.getDisplayName()); } else { selectedPlanets.remove(planet.getDisplayName()); } } 6 solved add or remove a string from a list based on an if statement
It is a bit unclear what you ask: php can only handle data on the server side. If you do not want some specific attribute of a dataset you read / write to / from a database to be modified, then just don’t do it. No one forces you to consider data you get, for … Read more
To fetch the text you need this : $(“#data”).find(“input:checked”).next(“label”).text(); ^ ^ ^ ^———-| Where to look What to find Where to navigate What to get So basically, search in #data div for checked checkboxes and grab the text of the label next to them. Read : https://api.jquery.com/find/ https://api.jquery.com/next/ https://api.jquery.com/text/ $(function() { var prevText = $(“.success”).text(); … Read more
In general, all comments regarding names and ids in your code should be considered. Avoid special characters, ID must be unique, etc… The code below should work based on your existing one. Please look for best practices and examples. This is a relatively easy thing to accomplish, it’s just that it doesn’t seem that you … Read more
offer a simple solution to css DEMO HTML <input type=”checkbox” id=”checkbox-id” /> <label for=”checkbox-id”>Some label</label> CSS input[type=”checkbox”] { position: absolute; left: -9999px; } input[type=”checkbox”] + label { background: url(http://xandeadx.ru/examples/styling-checkbox/checkbox-sprite.gif) 0 0 no-repeat; padding-left: 20px; } input[type=”checkbox”]:checked + label { background-position: 0 -32px; } 2 solved How To Use Image As A CheckBox in html [duplicate]
You are fetching your CheckBox with findViewById(R.id.checkbox); when in the xml, the id is android:id=”@+id/checkBox” The id is case sensitive so check your capitalization. Basically your code is fetching a view by ID and not finding it. Therefore your cb object is set to null and you throw a nullpointer here cb.setOnCheckedChangeListener(this); 0 solved Android … Read more
No need to use any third party library for this :- Navigation bar 1.1 Use that arrow for back button by setting leftbarbuttonitem 1.2 For Progress Bar and progress label you can design separate view and can add it as title view (self.navigationController.navigationItem.titleView) For question and answer, you can use table view 2.1 Question:- Use … Read more
As per my understanding, You have 3 checkbox and each contains the array as a value. Now, on checkbox selection you want to print the selected checkbox array. If Yes, you can try this : new Vue({ el: ‘#app’, data: { checkboxes: [], boundingBoxes: [ { name: “bounding box”, color: “red” }, { name: “bounding … Read more
Try this… Public Class Form1 Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load DataGridView1.ColumnCount = 5 End Sub Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click DataGridView1.Columns(0).Name = TextBox1.Text End Sub Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click DataGridView1.Columns(1).Name = DateTimePicker1.Value.Date End … Read more
First off – don’t use the tag as it has been deprecated since 1999 use <p style=”font-weight:bold; color:green”>….</p> Instead of checkboxs use radio buttons <input type=”radio” name=”red” value=”red” onClick=”myFunction(this.value);”> Red<br> Repeat the above for all possible selections. Change your function myFunction() to myFunction( value ) and work from there. The information is passed directly … Read more
Your problem is the last for loop. Each row will get the state of the last checked[] array entry. You should see that if you change the value of the last one. PS: Your code is a bit “messy” and can be optimized: @Override public View getView(final int position, View convertView, ViewGroup parent) { View … Read more
$name = $_POST[‘name’]; $email_body =”; <?php $aDoor = $_POST[‘formDoor’]; if(empty($aDoor)) { $email_body = “You didn’t select any buildings.”; } else { $N = count($aDoor); $email_body .= “You selected $N door(s): “; for($i=0; $i < $N; $i++) { $email_body .= $aDoor[$i] . ” “; } } ?> 0 solved Multiple Checkboxes
The fix ended up being simple, and even logical, in hindsight. The controls are dynamically added to the form, like so: formCustCatMaint.Controls.Add(coName) And so, replacing this line, in the loop: For Each cntrl As Control In Me.Controls …with this: For Each cntrl As Control In formCustCatMaint.Controls And this line, in the GetLabelTextForID() function: For Each … Read more
Please add more code and explain your question. A general answer to this question: for (int i = 0; i < action.RecordsCount(); i++) { RetrievalRecord uiRecord = action.GetRecord(i); Action_v_Record dbRecord = uiRecord.DataRecord as Action_v_Record; CheckboxRetrievalCell missingcell = uiRecord.GetCell(action.missingAction) as CheckboxRetrievalCell; CheckboxRetrievalCell irrelevantCell = uiRecord.GetCell(action.irrelevantAction) as CheckboxRetrievalCell; int missingCellValue = missingcell.ToInteger; int irrelevantCellValue = irrelevantCell.ToInteger; dbRecord.Missing.NewValue … Read more
Instead of this in your html: onclick=”javascript:Mon_Select()” just do this: onclick=”Mon_Select()” The first one isn’t valid js code (only works in urls), the second one works. EDIT Also, remove your id attributes from your <labels> as sanjeev suggests Hope this helps, cheers 6 solved How to properly enable/disable input boxes when a specific checkbox is … Read more