You can use the LINQ All method. @if(!Model.PaymentList.All(f=>f.Status==”Paid”)) { <button>click me</button> } Or the Any method @if(Model.PaymentList.All(f=>f.Status!=”Paid”)) { <button>click me</button> } 1 solved Hiding button if all status is “Paid” using LINQ [closed]
Introduction This article will discuss how to use LINQ to hide a button if all the status values are “Paid”. LINQ is a powerful language-integrated query language that can be used to query and manipulate data in a variety of ways. We will look at how to use LINQ to check if all the status … Read more
The compact way: struct Node { int x; Node *next; } nodes[] = { {1, nodes + 1}, {2, nodes + 2}, {3, nodes + 3}, {4, nodes + 4}, {5, nodes + 5}, {6, nodes + 6}, {7, nodes + 7}, {8, nodes + 8}, {9, nullptr} }; Node* root = nodes; solved How … Read more
When reading from standard input, do not mix C library functions, such as fgets(), and C++ std::cin operators. The C library knows nothing about what the C++ library is doing. Change your code to use only stdin, or only std::cin, to read standard input. solved Why is this code not taking input for “Designation”?
Inside merge() the assignment of i,j,k i = 0; j = middle; k = 0; while (i!=n1 || j!=n2) { … should be changed to this i = 0; j = 0; k = p; while (i!=n1 && j!=n2) {… 1 solved Segmentation fault in merge sort program
Declare a variable to count the stars with an appropriate data type. Iterate (loop) over the string to check each character for equality with ‘*’. If this is the case then increment your star counter. Width and height are not required. If you want to constrain a larger field to the width and height provided, … Read more
As said in remarks scanf(“%s%c”,a[i],&ch); try to read a ‘word’ as a string in a[i] and a char in ch Because a ‘word’ is ended by a separator and there is no space between %s and %c if a character is read to set ch that character is the first separator Example : #include <stdio.h> … Read more
I would use regex… var name = Regex.Match(File.ReadAllText(filename), @”Member:[ \t\r\n]+(.+?)\r?\n”) .Groups[1].Value; 0 solved Read data from varying positions in a text file [closed]
You can use Regex.Matches(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; string[] phones = Regex .Matches(source, “[A-Za-z]+: \\+([0-9)( ])+”) .Cast<Match>() .Select(i => i.ToString()) .ToArray(); OR You can use IndexOf(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; var telephoneIndex = source.IndexOf(“Telephone”, StringComparison.InvariantCulture); var faxIndex … Read more
If i understood it right, you want to achieve the requirements by using the program you wrote above. It possible to re-design it using your own code. eg : For get() struct node *get(int key, void *data) { if(*head_ref != NULL) { key = *head_ref->data; return *head_ref; } else { printf(“Error in retrieving data from … Read more
I think there is a bit of a confusion here what the string concatenation does to your values. It is nothing less than simply using the default format for a parameterless ToString()! Each of your strings like Debug.Log(“currentTime: ” + currentTime); basically internally implicitly equal Debug.Log(“currentTime: ” + currentTime.ToString()); In that case the ToString() without … Read more
You add by using the += operator: for (i = 1; i <= n; i++) total += i; cout << total; Note this is short for total = total + i. 3 solved for-Loop to add integers [closed]
When you create a method which is named InternfaceName.MethodName it is called Explicit interface implementation. What it means is that that method is accessible only through a reference of the interface type. So… How can you call to that method from within the class? Cast this to the interface type! public void MyBalance() { Console.WriteLine(” … Read more
You’re asking about the wrong language. C does not support the dot operator on integers. To do this in C, you need to print it to a string like so. char numstr[10]; sprintf(numstr, “%X”, 255) 3 solved Convert dec to hex number in C [duplicate]
The C++ compiler can’t and won’t catch all the possible way you could write incorrect code. And while running, a C++ program will usually not throw an error the moment you access memory out of bounds. The language was not designed to protect the programmer from doing bad things. So when a program does something … Read more