Ok, continuing from the comment, and just as laid out in the comment, the first thing you need to do with any data handling problem is to read all of your data into a form that allows you to work with it as needed. Here you have varying types of data that all make up … Read more
I think result may vary depending on which processor and which language you’re using. This because float numbers (in general) are stored with a number of bits that try to represent that fractional number, but there can be some (very little) difference. So when you do (d1-d2) you probably get a number really close to … Read more
You do not need anywhere near that many entries (10^9 / 3). Note that you need only the values mod 10^6. You have a recurrence relationship among these: a[n] = a[n-1]^2 + 2 Each value depends only on the previous one, so there will be a simple sequence of numbers. The relation will have a … Read more
How are the pre and post increment / decrement operators are evaluated in C++ when they happen to occur repeatedly in a single cout statement? [duplicate] solved How are the pre and post increment / decrement operators are evaluated in C++ when they happen to occur repeatedly in a single cout statement? [duplicate]
You can use .Insert(): string test = “Hello”; test = test.Insert(4, “,”); You should check if the string is long enough though like so: if (test.Length > 4) { test = test.Insert(4, “,”); } 0 solved How do I add a comma after the fourth character in a sentence?
There are tons of errors here, from incorrect attempts to overload operators to using data members by the wrong name. I’ll step through what I see. When defining the binary operator+ as a member function it only takes one argument, which is the right-hand argument to + (the left-hand is implicitly *this). Also your operators … Read more
Let’s suppose you run with libjpeg. You’ll allocate a buffer and then call jpeg_read_scanlines a sufficient number of times to get all of your decompressed image data into memory. You can read scanlines (rows) individually and reformat them as needed. If the image is grayscale, the RGB values will all be equal, so you can … Read more
You need to write to your file using the file stream you have defined once you have taken your inputs and you can do that using fout as follows. Additionally, there are different modes in which you could open a file for writing to it, which you can go through here. fout.open(“FootballTeam.txt”); cout << “Enter … Read more
#include <stdio.h> #include <stdlib.h> #include <string.h> char *getfield(char **sp){ char *left; //point to < char *right;//point to > if((left = strchr(*sp, ‘<‘)) == NULL) return NULL; if((right = strchr(left, ‘>’)) == NULL) return NULL; size_t len = right – left;//if len == 1, tag is nothing(<>) char *tag = malloc(len); memcpy(tag, left + 1, len … Read more
This should get you started: var myUrl = “wmq://aster-C1.it.google.net@EO_B2:1427/QM.0021?queue=SOMEQueue?”; var myRegex = new Regex(@”wmq://(.*?)@(.*?)\?queue=(.*?)\?”); var myMatches = myRegex.Match(myUrl); Debug.Print(myMatches.Groups[1].Value); Debug.Print(myMatches.Groups[2].Value); Debug.Print(myMatches.Groups[3].Value); But you may need to change it a bit for variations in the url. There are proper tutorials on the web to explain Regex, but here is some quick info: @ before a string … Read more
Yes, it’s a common practise in any OOP based language to use only the definition of an object so that implementation details can be changed at a later time Let’s say you have the following interface public interface ISearchProvider { ISearchResult Search(ISearchRequest request); } If you now implement a property inside your windows forms, that … Read more
You have an infinite loop – it seems that you got confused about the logic of your inner and outer loop. It looks like you need to change: else { gpa[x] = 0.00; } // end of if/else } // end of inner while loop finalGpa[x] = (gpa[0] + gpa[1] + gpa[2] + gpa[3]) / … Read more
This an ancient DOS Protected Mode Interface system call to set a protected mode interrupt vector. See eg http://www.delorie.com/djgpp/doc/dpmi/api/310205.html. The compiler was probably DJGPP. Porting this to a different OS and/or runtime system will require a redesign from scratch to reimplement whatever functionality the interrupt handlers provided under DPMI. Good luck to you with that. … Read more
A fairly easy to use tutorial to print in c# can be found here. Also, 1/4th of A4 is A6 format. See image. solved how to take the print out in a paper having size 1/4 of actual a4 size paper [closed]
You need to have a reference to the other forms from the form that invokes the action. One way is to expose the ListView as a property on the Form itself and the just reference it via the Form From Form1 private void button4_Click(object sender, EventArgs e) { Form2Instance.MyListView.Items.RemoveAt(0); } In Form2 add the following … Read more