You need to insert ints in the list instead of strings, just modify: item = input(“Enter a number to add to the list: “) noNumbers.append(item) By: item = int(input(“Enter a number to add to the list: “)) noNumbers.append(item) 7 solved Python list not picking up min and max values correctly
Your activities are indeed classes. Look at the declarations! public class MainActivity extends Activity { ^^^^^ // see? it’s a class! And the class is in whatever package it says on the top of the file. e.g. package com.example.myapp; every new activity has it’s own XML I guess this is where you are most confused. … Read more
You just need backslash to escape: System.out.println(“\”” + s + “\” ” + GM); Output: “Juan” GOOD MORNING 1 solved how to separate string with special character in Java
You need to get the result by using substring method as below String total_points = potential_points.getText(); int startIndex=total_points.indexOf(“:”)+2; int endIndex=total_points.length(); String result=total_points.substring(startIndex,endIndex); int no=Integer.parseInt(result); Simplified the above code as below String result=total_points.substring(total_points.indexOf(“:”)+2,total_points.length()); int no=Integer.parseInt(result); 15 solved Extract a number from a string getting number format exception
Use a dictionary, not variables. If you have variable names, the way to get the variable contents is evil, and almost always there is a better way. In this case: server_connection_commands = { “AdminServer”: “putty.exe -ssh 1.1.1.1”, “Server1”: “putty.exe -ssh 2.2.2.2” } server = requests.get(‘http://example.com’).text subprocess.Popen(server_connection_commands[server]) 2 solved Python – var = var = var … Read more
You can easily group by name to get what you need. Below is a quite general function to group any array of objects to a Map, by specified property. Then simply make it an array and you’re done function group(arr, propertyToGroupBy) { return arr.reduce(function(a, b) { return a.set(b[propertyToGroupBy], (a.get(b[propertyToGroupBy]) || []).concat(b)); }, new Map); } … Read more
Maybe I’m not understanding correctly what setDays() is meant to do, but it seems like this is what you would want: void numDays::setDays(int d) //mutator function to store the amount of days { days = d; hours = days * 8; } solved Why are my calculations are off? 1 work day is supposed to … Read more
You may try this var count = 1; function myFunction() { if (count<10) { count++; } else { window.location = “your-target-page.html”; } }; <html> <body> <button onclick=”myFunction()”>Click me 10 times</button> </body> </html> 0 solved Action on clicking a button 10 times in a webpage [closed]
I eventually figured it out. As I kept saying, the problem was in how I was populating the array. Here’s an entire section of code using a for loop which correctly populates my pointer array: #include <iostream> #include <fstream> #include <string> #include <new> using namespace std; int main() { int * arraySize; arraySize = new … Read more
Using a regex would work like this: import re regex = r’\d-\d{4}-\d{4}-\d’ preg = re.compile(regex) s1 = ‘9-9715-0210-0’ s2 = ‘997-150-210-0’ m1 = preg.match(s1) m2 = preg.match(s2) if m1: print(‘String s1 is valid’) else: print(‘String s1 is invalid’) if m2: print(‘String s2 is valid’) else: print(‘String s2 is invalid’) You can try the code at … Read more
Looks like the hash in database is shorter than the actual one. Maybe you have a character limit on the database row. 3 solved PHP login with sha256 don`t works
Use YEAR and MONTH functions … WHERE YEAR(SaleDate) = 2015 AND MONTH(SaleDate) = 12 Don’t use BETWEEN because you must to express the dates as literals, and that will be a problem considering that your SaleDate column could come with the time part in the future… 1 solved SQL Server: How to do WHERE statement … Read more
You just want to group on-the-fly, which means passing an ad hoc variable to the grouper. In data.table, this would be done by using rep in by: library(data.table) set.seed(01394) DT <- data.table(VAR = rnorm(2520)) DT[ , mean(VAR), by = rep(1:18, each = 140)] # rep V1 # 1: 1 0.029683200 # 2: 2 0.150411987 # … Read more
You could use sorted. The following solution works, provided the value of ‘id’ starts with a single character followed by numbers. sorted(b, key=lambda x: int(x[‘id’][1:])) 1 solved How to sort a list by dict values in Python? [closed]
Sure you want html?? <table align=”center” width=”590″ height=”590″ > <tr> <td align=”center” height=”80″ colspan=”4″>central text</td> </tr> <tr> <td align=”center” height=”80″ colspan=”2″>col</td> <td align=”center” colspan=”2″>col</td> </tr> <tr> <td align=”center” height=”40″>t</td> <td align=”center” height=”40″>t</td> <td align=”center” height=”80″ rowspan=”2″>t</td> <td align=”center” rowspan=”2″>t</td> </tr> <tr> <td align=”center” height=”40″>t</td> <td align=”center” height=”40″>t</td> </tr> <tr> <td align=”center” height=”30″>t</td> <td align=”center” >t</td> … Read more