[Solved] refactoring/making the code better in javascript [closed]

Yes, you should use switch statement here. Chaining so many else if’s is considered bad practice. You can read about switch statement here. https://www.w3schools.com/js/js_switch.asp Code would look something like: function likes(names) { if(names.length<0) { return `${names} likes this`; //return early if possible } let answer=””; switch (names.length) { case 0: answer = `no one likes … Read more

[Solved] Need to delete if block in file using python

The issue you are hitting here is that .readlines() reads line separated by a newline escape character (\n) and treats them as separate entries in an array – so your data contains: data == [‘if (aaaaa == b) {\n’, ‘qqqq\n’, ‘cccc\n’, ‘vvv\n’, ‘}’] If something isn’t working, run it through a debugger or print it … Read more

[Solved] Get string line by line android programmatically

I think you can go for an approach like this. int clicks = 0; Button checkButton = (Button) findViewById(R.id.check_Button); checkButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { EditText editBox = (EditText) findViewById(R.id.edit_Text); String items = editBox.getText().toString(); if (i == 0) { Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show(); i++; editBox.setText(“”); } else if (i == 1) { Toast.makeText(getApplicationContext(), … Read more

[Solved] how to check the range using only if statement

if you want to check the difference between two numbers, you need to subtract them. The result may be negative if the first number is smaller than the second, so you may want to use Math.abs() which will make it positive again. Then you have a positive number that you can check for being between … Read more

[Solved] is there a way to have a “main” arraylist? [closed]

List<List<Citizen>> mainList= new ArrayList<>(); You can go with List of List. Also need to consider below points. I recommend using “List” instead of “ArrayList” on the left side when creating list objects. It’s better to pass around the interface “List” because then if later you need to change to using something like Vector (e.g. you … Read more

[Solved] Event when onblur input jquery

The solution I’ve found : $(“#address”).on(‘blur focus’, function() { if (this.value==”) { $(‘#button_submit’).css(‘display’, ‘none’); } }); http://jsfiddle.net/np1wkh9p/17/ solved Event when onblur input jquery

[Solved] Getting java.lang.ArrayIndexOutOfBoundsException, looked, cannot find an example thats the same

In your for loop, i correctly iterates from 0 to the maximum length. However you have code such as: tweetArray[i+1] … tweetArray[i+7] that will fail once i reaches (or gets close to) its maximum. That is, you are referencing past the end of the array. In general, if you need to check something about the … Read more