[ad_1] You need to implement all the Network Calls in background Thread via AsyncTask. Here is a dummy template, you can modify it according to your needs: private class LongOperation extends AsyncTask<String, Void, String> { @Override protected String doInBackground(String… params) { //Send your HTTP REQUESTS HERE. return “”; } @Override protected void onPostExecute(String result) { … Read more
[ad_1] Your code compares adjacent elements x and y, but pushes x and y only if they are the first elements in the array (if z == 0; newarray.insert(0, x, y)). Otherwise, only y is pushed, so the first element of each group of consecutive integers is missing. This table illustrates what’s going on: x … Read more
[ad_1] First of all, sort the array then the i’th element will be minimum in all subsets that do not include the i-1 first elements, and include this element. There will be 2^(n-i) of those. In the same way, i will be the highest element in each subset that does not include any number after … Read more
[ad_1] What have you tried? Try this approach: Convert JSON to PHP array (json_decode()) Loop through the array, get the key and value for each entry (foreach(){}, array_keys()) Create a single string with an insert and add VALUES() for each row Execute the query after the loop $keys = array_keys($array); // get the value of … Read more
[ad_1] Here is my version where I filter on a range based on first value of the array and the coef variable, based on the result I slice away those elements already counted and filter again on the smaller array in a loop. This solution requires the input array to be sorted in ascending order … Read more
[ad_1] You can fill out two arrays with odd, even numbers like this var evenArray = new int[10]; var oddArray = new int[10]; for (int i = 0, even = 0; i < evenArray.Length; i++, even += 2) { evenArray[i] = even; } for (int i = 0, odd = 1; i < oddArray.Length; i++, … Read more
[ad_1] I think what you want is to sort the listbox items by putting them into an Array, but at the same time, you also have changed the listbox items into array of string and string cannot be sorted by descending/ascending as int does In that case, you should rather get your listbox items as … Read more
[ad_1] sizeof returns the size of the given type in number of chars, not the number of elements in the array (i.e. you have the wrong units). Therefore, ints+sizeof(ints) is incorrect, it should be ints + 5. 5 [ad_2] solved c++ fill call is creating an error [closed]
[ad_1] Use objects for the grouping. var categories = {}; function incrementBy(category, value) { if (!categories[category]) { categories[category] = 0; } categories[category] += value; } var datasetarr = []; var pos; for(var i = 0; i < arr.length; i++){ console.log(‘unsorted ‘ + arr[i].type + ‘ ‘ + arr[i].quantity); incrementBy(arr[i].type, arr[i].quantity) } for(var category in categories){ … Read more
[ad_1] The call to API.Tag.observeTagPool is asynchronous and it will finish after fetchTagPool() has returned the empty self.tagArr. You need to change fetchTagPool to return the value through a callback function like this: override func viewDidLoad() { super.viewDidLoad() // Note: This will print AA after viewDidLoad finishes // Use trailing closure syntax to pass the … Read more
[ad_1] This is how you would run a java program in a command line: java YourMainClass The command line arguments comes after that: java YourMainClass arg1 arg2 arg3 This would make the args string array contain “arg1”, “arg2” and “arg3”. If you make the args array an int[], how on earth is arg1 going to … Read more
[ad_1] for(int i = 0; ; i++) When does your loop end?!?!? Your second condition in for (the testing expression) is evaluated as true (at least as long as i<4). You need for(int i = 0; i < 4 ; i++) Otherwise it may break anytime after i>=4, but not before, since all components of … Read more
[ad_1] C++ does not have an associated length property for arrays. (See How do I find the length of an array?) You can do something like this: int length = sizeof(animals)/sizeof(animals[0]); Then, before accessing member variables of elements (like this: animals[i] -> hasFur(true);), you need to first create objects. animals[i] = new Animal(); // assuming … Read more
[ad_1] You don’t need to explicitly check against NULL for(i=0; i < 1000; i++) { if(!symbols[i]) // If pointer is NULL then increase the elements numberofelemets++; } 1 [ad_2] solved How to calculate the non-zero elements in the array? [closed]
[ad_1] Create two sections One for HomeArr and one for AutoArr. I believe for each section you wanna show a additional cell with some title. So below code should help you. extension ViewController : UITableViewDataSource { func numberOfSections(in tableView: UITableView) -> Int { return 2 } func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int … Read more