For the password validation: Use a do while loop. The condition to terminate would be if the counter reaches three or if the user gets it right. example int counter = 0; boolean passwordCorrect = false; do { Console.Write(“Please enter the password > “); passWord = Console.ReadLine(); //If the password is correct,then it will break … Read more
Inserting this line of code before .hide() fulfilled my requirement. if ($(this).parent().is(“:visible”)) { $(this).hide(); } else { $(this).show(); } solved search script in jquery
That is double’s precision. You could use cookies = Math.round( cookies * 100.0 ) / 100.0; solved Java doesn’t know how to multiply? What? [duplicate]
You have a 2D array. The usual way to traverse it, is be double for loop. The usual order will be this: 1st row – 1st column 1st row – 2nd column .. 1st row – last column 2nd row – 1st column … last row – last column Assume you are using the order … Read more
You could check with isset like if (isset($_GET[‘errormsg’]) && $_GET[‘errormsg’] == ‘no_appid’) { $_SESSION[‘errormsg’] = “There was a problem with your application. Please reenter all data.”; } look at php isset 4 solved How to fix Undefined Index warnings? [duplicate]
C# Code for Validation protected void btnSubmitForm_Click(object sender, EventArgs e) { if(txtSome.Text.Length==0) { label.Text = “your message for Required feild!”; } else if(txt2.Text.Length==0) { label.Text = “your message for Required feild!”; } else { //write code here to insert values in database. this block of code will be executed when your all text boxes will … Read more
The parentheses do not match in your predicate. And to compare with an array or set of values, it is much less error-prone to use the %@ expansion: NSArray *wantedIds = @[@1, @2]; NSPredicate *predicate = [NSPredicate predicateWithFormat:@”ANY programs.programId IN %@”, wantedIds]; 0 solved get all user who progam Id exit in a to many … Read more
You probably want this: u64 text[2] ; FILE *input = fopen(“myfile.data”, “r”) ; if (input == NULL) { printf (“Unable to open file\n”) ; return 1 ; } while (!feof(input)) { int charsread ; charsread = fread(text, 16, 1, input) ; // read at most 16 bytes into the text array // process your text … Read more
You should show some effort and try to solve it yourself (it’s good for learning if for no other reason), but anyway, this can be done in several ways. This is two: SELECT idt, nome, bool1 FROM path WHERE idt IN ( SELECT idt FROM path WHERE bool1 = ‘true’); SELECT path.idt, nome, bool1 FROM … Read more
If you want to split it by space try, val = val.split(“\\s”)[0]; Here the String is split by whitespace (\n, \r, \t, \f, and ” “) 0 solved Java String.split not work [closed]
When loading execute both operations together. updateChatAJAx(); updateChatAJAx1(); Then setInterval for both actions var flag=0; $(function(){ setInterval(function () { if(flag==0) { updateChatAJAx(); } else { updateChatAJAx1(); } }, 2000); }); Change the flag to choose operation. flag=0 -> updateChatAJAx(); and flag=1 -> updateChatAJAx1(); solved two set interval function in single PHP file is not working
(It probably would have been better if you asked about a specific part of performance you want to improve upon). Here’s a tip, use New Relic to ping your site and check that is still up and running: you will be alerted to any issues your Heroku app won’t go to sleep which will increase … Read more
If the code is a part of bbpress I think the following link could prove to be helpful. http://codex.bbpress.org/bbp_list_forums/ 0 solved syntax error, unexpected ‘false’ (T_STRING)? [closed]
Boostrap is released under the MIT license. Here is their license. …subject to the following conditions: The above copyright notice and this permission notice shall be included in all copies or substantial portions of the Software. I don’t think you need to reference it visibly, but you can’t strip the copyright information out of the … Read more
just add a event listener window.addEventListener(event_type, event_handler, capture) i.e.: window.addEventListener(“keypress”, myFunc, false) and you can use function myFunc(e) { alert(e.keyCode) } solved how do I connect keyboard keys to functions In a game [closed]