[ad_1] This code is completely wrong for what you are attempting. You are reading input as an integer instead of as a character. You are not initializing the vowel and consonant variables correctly, and not comparing var to them correctly. You are not checking for input errors. You are not handling upper-case letters. Try something … Read more
[ad_1] Official build of MinGW (that compiler Dev-C++ uses) has no support for standard library threads now. You can use boost::thread as a drop in replacement (API is similiar enough) or use Microsoft Visual C++, or try programming with g++ on Linux (this is what I have done recently, using a virtual machine). 1 [ad_2] … Read more
[ad_1] @Sourav Ghosh have already explained what was wrong with your code and also suggested one way to solve it. Here is another way. Instead of passing current and head as variables to be changed inside the function (i.e. as pointer-to-pointer), I would recommend that you use the function return value. In that way you … Read more
[ad_1] The most straightforward way: #include <iostream> int main() { //input string: std::string str = “w o r d 1\tw o r d2\tword3\tword4”; int wordStartPosition = 0;//The start of each word in the string for( int i = 0; i < 2; i++ )//looking for the third one (start counting from 0) wordStartPosition = str.find_first_of( … Read more
[ad_1] This is the non-lazy method of implementing the Singleton pattern for languages that support it. It’s perfectly acceptable to do this, especially since it’s one of the ways of implementing a thread-safe Singleton. However, if your Singleton object is expensive (see lazy initialization) to create, then it might not be appropriate to create it … Read more
[ad_1] You’re getting only numbers because there’s no specialization of std::to_string() for char. So when you do to_string(alphabet[random])), it converts the char to int (which returns the letter’s character code) and then converts that to a string. So to_string(‘a’) is “97”, not “a”. Instead of an array, you could use a string containing the alphabet. … Read more
[ad_1] #define P1(x) x+x #define P2(x) 2*P1(x) int a=P1(1)?1:0; int b=P2(a)&a; after code substitution it will look like this: int a=1+1?1:0; int b=2*a+a&a; Since 1+1 is not false, a will be 1, so: int b=2*1+1&1 for clearness, I will write it with parenthesis (see operator precedence): int b=((2*1)+1)&1 which is equivalent to: int b=3&1 which … Read more
[ad_1] You can’t do 2 sets of values like your trying to do with an INSERT statement. Your effectively doing: INSERT INTO Controller_Forecast(C1,C2…) VALUES(…loads of values…) VALUES(…Loads of more values…) This isn’t valid. To insert 2 sets of data, which is what it looks like you’re trying to do you can do 2 INSERT INTO … Read more
[ad_1] You are not using bubble sort. this is a selection sort algorithm and your code is not correct. I have updated the code for the bubble sort algorithm. #include <stdio.h> #include <stdlib.h> #include <time.h> int main() { int ctr, inner, outer, didSwap, temp; int nums[10]; time_t t; srand(time(&t)); for (ctr = 0; ctr < … Read more
[ad_1] Three problems: No header files. You need stdio.h for printf and fileno, and io.h for read and setmode (setmode is a Windows only function; on Linux, you would include unistd.h for read). This: int main(void); Is a function declaration, not a definition. Get rid of the ;: int main(void); Finally: while(read(STDIN_FILENO, &c, ‘) > … Read more
[ad_1] Do a single regex replacement: string input = @”Hello World XXX Goodbye XXX Rabbit!”; Regex rgx = new Regex(@”\s*\w+\s+(?:XXX|xxx)”); // or maybe [Xx]{3} string result = rgx.Replace(input, “”, 1); Console.WriteLine(result); Hello Goodbye XXX Rabbit! Demo This replacement only would target XXX for removal if it be preceded by a word (one character or more). … Read more
[ad_1] You don’t have a clear concept in object oriented programming. When you create two objects, then they are completely different from each other. They do not interact with each other until they are forced.So, myMum and myDaughter are seperate objects and they do not share the values of their variables. The last two outputs … Read more
[ad_1] You can make an array of your string value and pick the random value from array. // String array like in below format. string [] stringArray = new [] {“A”, “B”, “C”, “D”, “E”, “F”}; // Make it accordingly int ramdomNum = random.Next(0, stringArray.Length); Console.Write(stringArray[ramdomNum]); Hope this will help you. [ad_2] solved How can … Read more
[ad_1] It looks like you just need to change the logic slightly: When you find the start line, set your variable to true (and continue the loop). When you find the end line, set your variable to false (and continue the loop, or break the loop if you only expect to have one section to … Read more
[ad_1] The test (result != X_WON || result != O_WON || result != DRAW) is always true, since result can’t be equal to all 3 values. result should be initialised to UNFINISHED and the test changed to: (taken != 9 && result == UNFINISHED) 0 [ad_2] solved game does not allow you to win