[Solved] Subtract two data sets where column names are same [closed]
Just write df1-df2[colnames(df1)] # a b c # 1 1 -3 1 # 2 2 -5 8 # 3 3 -6 -1 2 solved Subtract two data sets where column names are same [closed]
Just write df1-df2[colnames(df1)] # a b c # 1 1 -3 1 # 2 2 -5 8 # 3 3 -6 -1 2 solved Subtract two data sets where column names are same [closed]
The place of mysql_query isn`t correct. You must insert records in loop: foreach ($xml as $syn) { $w1 = $syn->w1; $w2 = $syn->w2; $sql = “INSERT INTO db_name (w1, w2) VALUES (‘$w1′,’$w2’)”; $query = mysql_query($sql); if (!$query) { echo (‘Error: ‘ . mysql_error()); } else { echo “Record added”; } } mysql_close($con); 3 solved Parse … Read more
It will print out 5. It doesn’t even approach to the second if-else, because doesn’t pass the first condition x!=5 and the else statement is missing and it goes to the last line where you print the variable out. It’s the same as: int x=5, y=5, z=5; if (x!=5) { if (y<=7) { z=z+4; } … Read more
Try removing ‘\n’ from the scanf, like this: scanf (“%i”,&x); Take a look at this discussion for additional info on using ‘\n’ in a scanf: Using “\n” in scanf() in C 2 solved C-Program – Taking extra entry to end program
your value at key[18] is “L” so if condition is always true and you will get an alert with value 7 1 solved Javascript for loop with if statement not reaching the else if statement [closed]
There would be no “empty space”, no null. This is the general contract for all lists (List<E>) in Java Collections API. solved Java LinkedList remove
There is no $dbh variable, so you can’t call prepare() on it. 2 solved Hi am new to hostgator cpanel.I get this database connection error when testing my website [closed]
http://api.jquery.com/html/ The html() function gets the html string. Then when you pass it in to $(), JQuery is creating html elements that are the same as your content and are not part of the DOM. Instead you should just use: $(‘#id’).prop(‘id’, ‘id’ + cnt); 0 solved Set a tr id in jQuery [closed]
Here’s one way: public static void main(String[] args) { String s = “abc,xyz,lmn,ijk”; char[] ch = s.toCharArray(); int counter = 0; int place = 2; for (int i = 0; i < ch.length-2; i++) { if(ch[i] == ‘,’) { counter++; } if(counter == place && ch[i] != ‘,’) { System.out.print(ch[i]); } } } It prints … Read more
The question is a bit too broad to answer it here. But Jonas Bonér, the creator of Akka, explores the relationship between Microservices and Reactive Systems in his free ebook “Reactive Microservices Architecture“, why don’t you read that for a start. Akka is a library/tookit, it’s more low-level and doesn’t guide you towards using certain … Read more
Invoke the program with parameters 10 11 5 and you’ll get to access_granted. But it may depend on how your compiler aligns variables data in memory. 1 solved What does this c code do and how to get to the access granted [closed]
strcmp & strncmp functions return 0 if strings are equal. You should do: if (strncmp(frase1, frase3, 4) == 0) … i.e.: char *str1 = “Example 1”; char *str2 = “Example 2”; char *str3 = “Some string”; char *str4 = “Example 1”; if (strncmp(str1, str2, 7) == 0) printf(“YES\n”); // “Example” <-> “Example” else printf(“NO\n”); if … Read more
<?php if(isset($_POST[‘action’]) && $_POST[‘action’]!=””) { if(isset($_POST[‘username’]) && $_POST[‘username’]!=””) { header(‘Location: some_other_page.php?username=”.$_POST[“username’]); exit; } } ?> <form action=’index.php’ method=’post’> <input name=”username” type=”text” value=”” placeholder=”Insert username here”> <input type=”submit” value=”Go” name=”Go”> <input type=”hidden” name=”action” value=”do_redirect”> </form> 1 solved Redirect to URL with variable inside php
When using if statements and you want to compare a result you should use == instead of =. With = you are assigning a value to a variable and == compares between to values. You can also not compare two things at the same time like: if (result = 70<=100) You need to check if … Read more