[ad_1] In your switch statement, replace every return; with break; which is the signal to break out of the switch, but the rest of the code will run. When you write return within a void method, when its reached it means you are breaking out of the method itself so no code past it will … Read more
[ad_1] You can try something like this : input_st = “Field1:’abc’,Field2:’HH:MM:SS’,Field3:’d,b,c'” output_st = {item.split(“:”)[0]:”:”.join(item.split(“:”)[1:]).replace(“‘”, “”) for item in input_st.split(“‘,”)} outputs : {‘Field1’: ‘abc’, ‘Field2’: ‘HH:MM:SS’, ‘Field3’: ‘d,b,c’} Kind of ugly but it does the job. 4 [ad_2] solved Convert string to Ordered Dictionary [closed]
[ad_1] Your second program is malformed. It’s not using std::string::operator[] at all. string * ps = new string(str); ps[0] = ‘n’; Not only does std::string support the [] operator, every pointer to a type also supports the [] operator. It’s how C style arrays work, and it’s what you’re doing in the code above. ps … Read more
[ad_1] Demo https://jsfiddle.net/mg8zbr41/172/ (I hope this was the desired behaviour) Explanation The whole problem would have been solved if we were allowed to have overflow-x: auto and overflow-y: visible together. But we cannot do that (see this answer). So we use the following workaround. If you want to have want the red div to pop … Read more
[ad_1] The two main concept that you see in the last line are list comprehension and nested loops. Have a look. for understanding better what is going on, we’re going to split that line in simplier part: TENS for tens in “twenty thirty forty fifty sixty seventy eighty ninety”.split(): print(tens) OUTPUT: twenty thirty forty fifty … Read more
[ad_1] Rules for a.compareTo(b) returns negative value : a is before b returns 0 : a equal to b return positive value : a is after b Because the parameter are first, second and you compare like second.compareTo(first) you’ll get reverse order : (second+first) 344 first+ second 434 comparing : -1 >> 4 is before … Read more
[ad_1] var myArray = [ {productId: 116605, productserialno: “324234”}, {productId: 106290, productserialno: “12121”}, {productId: 106290, productserialno: “12121”}, {productId: 106293, productserialno: “4324343”} ]; var grouped = myArray.reduce(function (obj, product) { obj[product.productId] = obj[product.productId] || []; obj[product.productId].push(product.productserialno); return obj; }, {}); var groups = Object.keys(grouped).map(function (key) { return {product: key, productserialno: grouped[key]}; }); var pre = document.createElement(“pre”); … Read more
[ad_1] Attributes must be separated from the tag name by a space: <GroupwareSubscriptionactionCode=”04″> should be <GroupwareSubscription actionCode=”04″>. 8 [ad_2] solved System.Xml.XmlException: The ‘=’ character, hexadecimal value 0x3D, cannot be included in a name [closed]
[ad_1] Doable with formulas and and helper column: In column E (Helper): =IF(A2=A1,””,A2) In Column C (Output): =IF(E2=””,C1,CHAR(COUNTIF($E$2:E2,E2)+64)) 0 [ad_2] solved Repeating series of numbers-unique id needed
[ad_1] After going through the Pandas documentation, found the way to validate the data. Let’s just say you have a custom validation function. def validate_rating(rating): “””” Description: validate if hotel rating is a digit between 0 to 5 Args: rating (str): rating to be validated Returns: True if rating is valid False if rating is … Read more
[ad_1] Some corrections, plus a solution to what I think you are trying to achieve: Don’t use [class=interests] in the CSS, the dot is made for that: .interests ! Don’t use [id=all-contents] in the CSS, the # is made for that: #all-contents ! Don’t use spaces in class names ! professional interests → professional_interests, There … Read more
[ad_1] You could also use media queries. On screens smaller than 600px width the image will be width 100%. On screens larger than 600px width the image width is auto meaning the size of the image. You might want to tweak that 600px for your project. .container { position: relative; margin-top: 10px; } img { … Read more
[ad_1] x << 1 is analogous to operations like x * 2. If you don’t store the result anywhere, it is just discarded and the line may just get omitted entirely by an optimizing compiler. If you want to store the result of an operation like that back into x, you have options like: x … Read more
[ad_1] As i said problem is in scanning N and M variables. Change scanf(“%d %d”,&N,&N); to scanf(“%d”,&N); scanf(“%d”,&M); and you are fine. Problem was you were reading N twice while didnt read an M which was used uninitialized. Non-static variables (local variables) are indeterminate. Reading them prior to assigning a value results in undefined behavior. … Read more
[ad_1] You could just iterate until 5 instead of 6 and print your message out of the loop: for counter in range(5): # Remove the if statement: # if counter == 5: # print(“”) # break myCar.accelerate() time.sleep(1) print(“Maximum speed reached!”) 1 [ad_2] solved Break out of Python for loop