Suppose there are n people attending this quiz, the # of the winner is x. So the sum of people entering before the winner is the sum of 1+…+(x-1), the sum of people entering after the winner is the sum of (x+1)+…+n. Here we have 1+…+(x-1) = (x+1)+…+n, which derives to (x*(x-1))/2 = ((x+n+1)*(n-x))/2. Simplifying … Read more
You can replace all duplicate underscores with single underscores, then replace all underscores with spaces: while (string.indexOf(‘__’) != -1) { string = string.replace(‘__’, ‘_’); } while (string.indexOf(‘_’) != -1) { string = string.replace(‘_’, ‘ ‘); } Another way would be to loop through the string and check for underscores and output a space for the … Read more
You can use for for looping through array elements: var url = [“aaa”, “bbb”, “ccc”] for (var i = 0; i < url.length; i++) { if (window.location.href.indexOf(url[i]) > -1) { $(“#wrap”).css({display: ‘block’}); $(“#nav”).css({display: ‘block’}); break; } } 1 solved Declaring variables jQuery
If I am understand You the right way, it must be something like this: Create a method like this: private void setDay(boolean dayIncrement){ Calendar cal = Calendar.getInstance(); //get an instance of Calenar int dayOfWeek = cal.get(Calendar.DAY_OF_WEEK); //get the current day switch (dayOfWeek) { //if it is monday…. case Calendar.MONDAY: text1.setText(“some text for MONDAY”); //if the … Read more
You can use preg_replace(). http://php.net/manual/en/function.preg-replace.php $str=”Hello <font size=”4″>today</font> is my <font size=”3″>special day</font> and am <font size=”11″>ready</font> for it…”; preg_replace(‘/<font size=”(\d+)”>(.+?)<\/font>/’, ‘<span style=”font-size:$1;”>$2</span>’, $str) Output: Hello <span style=”font-size:4;”>today</span> is my <span style=”font-size:3;”>special day</span> and am <span style=”font-size:11;”>ready</span> for it… 4 solved Replace with php each font size=”” to font-size: ; how to? [closed]
with your “warning” you also get a string number, where “warning” appears. please give the string where an error appears I did not see at first time your warnings just replace the -1 to NULL or replace -1 to (void *)-1 course standard should be written to NULL, but if you really want, you can … Read more
function main(arg1){ switch(arg1) { case ‘Jatin’: alert(‘This is Jatin’); break; case ‘Vivek’: alert(‘This is Vivek’); break; case ‘Vikas’: alert(‘This is Vikas’); break; default: alert(‘The name is not found’); } // no semi colon } // closing brace main(“Jatin”); 0 solved Switch Statement-JavaScript [closed]
@StevenRumbalski has given the right answer i.e., output = filter(lambda k: 5 <= dict1[k] <= 8, dict1) solved Use filter method and find the keys with values between 5 to 8 from the given dictionary
Header files normally only contains prototype declarations of methods, just to satisfy initial compiler checks. The implementation files are already compiled to binary forms and distributed as library files. They are linked to your program during the linking process. If you have studied C, you will remember that you used to add a prototype declaration … Read more
Since your linked site uses vimeo, I’ll direct you here: http://vimeo.com/api/docs/player-js A stop (pause) is as simple as: document.getElementById(‘myViddy’).pause(); //for <object>-style embed and document.getElementById(‘myIFrame’).postMethod({“method”: “pause”}); //for <iframe>-style embed solved create a stop with Jquery for viemo embedded video [duplicate]
You just need basic date arithmetic, and the plain old date type. CREATE TABLE doctor_visits ( doctor_id NUMBER NOT NULL, in_time DATE NOT NULL, out_time DATE NOT NULL ) / I presume you want to find doctors who were in the hospital at 10:00am, as opposed to doctors who visited exactly at 10AM SELECT doctor_id … Read more
v is a pointer, and it looks like VECTOR expects its argument to be a value. So change VECTOR(v) to VECTOR(*v). 1 solved error: request for member ‘stor_begin’ in ‘v’, which is of non-class type ‘igraph_vector_t*’
You can use public bool IsAlpha(string strToCheck) { Regex objAlphaPattern=new Regex(“[^a-zA-Z]”); return !objAlphaPattern.IsMatch(strToCheck); } Regards solved Validate input string [closed]
To get started with, FASTA is text file format. To write text files check MATLAB documentation of fopen, fprintf and fclose. To load the text from the data files you’ve written you can use fopen, fscanf and fclose. Actually, MATLAB has fastainfo, fastaread and fastawrite too. You should check MATLAB documentation of these commands and … Read more
in your xml file when defining your EditText, you add your inputType as Number android:inputType=”number” solved Opening the numpad of the device [duplicate]