[Solved] Refresh table after seconds

You need to use $.ajax like $(function(){ function getdata(){ $.ajax({ url:’getdata.php’, success:function(response){ $(‘#dataTables-example tbody’).html(response); } }); } setInterval(function(){getdata()},5000); }); getdata.php <?php $req = mysqli_query($con, ‘select user_id, user_name from users’); while ($dnn = mysqli_fetch_array($req)) { echo “<tr> <td>” . $dnn[‘user_id’] . “</td> <td>” . $dnn[‘user_name’] . “</td> </tr>”; } ?> 6 solved Refresh table after seconds

[Solved] Java language – show number 1-100

Your logic to print is fine, all you need to do is to wrap the code into a for loop and excute it from 1 to 100, e.g.: for(int zmienna = 0 ; zmienna <= 100 ; zmienna++){ if (zmienna % 5 == 0 && zmienna % 3 == 0) System.out.println(“FizzBizz”); else if (zmienna % … Read more

[Solved] E/AndroidRuntime: FATAL EXCEPTION: main [dupli] [duplicate]

your instantiation must be inside a method check the following and under setContentView method TextView tvnum =null; Button btnMin=null; @Override protected void onCreate(Bundle savedInstanceState) //TODO solve runtime problem(E/AndroidRuntime: FATAL EXCEPTION: main) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); tvnum = (TextView) findViewById(R.id.TV_num);//creating object of TextView int id = 100;//id is first number of tv num btnMin = (Button) findViewById(R.id.btnMIN); … Read more

[Solved] Returning specific regions [closed]

You can group the results of regionprops into a vector and use it for indexing: rg = regionprops( L, ‘Area’ ); allArea = [rg(:).Area]; % grouping all area values into a single vecotr labels = find( allArea >= 300 & allArea < 500); % select relevant regions solved Returning specific regions [closed]

[Solved] garbage value in C array

In the function argument: char arr[9][5] In the loop: for (i = 0; i<5; i++) { for (j = 0; j<9;j++) { if (arr[i][j] == 1) You flipped the position of i and j. i should go from 0 to 9, j from 0 to 5. 0 solved garbage value in C array

[Solved] how to hide a tag? [closed]

This is the best I can do without knowing your code: HTML: <h4 id=”myH4″>Hello World</h4> Javascript: document.getElementById(“myH4″).style.display=”none”; or document.getElementById(“myH4″).style.visibility=”hidden”; 7 solved how to hide a tag? [closed]

[Solved] Restart Mysql by PHP [closed]

Yes, it is possible. How depends on which OS you’re running. One approach is the PHP exec function to execute a external program. The command to be executed depend on the OS, as I said. Here are the command (If I’m correct, please tell me if I’m not): Debian / Ubuntu: /etc/init.d/mysql restart Mac OS … Read more

[Solved] how to compare between rounded off long values and long values in ArrayList? [closed]

Here is an example of what you are trying to do. import java.util.ArrayList; import java.util.Arrays; public class Test{ public static void main(String[] args) { ArrayList<Integer> numberList = Arrays.asList(10234, 20233, 34546, 43546, 59865, 70002, 92435, 200354); for(int nbr : numberList){ //goes through the list if( nbr > 20000 && nbr < 50000){ System.out.println(nbr); } } } … Read more