Yes, there is the split function, however before calling it on your string, you must get rid of the [ and ], or else instead of [‘1’, ‘2’, ‘3’, ‘4’], you will get [‘[1’, ‘2’, ‘3’, ‘4]’], so instead of s.split(), we do s[1:-1].split(), also this means your list is strings instead of ints (‘1’ … Read more
You can do: diceroll1() + diceroll2() since the compiler sees it as value that diceroll1() returns + value of diceroll2(); 0 solved How can I use the output of a rand function, simulating 2 die rolls?
You are calling whole logic in onchange, you got wrong double qoutes (not sure but may be causing issue). Also document.getElementByid should be document.getElementById (see I in capital for Id) You should write a separate Javascript function and call it on change event of input. So change below line <br><input list=”Service” name=”Service” value=”** Select **” … Read more
First off, a few things to note. First, compilers do not give Exceptions, they give compilation errors – what you are experiencing is at runtime, not compile-time. Second, fileIn.exists() != false is equivalent to fileIn.exists(), which is easier to read. The actual problem you’re receiving is because your condition is false – which implies in … Read more
Your key is invalid.. foreach ($myarray[“docs”] as $myarrays) { echo $myarrays[“property_imgurl”]; } Live preview 2 solved Can’t echo items from array
Unfortunately you may want to think about redoing your site using twitter bootstrap and not your original css. I also noticed that your css does not use any of the classes used in bootstrap which means that your html will need major changes in order to use bootstrap’s framework. So with that said you may … Read more
Because you are filling x[i] with each of the values of scores. You have one extra loop. Since the last value of the slice scores is 83, you are filling x one more time, with 83 for each slot. Simpler would be: for i, _ := range x { // fill up x array with … Read more
A neat way to do it is String s = “[1,2,3]” s=s.sbustring(1,s.length-1); List<Long> numLongs = new ArrayList<Long>(); for(String eachString: s.split(“,”)){ try { numLongs.add(Long.parseLong(eachString)) } catch (NumberFormatException e){ System.out.println(“failed to convert : “+s); } } 0 solved Converting a string into an List [closed]
Valgrind says that the illegal write is occurring at Address 0x6172676f72502074. If you look at that address as ASCII characters, it’s: argorP t, or converting from little endian: t Progra. This looks like part of one of your menu items, “9. Abort Program”. Maybe the bug is that menu_init() is writing past the end of … Read more
Your trying to access the value of age from a page( dos.php) but you posting it to (two.php) and your missing $_POST[‘age’]. one.php <HTML> <BODY> <FORM ACTION=”two.php” METHOD=”POST”> Age: <INPUT TYPE=”text” NAME=”age”> <INPUT TYPE=”submit” VALUE=”OK”> </FORM> </BODY> </HTML> two.php <HTML> <BODY> <?PHP $age = $_POST[‘age’]; print (“The age is: $age”); ?> </BODY> </HTML> 0 solved … Read more
If you want to prevent caching you could also just use the current timestamp instead of random number. The following code snippet finds every link on the page containing “pdf” and adds either ?r={timestamp} or &r={timestamp}. var timestamp = new Date().getTime(), links = document.querySelectorAll(“a[href*=pdf]”); for (var i = 0, l = links.length; i < l; … Read more
As @SeyyedParsaNeshaei says, there is another answer that gives a “marquee” type scrolling, however, if what you want (as you say) is one word at a time, consider the following little sketch, which will run in Playground. It basically sets up a timer that changes the text of a UILabel one word at a time. … Read more
You must using parseInt: function low(numbers){ var arr = numbers.split(” “) var highest = parseInt(numbers[0]); for(i = 0; i < arr.length; i++){ if(parseInt(arr[i]) > highest){ console.log(arr[i] +”>”+ highest) console.log(parseInt(arr[i]) > highest) highest = parseInt(arr[i]) } } alert(highest) return highest } low(“4 5 29 4 0 -214 542 -64 1 -3 3 4 63 -6”); 1 … Read more
Solution: I put all of the conditional statements inside of if (!allCorrect[i]) so it looks like this if (!allCorrect[i]) { if (int.TryParse(parameters[i], out INT)) { if (_command.ParameterTypes[i] == EVariableType.INT) { allCorrect[i] = true; } else { allCorrect[i] = false; } } } if (!allCorrect[i]) { if (float.TryParse(parameters[i], out FLOAT)) { if (_command.ParameterTypes[i] == EVariableType.FLOAT) { … Read more
This should work public bool CheckFile() { StreamReader sr = new StreamReader(File.Open(@”YourFilePath”, FileMode.Open)); string toCheck; using (sr) { toCheck = sr.ReadToEnd(); } return toCheck.Contains(“fileName”); } solved Search column name in csv file using c# [closed]