If you want to use recursive method why use loop in it…? I have write simple method which returns the reverse string using recursion. public string ReverseString(string s) { if (s == null || s.Length <= 1) // if length is less or equal 1 then also returns return s; return ReverseString(s.Substring(1)) + s[0]; } … Read more
Try this: List<String> actual = new ArrayList<>(); List<String> required = new ArrayList<>(); List<String> common = new ArrayList<>(actual); common.retainAll(required); System.out.println(” 100.0 * common / actual = ” + (actual.size() == 0 ? 0 : 100.0 * common.size() / actual.size())); System.out.println(” 100.0 * common / required = ” + (required.size() == 0 ? 0 : 100.0 * … Read more
initBoard doesn’t do anything. for(int y = 0; y < 0; y++) y starts at 0. 0 is not less than 0, so the loop does not run. Put the size of your board (8) in a constant, then use that everywhere, and you’ll be less likely to use the wrong number. 0 solved Why … Read more
IIUC, given array = [[[0,0,1,0],[0,0,0,1],[1,0,0,0],[0,1,0,0]], [[0,1,0],[1,0,0],[0,0,1],[0,0,1]], [[0],[1],[0],[1]], [[1],[1],[0],[1]]] Do import numpy as np >>> np.array(array).T array([[list([0, 0, 1, 0]), list([0, 1, 0]), list([0]), list([1])], [list([0, 0, 0, 1]), list([1, 0, 0]), list([1]), list([1])], [list([1, 0, 0, 0]), list([0, 0, 1]), list([0]), list([0])], [list([0, 1, 0, 0]), list([0, 0, 1]), list([1]), list([1])]], 2 solved Reshaping a … Read more
“blah” is a const char [5]. In the first line, that array is decayed into a pointer to be stored in your variable as a pointer to the first element. It is also a pointer to non-const characters that points to const characters. It should be: const char *sz1 = “blah”; In the second (thanks … Read more
I can guess, you forgot to initialize your m and n variables with proper values. Add m = 10; n = 5; before calling Difference and your code will work. I also suggest you to write more readable code: better naming for variables, use some spaces and avoid global variables. Edit: In C++ you can … Read more
Use Array.prototype.map instead, forEach gets no returns let newobj = [ { id: 22, reason: ‘reason 2’, phase: ‘phase 2’, reviewer: ‘by user 2’, date: ‘date 2’ }, { id: 21, reason: ‘reason 1’, phase: ‘phase 1’, reviewer: ‘by user 1’, date: ‘date 1’ } ]; let arr1 = { initiateLevel: true, parent: [ { … Read more
The command strcat(a[0],”\0″); is working on strings which are already terminated by \0. Otherwise it doesn’t know where to append the second string. In your case a[0] is not terminated, so the function will induce undefined behavior. You can do the following instead: a[0][n] = ‘\0’; (the same is for the rest of a elements) … Read more
In the loop below value is stored in fixarray only when element in array1 is not zero but its index gets incrementated even when element is zero. for (i = 0; i < linect; i++) { if (array1[i] > 0.5) { fixarray1[i] = array1[i]; fixarray2[i] = array2[i]; } } In this loop index of fixarray … Read more
You can do it using syntax like the following: for (String s: cdSporNavn){ if(s.indexOf(“java”) != -1){ System.out.println(s); } } See Using Enhanced For-Loops with Your Classes for further information and examples. 0 solved enhanced for loop (java) [duplicate]
If $monster is an array and mysql_real_escape_string as the name implies, takes a string, you must pass it a string. Since the function takes a $monster_name, perhaps you need to take that from the $monster array? Something like (without any idea of your code, just as an example, do not copy and paste 🙂 ): … Read more
Split the string into array: String x = “What is my name”; String[] splitted = x.split(” “); for (int i = 0; i < Array.getLength(splitted); i++) { System.out.println(“Word ” + (i+1) + “: ” + splitted[i]); } You can change System.out.println() to your desired output method. Edit (as suggested in comment): For safer code, change … Read more
var finalArr = []; userData.map(item => { userData1.map(item1 => { if (item.email === item1.email) { finalArr.push(Object.assign(item, item1)); } }) }) It’s not so difficult, you should think youself next time. 6 solved How to merge two array value matching by key value using Node.js/JavaScript
You might want to use use zip functionality to print pairs of values. list1 = [“1”, “2”] list2 = [“3”, “4”] for pair in zip(list1, list2): print i This will print: (‘1’, ‘3’) (‘2’, ‘4’) Please notice that the lists should be at the same size. 2 solved Print a single string from and an … Read more
You can use forEach to get all elements that fit the condition: const arr = [12,59,42,53,6]; const x = 24; const y = 4; arr.forEach(function(item, index){ if(item * y === x) { console.log(item, index); } }); solved Determine which element of an array will make IF statement return true Javascript [closed]