BODMAS rule is used to evaluate the expression . d*b = 18 “+” and “-” have same precedence . But “-” comes first in the left. SO 100 – 18 = 82 And then 82 + 8 = 90. solved Precedence of basic mathematical operators
Thus in a C++ program that is made up of value computations exclusively the evaluation order would entirely be dictated by operator precedence and associtivity. (2) No, the evaluation order of value computations is not entirely dictated by operator precedence and associativity. They impose only a partial ordering on evaluation. Consider a + b. In … Read more
I’m actually going to answer this question, even though it’s true that “the OP simply needs to compile the code and run it”, because it isn’t obvious to a beginner that this is one of the cases where that gives the right answer. People get dinged all the time on this site for asking why … Read more
Although those examples come from a different language, I think they are the same as operator precedence in C. In general, you’d be better off using a reference for the C language, such as the C standard, or a summary such as the one in Wikipedia. However, I don’t believe that is actually what you … Read more
a++ means that a is incremented after evaluation ++a means that a is incremented before evaluation a is incremented three times in total, so its value is 3 after the expression is computed. b= a++ + ++a * ++a; means that a is evaluated (0), then incremented, this (0) is added to the result of … Read more
The effect is as you write, but it’s achieved using a slightly different sequence: The post-increment has highest precedence, so it’s evaluated first. However, its return value (which is processed by further operators) is the value of iter before the increment. Dereference is evaluated next, returning pointer to which the non-incremented value of iter was … Read more
How are the pre and post increment / decrement operators are evaluated in C++ when they happen to occur repeatedly in a single cout statement? [duplicate] solved How are the pre and post increment / decrement operators are evaluated in C++ when they happen to occur repeatedly in a single cout statement? [duplicate]
Do this and please learn the usage of operators beforehand. if(a<=b && b<c) { //do stuff } solved C++ operator precedence a
As you can see here, the | operator has a higher precedence than the assignment operator =. Therefore, when you don’t wrap (a = false) in parentheses : if (a = false | (b = false) || (c = true) | (d = true)) is equivalent to if (a = (false | (b = false) … Read more